No of days in a month in Query designer

Hi
I have Calender Year/Month (0CALMONTH) in the row of query,  I need to show no of days in that month, how can I do this in Query designer

Hi,
If the user requirment is to select a single month for analysis then you could possibly use a formula variable that is populated as a user exit to return the number of days in the month selected and then use this in your calculation.
This formula varible can be hidden from display in the query designer.
hope it gives you an idea.
regards,
CH

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  • Calculate no of execution month in query design

    Hi,
    I received requirements to create sales report as users would like to execute the sales report by entering the range of calendar month (eg: from 10.2010 to 12.2010). They would like to have average sales figures to be calculated as total sales / no of month (which is 3) that based on no of month that user had entered.
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    Thanks and regards,
    Kang Ring

    Hi,
    Please follow the below steps it will give you desired result.
    Make a new formula in that put value 1 and exception aggregation as counter of all detailed values and refernce characterstic as calmonth so it will give you 1 against all the months you entered in the selection screen.Suppose you enter for a range of 3 months so you will get count 111 and in result you will get 3.
    Now you want your sales to be divided by the sum of months count.
    In order to achieve that create another fornula  and put
    SUMGT(formula1) formula 1 is the first formula you created.
    After doing this you will get 3 against all your month.
    Now create another formula and in that put your sales keyfigure and divide by formula 2.
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    Hide formula 1 and formula 2.
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    Regards,
    AL

  • Using Calendar Year Month in query designer to populate a Month Structure

    Hi
    Is it possible to create a query that has a standard structure of Month Columns (Jan-Dec) with each month column populated by the correct 0CALMONTH (similar infoobject) value?  I would also like to be able to filter this by the correct year selected since this will be a filter value.
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    Hi,
    I would also like to be able to filter this by the correct year selected since this will be a filter value.
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  • Count days in a month for a date range

    i am trying to find no. of days between 2 Date Ranges for a list of Ids. i used the logic in the below link:
    count days of the month
    My query is giving duplicates since, I have list of Ids.
    Doctor_ID     Patient_ID     ARRIVE_DT_TM     DISCH_DT_TM
    755722     42972229     10/18/2012 7:50     3/14/2013 20:45
    763305     42972232     1/7/2013 20:27     3/15/2013 19:15
    25391509     42972298     2/4/2013 22:45     3/8/2013 22:03
    746779     42972331     1/4/2013 23:00     3/26/2013 21:50
    763305     42972338     3/4/2013 22:19     3/6/2013 19:35
    763305     42972411     11/4/2013 22:32     3/29/2013 17:30
    I am looking for query to give me for Patient_ID = 42972229
    MONTH     COUNT_DAYS
    201210     14
    201211     30
    201212     31
    201301     31
    201302     28
    201303     14
    I am running the following code and it loops through the months and gives duplicates when I remove where Patient_id IN (42972229)
    select
    Doctor_ID
    , Patient_ID
    , AR_DTTM
    , DSC_DTTM
    , TO_CHAR(ADD_MONTHS(TRUNC(date1, 'MONTH'), LEVEL - 1), 'YYYY MM') MONTHS_BET
    , (LEAST(date2, ADD_MONTHS(TRUNC(date1, 'MONTH') - 1, LEVEL)) - GREATEST(date1, ADD_MONTHS(TRUNC(date1, 'MONTH'), LEVEL - 1)))+ 1 AS DAYSCOUNT
    from (select
    Doctor_ID
    , Patient_ID
    , ARRIVE_DT_TM AR_DTTM
    , DISCH_DT_TM DSC_DTTM
    ,TRUNC(ARRIVE_DT_TM,'DDD') AS date1
    ,TRUNC(DISCH_DT_TM,'DDD') AS date2
    from temp where Patient_id IN (42972229)
    CONNECT BY LEVEL <= MONTHS_BETWEEN(TRUNC(date2, 'MONTH'), TRUNC(date1, 'MONTH')) + 1
    Please help!

