Need a sql query to get multiple dates in rows

Hi All,
i need a query to get dates for last 7 days and each dates should be in one row...
but select sysdate from dual..gives one row...
Expexcted Output
Dates:
01-oct-2013
30-sep-2013
29-sep-2013
28-sep-2013
27-sep-2013
26-sep-2013

Hi,
Do you mean that you want all 7 dates together on 1 row?
Here's one way:
SELECT LISTAGG ( TO_CHAR ( SYSDATE + 1 - LEVEL
                          , 'DD-Mon-YYYY'
                ) WITHIN GROUP (ORDER BY LEVEL)    AS txt
FROM    dual
CONNECT BY LEVEL <= 7
This is an example of String Aggregation, that is, taking a column on multiple rows, and concatenating all the values (however many htere happen to be) into 1 big string column 1 row.
Like everything else, exactly how to do it depends on your Oracle version.
For more on String Aggregation, including differetn techniques for different versions, see http://www.oracle-base.com/articles/10g/StringAggregationTechniques.php
Message was edited by: FrankKulash
Sorry, I mis-read the question.

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Sql query to get Thursday (Date) for the year 2014

Hello All,
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Hi,
Check if this can help you
DECLARE @counter INT
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BEGIN
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Regards
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I want to write a sql query that shows union f all the [Type] for each [Key] if [Key] has atleast one [Type] in common and for non matched [Key]s it will return the row as it is.
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insert into @categories ([Key], [Type]) values (5, 'F')
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1 A
1 B
1 C
1 E
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2 B
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6 F
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The data element names are wrong. KEY is a reserved word; “Categories" and "type" are called attribute properties in ISO-11179 rules. Matthias Kläy is right; this is a graph problem in disguise, but you can do it with set theory to get what are called
equivalence classes.
An edge in a graph has two nodes. Some authors allow a single node to count as a edge, but a better way is to put the same node on both ends of the edge. Here is the graph in a table with all the needed constraints. This is why you should post DDL and not be
so rude.
DROP TABLE Graph;
CREATE TABLE Graph
(edge INTEGER NOT NULL,
node_1 CHAR(1) NOT NULL,
node_2 CHAR(1) NOT NULL,
CHECK (node_1 <= node_2),
PRIMARY KEY (node_1, node_2));
Here is your data in the correct format.
INSERT INTO Graph
VALUES
(1, 'A', 'B'),
(2, 'B', 'C'),
(3, 'D', 'D'), -- orphan node
(4, 'A', 'E'),
(5, 'F', 'G'),
(6, 'G', 'H');
Now Google Warshall's Algorithm. It uses three nested loops and an adjacency array. This is very clean and fast in a procedural language. Not so much in SQL. Let us do this in steps:
WITH X1 (edge, node1_1, node1_2, node2_1, node2_2 )
AS
(SELECT CASE WHEN G1.edge <> G2.edge
THEN G1.edge ELSE G2.edge END,
G1.node_1, G1.node_2,
G2.node_1, G2.node_2
FROM Graph AS G1, Graph AS G2
WHERE G1.node_1 IN (G2.node_1, G2.node_2)
AND G1.edge <> G2.edge),
X2 (edge, node_1, node_2)
AS
(SELECT edge,
CASE WHEN node1_1 IN (node2_1, node2_2) THEN node1_2 ELSE node1_1 END,
CASE WHEN node2_1 IN (node1_1, node1_2) THEN node2_2 ELSE node2_1 END
FROM X1)
SELECT DISTINCT edge,
CASE WHEN node_1 < node_2 THEN node_1 ELSE node_2 END,
CASE WHEN node_2 < node_1 THEN node_1 ELSE node_2 END
FROM X2;
The X1 subquery gets the paths of length two. The X2 subquery removes the middle node and creates a new sorted edge. Insert these new rows into Graphs, if they are not there. Repeat the process until no more rows are added.
DROP TABLE Graph;
CREATE TABLE Graph
(edge INTEGER NOT NULL,
node_1 CHAR(1) NOT NULL,
node_2 CHAR(1) NOT NULL,
CHECK (node_1 <= node_2),
PRIMARY KEY (node_1, node_2));
INSERT INTO Graph
VALUES
(1, 'A', 'B'),
(2, 'B', 'C'),
(3, 'D', 'D'), -- orphan node
(4, 'A', 'E'),
(5, 'F', 'G'),
(6, 'G', 'H');
Here is the monster rolled up into a single statement.
INSERT INTO Graph
SELECT DISTINCT edge,
CASE WHEN node_1 < node_2 THEN node_1 ELSE node_2 END,
CASE WHEN node_2 < node_1 THEN node_1 ELSE node_2 END
FROM (SELECT edge,
CASE WHEN node1_1 IN (node2_1, node2_2) THEN node1_2 ELSE node1_1 END,
CASE WHEN node2_1 IN (node1_1, node1_2) THEN node2_2 ELSE node2_1 END
FROM
(SELECT CASE WHEN G1.edge < G2.edge
THEN G1.edge ELSE G2.edge END,
G1.node_1, G1.node_2,
G2.node_1, G2.node_2
FROM Graph AS G1, Graph AS G2
WHERE G1.node_1 IN (G2.node_1, G2.node_2)
AND G1.edge <> G2.edge) AS X1(edge,node1_1, node1_2, node2_1, node2_2) )
AS X2(edge, node_1, node_2)
EXCEPT
SELECT * FROM Graph;
SELECT * FROM Graph ORDER BY edge, node_1, node_2;
1 A B
1 A C
1 B E
1 C E
2 B C
3 D D
4 A E
5 F G
5 F H
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--CELKO-- Books in Celko Series for Morgan-Kaufmann Publishing: Analytics and OLAP in SQL / Data and Databases: Concepts in Practice Data / Measurements and Standards in SQL SQL for Smarties / SQL Programming Style / SQL Puzzles and Answers / Thinking
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SQL Query from getting multiple itemName against one production No.

