NT Lan Manager call from servlet

Can someone please point me in the right direction for some documentation, or even an example, of how to access the NT Lan Manager user information from a Java Servlet?
I am using iAS Java Edition.
Best regards
Christian Almgren

You can use
String s = response.encodeRedirectURL("http://www.sandeep.com/hello?sid=2222");
response.sendRedirect(s);
Or you could use the RequestDispatcher class
RequestDispatcher rd = this.getServletConfig().getServletContext().getNamedDispatcher("myservlet")
where myServlet is your registered name
rd.forward(request,response);
Hope this helps!!
Sandeep
null

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Tomcat /manager commends from Servlet

Hi all,
I asked a question regarding the excution of Tomcat /manager commands from a servlet and I got no replies... :(
Well, I never found a way to directly execute the /manager commands from the servlet (API) - but I did (eventually) get it working via URLConnection. Now, I've decided to release my (simple) code here so that it may help others!
This code searches for a context and then checks if it is running, if it is found not to be running it will attempt to start it. (tested and found to work under Tomcat 5.0.28).
String
    protocol = "http",
    host      = "localhost",
    usr       = "usr",
    pwd       = "pwd",
    context   = "/myapp";
int port = 80;
URL list = new URL(protocol,host,port,"/manager/list");
URLConnection c = (URLConnection)list.openConnection();
String encs = new sun.misc.BASE64Encoder().encode((usr+":"+pwd).getBytes());
c.setDoInput(true);
c.setRequestProperty("Authorization", "Basic " + encs);
c.connect();
BufferedReader buf = new BufferedReader(new InputStreamReader(c.getInputStream()));
String line;
while ( (line = buf.readLine()) != null )
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    if ( line.startsWith(context+":") )
       * Found the context
       * Now make sure that it's running
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        buf.close();
        System.out.println("Context ["+context+"] - Attempting to start context...");
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        c.setRequestProperty("Authorization", "Basic " + encs);
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notes:
The buffer reading after both commands seems to be required! I don't know why... But I found that without them, the manager commands seem to be ignored!?!? odd!
Well, I hope this helps someone...

thanx
but when i am Deploying directory or WAR file located on server
where is this XML Configuration file,
so that i can fill in the text box-XML Configuration file URL
and secondly in tomcat 5.5.4
there is no context path described in server.xml
so where is this in 5.5.4

Best Practice for EJB calls from servlet?

Hi folks
I could not find general rules for making calls to an stateful EJB from the web container (e.g. from a backingBean). In some books they say it is a bad programming style calling them directly from a common servlet. The book says create first an HTTPSession Object and from there call the stateful EJB.
I'm a bit confused because, I'm missing some best practice guide from where to initiate such calls.
Can somebody please point me in the right direction?
Kind Regards
Bruno
Edited by: zajoho on Oct 30, 2008 11:14 PM

Hi Bruno,
The main issue with the combination of stateful session beans and servlets is the servlet threading model.
It is dangerous to store a stateful session bean reference in servlet instance state, since the servlet instance
can be accessed concurrently, yet a stateful session bean reference is intended to be used by only one
client.
As you point out, one alternative is to store the reference in the HttpSession. That associates the reference
with a particular client, which matches the stateful session bean programming model.

Sabre web service call from servlet

hi all:
I need to call sabre web service from my application. sabre have provided one utility (bat file for windows environment), this is working fine. I have just created servlet and called this web service in the same way as this batch file calling using java program.
I am facing below problem while calling this sabre web service.. I am facing this problem.
XSL-1900: (Fatal Error) An internal error condition occurred.
05/07/21 17:10:05 java.io.IOException: SOAP exception while trying to externalize: Unable to create envelope from given source: XSL-1900: (Fatal Error) An internal error condition occurred.
05/07/21 17:10:05 at com.sun.xml.messaging.saaj.soap.SOAPPartImpl.getContentAsStream(SOAPPartImpl.java:189)
05/07/21 17:10:05 at com.sun.xml.messaging.saaj.soap.SOAPPartImpl$1.getInputStream(SOAPPartImpl.java:232)
05/07/21 17:10:05 at javax.activation.DataHandler.writeTo(DataHandler.java:297)
05/07/21 17:10:05 at javax.mail.internet.MimeBodyPart.writeTo(MimeBodyPart.java:1089)
05/07/21 17:10:05 at javax.mail.internet.MimeBodyPart.writeTo(MimeBodyPart.java:635)
05/07/21 17:10:05 at javax.mail.internet.MimeMultipart.writeTo(MimeMultipart.java:233)
05/07/21 17:10:05 at com.sun.xml.messaging.saaj.soap.MessageImpl.saveChanges(MessageImpl.java:372)
05/07/21 17:10:05 at com.sun.xml.messaging.saaj.soap.MessageImpl.writeTo(MessageImpl.java:399)
05/07/21 17:10:05 at com.sabre.universalservices.wsclient.SoapClient.sendSoapMessage(SoapClient.java:112)

Hai ,
I am new to this sabre web service. now we are using eSAPI connection to connect to Sabre.
we want to upgrade it into "sabre web service".
will you please help on this...
I don't know how to start...
please give your mail ID.... My Id is [email protected]
Thanks !!!!!!!