    Hi,
    ASTRA_007 wrote:
    Results I would like to see are:
    Doctor_ID     Patient_ID     ARRIVE_DT_TM     DISCH_DT_TM     Month     CountofDays
    755722     42972229     10/18/2012 7:50     3/14/2013 20:45     2012 10     14
    755722     42972229     10/18/2012 7:50     3/14/2013 20:45     2012 11     30
    755722     42972229     10/18/2012 7:50     3/14/2013 20:45     2012 12     31
    755722     42972229     10/18/2012 7:50     3/14/2013 20:45     2013 01     31
    755722     42972229     10/18/2012 7:50     3/14/2013 20:45     2013 02     28
    755722     42972229     10/18/2012 7:50     3/14/2013 20:45     2013 03     14
    763305     42972232     1/7/2013 20:27     3/15/2013 19:15     2013 01     25
    763305     42972232     1/7/2013 20:27     3/15/2013 19:15     2013 02     28
    763305     42972232     1/7/2013 20:27     3/15/2013 19:15     2013 03     15
    and so on...So each row represents a patient-month, and you want to display several columns from the temp table on each output row. In that case, include all those columns in both the SELECT and GROUP BY clauses, like this:
    WITH     universe     AS
         SELECT     *
         FROM     temp
    --     WHERE     patient_id     IN (42972229)
    ,     date_range     AS
         SELECT     TRUNC (MIN (arrive_dt_tm))     AS first_date
         ,     TRUNC (MAX (disch_dt_tm))     AS last_date
         FROM     universe
    ,     all_dates     AS
         SELECT     first_date + LEVEL - 1     AS a_date
         FROM     date_range
         CONNECT BY     LEVEL     <= (last_date + 1) - first_date
    SELECT    u.doctor_id
    ,       u.patient_id
    ,       u.arrive_dt_tm
    ,       u.disch_dt_tm
    ,       TO_CHAR ( TRUNC (a.a_date, 'MONTH')
                  , 'YYYY MM'
                )          AS month
    ,       COUNT (*)          AS count_days
    FROM       all_dates  a
    JOIN       universe   u  ON  a.a_date  BETWEEN  TRUNC (u.arrive_dt_tm)
                                         AND      u.disch_dt_tm
    GROUP BY  u.doctor_id
    ,       u.patient_id
    ,       u.arrive_dt_tm
    ,       u.disch_dt_tm
    ,         TRUNC (a.a_date, 'MONTH')
    ORDER BY  u.patient_id
    ,       TRUNC (a.a_date, 'MONTH')
    ;Output from your sample data (with no filtering):
    `DOCTOR_ID PATIENT_ID ARRIVE_DT_TM     DISCH_DT_TM      MONTH   COUNT_DAYS
        755722   42972229 10/18/2012 7:50  3/14/2013 20:45  2012 10         14
        755722   42972229 10/18/2012 7:50  3/14/2013 20:45  2012 11         30
        755722   42972229 10/18/2012 7:50  3/14/2013 20:45  2012 12         31
        755722   42972229 10/18/2012 7:50  3/14/2013 20:45  2013 01         31
        755722   42972229 10/18/2012 7:50  3/14/2013 20:45  2013 02         28
        755722   42972229 10/18/2012 7:50  3/14/2013 20:45  2013 03         14
        763305   42972232 1/7/2013 20:27   3/15/2013 19:15  2013 01         25
        763305   42972232 1/7/2013 20:27   3/15/2013 19:15  2013 02         28
        763305   42972232 1/7/2013 20:27   3/15/2013 19:15  2013 03         15
      25391509   42972298 2/4/2013 22:45   3/8/2013 22:3    2013 02         25
      25391509   42972298 2/4/2013 22:45   3/8/2013 22:3    2013 03          8
        746779   42972331 1/4/2013 23:0    3/26/2013 21:50  2013 01         28
        746779   42972331 1/4/2013 23:0    3/26/2013 21:50  2013 02         28
        746779   42972331 1/4/2013 23:0    3/26/2013 21:50  2013 03         26
        763305   42972338 3/4/2013 22:19   3/6/2013 19:35   2013 03          3
    In the end the objective is to count the no. of days in each month between the arrival and discharge dates by Physician and for his/her patients.Then is the output above really what you want? Say you're interested in physician 763305. That physician had 18-patient days in March, 2013, but the output doesn't make it clear.
    I ran your query, it works great but I have a long list of patients for whom I have to run these counts.the query above includes all patient_ids.
    That's a separate problem, to be solved in the first sub-query, universe. The rest of the query will be unchanged.
    How will you know which patients to include? If you can derive the list from temp itself, just use a WHERE clause in universe. If you need to look at other tables, join them in universe, or use them in sub-queries in universe, or both.
    For exmple, if you decide that the list of patient_ids has no pattern, and that you'll need to store their ids in a separate table (perhaps a global temporary table), then universe might be:
    WITH     universe     AS
         SELECT     t.*     -- or list columns needed
         FROM     temp                        t
         JOIN     patient_ids_to_include  p 
                      ON  p.patient_id = t.patient_id
    ) ...The rest of the query can be the same as above.
    If a same patient is admitted again then Patient_ID will be different no matter when readmitted.Are you saying that patient_id identifies a visit, not a patient, and that the same person is assigned a different patient_id every time that person is admitted?
    For
    INSERT INTO temp (doctor_id, patient_id, arrive_dt_tm, disch_dt_tm)
    VALUES ( 755722
    , 42972229
    , TO_DATE ('03/14/2013 23:00', 'MM/DD/YYYY HH24:MI')
    , TO_DATE ('04/01/2013 12:00', 'MM/DD/YYYY HH24:MI')
    First the Patient ID will be different from the earlier admission. Second the results will show like:
    Doctor_ID     Patient_ID     ARRIVE_DT_TM     DISCH_DT_TM     Month     CountofDays
    755722     42972229     3/14/2013 23:00     4/1/2013 12:00     2012 03     14
    755722     42972229     3/14/2013 23:00     4/1/2013 12:00     2012 04     1Are you saying that temp.patient_id is unique, and so the situation is impossible?
    Edited by: Frank Kulash on May 7, 2013 10:23 AM

