Need date difference in Minutes

Hi,
I want to get the difference of date in minute.
Please help me out.
format is mentioned below in the query
select (to_date('9/19/2007 8:02:33 PM', 'MM/DD/RRRR HH12:MI:SS AM')
- to_date('9/19/2007 7:02:02 PM', 'MM/DD/RRRR HH12:MI:SS AM'))
from dual
Regards
Amit

This?:
SQL> with date_diff as
     (select to_timestamp ('9/19/2007 8:02:33 PM',
                           'MM/DD/RRRR HH12:MI:SS AM'
             - to_date ('9/19/2007 7:02:02 PM', 'MM/DD/RRRR HH12:MI:SS AM')
                                                                           dt
        from dual)
select extract (day from dt) * 24 * 60
     + extract (hour from dt) * 60
     + extract (minute from dt)
     + extract (second from dt) / 60 min
from date_diff
       MIN
60.5166667

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Date difference in minutes

Is there any function module which can give difference between dates with associated time in minutes ?
Eg. Difference between
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hi , use this function module,
L_TO_TIME_DIFF
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I_START_DATE                    10/12/2006
I_START_TIME                    12:00:00
I_END_DATE                      10/12/2006
I_END_TIME                      12:00:30
I_TIME_UOM                      MIN
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E_TIME_DIFF                                 0.500
2...
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I_START_DATE                    10/12/2006
I_START_TIME                    12:00:00
I_END_DATE                      10/18/2006
I_END_TIME                      12:00:30
I_TIME_UOM                      MIN
Export parameters               Value
E_TIME_DIFF                             8,640.500
hope this helps ,
regards,
vijay

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Hi
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Thanks

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I hope I am putting this in the right section. This is my first post. Thank you all ahead of time for your help.
I am new to both SQL and Report Builder so please bear with me and thank you ahead of time.
I need to find the time difference (in minutes) between Time 1 and Time 2. I've figured out the basics in how to do this but I need the logic to work in ONE DIRECTION. Meaning I need the statement to find the difference STARTING FROM TIME 1 and then ENDING
WITH TIME 2. I need the statement to always assume that Time 1 is FIRST and that Time 2 is LAST.
Here's an example of my results now with a basic DateDiff statement.
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9478 9zgyc24gzsgpz 2290340548
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Hi,
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Regards,
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I am trying to implement one scenario where in i need to compare the date differences for consecutive rows and generate a sequence against that.
this is the table schema:
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id int identity(1,1),
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time datetime
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(1, '2011-02-20 12:32:34.172'),
(1, '2011-02-20 12:32:34.172'),
(1, '2011-02-20 12:43:21.004'),
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(2, '2011-02-20 12:48:06.004'),
(2, '2011-02-20 12:53:07.733'),
(2, '2011-02-20 12:55:30.295');
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time
sequence
1 1 2011-02-20 12:30:00.000
00
2 1 2011-02-20 12:32:34.172
00
3 1 2011-02-20 12:32:34.172
01
4 1 2011-02-20 12:32:34.172
02
5 1 2011-02-20 12:46:39.745
00
6 2
2011-02-20 12:48:06.004 00
7 2
2011-02-20 12:48:07.003 00
8 2
2011-02-20 12:48:07.003 01
9 2
2011-02-20 12:46:39.745 00
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Thank You in Advance. :)

create table temp
(id int identity(1,1),
emp_id int,
time datetime
insert into temp values
(1, '20110220 12:30:00.000'),
(1, '20110220 12:32:34.172'),
(1, '20110220 12:32:34.172'),
(1, '20110220 12:43:21.004'),
(1, '20110220 12:46:39.745'),
(2, '20110220 12:48:06.004'),
(2, '20110220 12:48:06.004'),
(2, '20110220 12:53:07.733'),
(2, '20110220 12:55:30.295');
go
SELECT id, emp_id, time,
   dateadd(mcs, (row_number() OVER(PARTITION BY emp_id, time ORDER BY
id) - 1) * 10,
   convert(datetime2(5), time)) AS [Sequence]
FROM   temp
ORDER BY id
go
DROP TABLE temp
Erland Sommarskog, SQL Server MVP, [email protected]