Hello Everyone !!!!!!
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Similarly i have developed single interface for now i have 1 problem ,
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Select Distinct B.* from OWOR
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Could anybody help me out to update my Query according to my Client request ...
Please ..............
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Edited by: Rizzikhan on Oct 13, 2010 9:31 AM

Hello Everyone !!!!!!
My Client required an interface which can combine the production cycle. In which single Interface shows all the Production cycle like Bills of material, Production Order, Issue from Production and received from Production.
Similarly i have developed single interface for now i have 1 problem ,
when i show all the the production order number in a matrix i got Prodcution order number, DocNo,and Status .
as u know in one production order against multiple items, Similarly in multiple items there have been multiple ItemNames , I need multiple ItemName .
For this i have developed a Query but unfortunately my query doesn't show all the ItemName.
Select Distinct B.* from OWOR
Inner Join WOR1 B ON OWOR.DocEntry = B.DocEntry
Inner Join OITM C On OWOR.ItemCode = C.itemCode
Where OWOR.ItemCode = '16.0LF2060WGD'
And OWOR.Status = 'R'
AND DocNum = 708680
Here 16.0LF2060WGD= Production order Number
R = Status of that production Order number which is in the Release Mode
Please make sure that in one Production order against multiple itemcode nad multiple ItemName exist and Production order also Exist in the OITM table ........Please help me out
Could anybody help me out to update my Query according to my Client request ...
Please ..............
Thanx
Edited by: Rizzikhan on Oct 13, 2010 9:31 AM

Need a sql query to get the difference between two timestamp in the format of hh:mm:ss.msec

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Hi,
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DECLARE @endTime DATETIME
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SET @endTime = '2013-11-10 01:22:30'
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' Days ' +
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CASE WHEN DATEPART(SECOND, @endTime) >= DATEPART(SECOND, @startTime)
THEN CAST((DATEDIFF(MINUTE, @startTime, @endTime) % 60) AS VARCHAR)
ELSE
CAST((DATEDIFF(MINUTE, DATEADD(MINUTE, -1, @endTime), @endTime) % 60)
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END +
' Minutes ' +
CAST((DATEDIFF(SECOND, @startTime, @endTime) % 60) AS VARCHAR) +
' Seconds '
Reference:
http://sqlandme.com/2013/12/23/sql-server-calculating-elapsed-time-from-datetime/
- Vishal
SqlAndMe.com

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SQL> ed
Wrote file afiedt.buf
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Best Regards,Uri Dimant SQL Server MVP,
http://sqlblog.com/blogs/uri_dimant/
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SS

You can compare stuff in the EL, but I don't think this is what you need.
You can just use Java code in the backing bean class for all the business logic. You can use DAO classes for database access logic. Finally for displaying you can use the JSF tags such as h:outputText.

Need a sql query to get multiple dates in rows

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