Need COTS Analog Speed Signal from Encoder

Hello everyone, need some shopping help.
I have a customer who wants to get a scaled analog output corresponding to rotational speed from an encoder instead of doing traditional freq measurements. We want a stand alone package that does the frequency measurement on board and just puts out a scaled analog output.
Need < 100 mS latency and ability to resolve 5 rpm to 1000 rpm. Just don't know where to go to buy one.
Anyone know of such a device?
Thanks
Wes Ramm
Wes Ramm, Cyth UK
CLD, CPLI
Solved!
Go to Solution.

One example of many manufacturers of frequency to voltage converters:
http://www.dataforth.com/functional.view.aspx?ptypeid=11
Look at the detailed specs to make sure the unit's input voltage range is compatible with the encoder along with the response time.
-AK2DM
~~~~~~~~~~~~~~~~~~~~~~~~~~
"It’s the questions that drive us.”
~~~~~~~~~~~~~~~~~~~~~~~~~~

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Incremental Encoder Example.pdf ‏94 KB

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Message Edited by Jochen on 09-24-2008 09:24 AM

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Go to Solution.

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Is it possible to use "Delay Values" to create a frequency signal from digital "Count Edges" -task? (= are the results I'm getting correct?)

Hello.
I have a digital encoder from which I need freaquency information (to ultimately get rpm -infromation). The problem is that this task is inside a loop with 2 other DAQmx -tasks that are using "one sample on demand"-aquisition mode and if I configure this new counter task to be a freaquency task, it only updates once in ~ second which makes the whole loop lag.
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This explanation was probably quite confusing so please see the picture attached.
Thanks a lot in advance!
Attachments:
are_the_results_correct.jpg ‏200 KB

First of all, thank you for quick reply. Unfortunately I don't have the acces to the vi. until tomorrow.
And yes, I think you understood correctly: essentially this arragement measures how many edges have been counted during one iteration. This is how I figured out that this could then be used as a frequency measurement:
1. From the "Edges - Delayed Edges" I get the information on how many edges have been counted during last iteration.
2. I "know" (really I don't?) that one iteration lasts ~0,01s because of the delay in the loop.
3. There is 2048 edges in one round of the encoder so I get the rpm as follows: rpm = (edges - delayed edges)/204,8*60(s)
(If I was using history size of one as you suggested it would be: rpm = (edges-delayed edges)/2048 * 60) However using history size of 10 and taking it account in the multiplication smoothens the response nicely.
But doesn't this arragement count on the fact that the vi runs smoothly and there is no additional lag?
I quess using another loop and notifiers for a dedicated freaquency measurement as you suggested could be worth trying. I just have to first learn how to use them.
If I do use them will the main loop run smoothly and not wait for every update of the notifier? This would be essential since the freaquency output refresses only about once in a second if I use the continious aquisition mode.
Attachments:
are_the_results_correct.jpg ‏198 KB

Need COTS Analog Speed Signal from Encoder

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