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As for the minutes calculation it doesn't take Einstein to know that the number of minutes in a day = 24 (hours) * 60 (minutes)
SQL> ed
Wrote file afiedt.buf
1 with t as (select 1 as id, sysdate-10 as dt from dual union all
2             select 2, sysdate-7.4 from dual union all
3             select 3, sysdate-6.45 from dual union all
4             select 4, sysdate-2.82 from dual union all
5             select 5, sysdate from dual)
6 -- END OF TEST DATA
7 select id
8        ,dt
9        ,dt-lag(dt) over (order by id) as dt_diff_days
10        ,(dt-lag(dt) over (order by id))*(24*60) as dt_diff_minutes
11* from t
SQL> /
        ID DT                  DT_DIFF_DAYS DT_DIFF_MINUTES
         1 30/11/2007 13:07:37
         2 03/12/2007 03:31:37          2.6            3744
         3 04/12/2007 02:19:37          .95            1368
         4 07/12/2007 17:26:49         3.63          5227.2
         5 10/12/2007 13:07:37         2.82          4060.8
SQL>

Date difference in one column

Hi all,
I need the column DATEDIFFERENCE as per below
Kindly help me out .
How to perform on the same column .
Regards, Subathra

create table test (id varchar(10), createddate datetime, assigneddate datetime, resolveddate datetime)
insert into test values ('SD1023','4/2/2014 10:02:00','4/2/2014 10:06:00','6/2/2014 20:06:03')
insert into test values ('SD1023','4/2/2014 10:02:00','4/2/2014 10:20:01','6/2/2014 20:06:03')
insert into test values ('SD1023','4/2/2014 10:02:00','4/2/2014 12:02:00','6/2/2014 20:06:03')
insert into test values ('SD1023','4/2/2014 10:02:00','6/2/2014 20:06:03','6/2/2014 22:10:03')
insert into test values ('SD10123','6/2/2014 20:06:03','6/2/2014 20:06:03','6/2/2014 23:06:06')
insert into test values ('SD10123','6/2/2014 20:06:03','6/2/2014 21:06:04','6/2/2014 23:06:06')
insert into test values ('SD10123','6/2/2014 20:06:03','6/2/2014 22:06:05','6/2/2014 23:06:06')
insert into test values ('SD10123','6/2/2014 20:06:03','6/2/2014 23:06:06','6/2/2014 23:06:06')
;with mycte as (select *,row_number() Over(Partition by id Order by AssignedDate) rn1
,row_number() Over(Partition by id Order by AssignedDate DESC) rn2
from test)
,mycte1 as (
Select m0.id,m0.createddate,m0.assigneddate,m0.resolveddate,
CASE WHEN m0.rn1=1 Then m0.createddate Else m1.assigneddate End as dt1,
CASE WHEN m0.rn2=1 Then m0.resolveddate Else m0.assigneddate end as dt2
from mycte m0 left join mycte m1 on m0.id=m1.id and m0.rn1=m1.rn1+1)
select id,createddate,assigneddate,resolveddate
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drop table test

Difference in Minutes

I want to calculate minutes between these 2 rows:
My input data looks like:
id cola colb colc cold
123 12/14/2004 7:15:00 AM 12/14/2004 5:00:00 PM 12/14/2004 7:15:00 AM 12/14/2004 5:00:00 AM
123 12/14/2004 12:30:00 AM 12/14/2004 5:00:00 PM null null
Output looks like:
id cola colb cole colc cold colg
123 12/14/2004 7:15:00 AM 12/14/2004 5:00:00 PM 855 12/14/2004 7:15:00 AM 12/14/2004 5:00:00 AM 585
cole --> sum of difference of minutes between colb and cola from row 1 & 2
colg ---> difference in minutes between cold and colc
Thanks in advance

alter session set nls_date_format = 'MM/DD/YYYY HH:MI:SS PM'
with t as (
           select 123 id,to_date('12/14/2004 7:15:00 AM') cola,to_date('12/14/2004 5:00:00 PM') colb,to_date('12/14/2004 7:15:00 AM') colc,to_date('12/14/2004 5:00:00 AM') cold from dual union all
           select 123,to_date('12/14/2004 12:30:00 AM'),to_date('12/14/2004 5:00:00 PM'),to_date(null),to_date(null) from dual
select id,
        cola,
        colb,
        trunc((colb - cola) * 24 *60) cole,
        colc,
        cold,
        trunc((cold - colc) * 24 *60) colg
from t
        ID COLA                   COLB                         COLE COLC                   COLD                         COLG
       123 12/14/2004 07:15:00 AM 12/14/2004 05:00:00 PM        585 12/14/2004 07:15:00 AM 12/14/2004 05:00:00 AM       -135
       123 12/14/2004 12:30:00 AM 12/14/2004 05:00:00 PM        990
SQL> SY.

Need date difference in Minutes

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