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    Any ideas on how to achieve this without creating 12 different Customer Exit variables (one for each end date of each month)?
    Thanks
    Regards
    Oddmar Lid

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                                        , 'DD-MON-YYYY'
                            ) - 8
                             , 'SUNDAY'
                     ) + (7 * 2)     -- Last number is week number
    This is not an excellent way to do it as it does not take care of leap years and it does not scan and update values in the whole table for all years correctly.
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    I hope this answers your question.
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    See the forum FAQ {message:id=9360002}

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  • Elapse days - calculation from month and year

    Duplicate thread ...
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    Edited by: Arun Varadarajan on Apr 5, 2009 10:44 PM
    Edited by: Arun Varadarajan on Apr 5, 2009 10:45 PM

    Hello,
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    Regards,
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    REPORT  zqty_to_date.
    PARAMETERS:
      p_date     TYPE dats,
      p_qty      TYPE i.
    DATA:
      days      TYPE i,
      n_year    TYPE numc4,
      n_month   TYPE numc2,
      n_day     TYPE numc2,
      qtd(6)    TYPE p DECIMALS 1.
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      n_month = p_date+4(2).
      n_day = p_date+6(2).
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    *&      Form  days_in_month
    *       text
    FORM days_in_month USING year month CHANGING days.
      DATA: ymod4   TYPE i,
            ymod100 TYPE i,
            ymod400 TYPE i.
      CASE month.
        WHEN 4 OR 6 OR 9 OR 11.
          days = 30.
        WHEN 2.
          ymod4 = year MOD 4.
          ymod100 = year MOD 100.
          ymod400 = year MOD 400.
          IF ( ymod4 = 0 AND ymod100 > 0 ) OR ( ymod100 = 0 AND ymod400 = 0 ).
            days = 29.
          ELSE.
            days = 28.
          ENDIF.
        WHEN OTHERS.
          days = 31.
      ENDCASE.
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  • Show data of last day of previous month against any day of current month

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