Accessing an IFRAME tag after page being called from Servlet

Hi there, can anyone help me please.
I have two JSP pages, JSP1a and JSP2. When I call JSP1a from my browser, it runs some alert messages and then calls JSP2, which does a check on my database and then returns control to JSP1a and reloads the page. This all works fine.
I am now trying to integrate these two pages into my main app, but I get a problem. I am now calling JSP1a, from a controlling Java Servlet (my app is based around a Model 2 architecture) which fires fine, but the reference to the line
"window.frames.hidFrame.location.href=jsp2.jsp"
doesnt seem to work. "hidFrame" is an IFRAME in the body tag of my JSP1a page.
Can anyone help ? why does this line not fire, when the page has been loaded from a Java Servlet ? but it fires fine when I load the page directly ? and what is the solution to get around this problem please.
Thanks
Robert
JSP1a.jsp
<HTML>
<HEAD>
<SCRIPT language="JavaScript" type="text/javascript">
     function checkFunction(){
          var seconds = new Date();
          alert("inside function 1c ");
          window.frames.hidFrame.location.href = "jsp2.jsp";
     function retMessage(){
          alert("inside return function");
          window.location.reload(true);
</SCRIPT>
</HEAD>
<BODY onload="setTimeout('checkFunction()',5000);">
<p>this is JSP1a</p>
<SCRIPT language="JavaScript">
alert("inside main body");
</SCRIPT>
<IFRAME frameborder="0" id="hidFrame" style="display:none"></iframe>
</BODY>
</HTML>
JSP2.jsp
<%@ page import="java.util.*" %>
<jsp:useBean id="dbBean" scope="application" class="myApp.DbBean"/>
<HTML>

<%
boolean flag = false;
int i=1;
flag = dbBean.checkForUpdates();
System.out.println("flag = " + flag);
//if(flag == false) {
if (i == 1){
%>
     <BODY onload="parent.retMessage()">
<%} else {%>
     <BODY onload="parent.setTimeout('checkFunction()', 5000)">
<%}%>
</BODY>
</HTML>

its ok, I have found the problem. Someone recommended to me to change the IFRAME tag to make it visible just while I was debugging and low-and-behold there was a 404 error message being displayed which I had no idea about. It couldnt find my JSP2.jsp page. Because I am calling JSP1a from a servlet now, I needed to add a full path to my reference so that the servlet would know where to look. I did this and it works ok. I know its probably not best practice to hard code the full path to JSP2.jsp, I guess I should go back to the servlet and call JSP2 from there ?
Regards
Robert

Request dispatcher and jsp pages called from servlets

          Given the following webapp directory structure:
          root/
          jsp/
          ..all jsp files
          web-inf/
          classes/
          /servlets
               ..all servlet files
          /com
          ..all other java class files
          I have the jsp directory coded as: jspdir = "/jsp/" (and have tried variations
          on this theme)
          I try to open a new jsp page with the following code in a servlet in the above
          servlet directory:
               RequestDispatcher rd;
               rd = getServletContext().getRequestDispatcher(jspdir + myjsp.jsp);
               rd.forward(req, res);
          rd continues to return null.
          The jsp pages are not registered in the web.xml file for this webapp, if that
          makes any difference.
          Does anyone have any suggestions?
          [problem.txt]


I create a small sample and put these files into /jsp in my war context
          it works fine, please send me the example code you are using and the
          environment description of the deployed application
          I attached my samples, that work
          Filip
          ~
          Namaste - I bow to the divine in you
          ~
          Filip Hanik
          Software Architect
          [email protected]
          www.filip.net
          "Bill Blackmon" <[email protected]> wrote in message
          news:[email protected]...
          >
          > Yes, I am able to access the jsp pages with the url listed.
          >
          > "Filip Hanik" <[email protected]> wrote:
          > >The weblogic servlet engine, is by default mapping anything that ends
          with
          > >*.jsp to be a JSP.
          > >so there shouldn't be a problem. You didn't answer my first question,
          > >are you able to access your JSP through the browser?
          > >http://localhost:7001/root/jsp/myjsp.jsp
          > >
          > >Filip
          > >
          > >--
          > >~
          > >Namaste - I bow to the divine in you
          > >~
          > >Filip Hanik
          > >Software Architect
          > >[email protected]
          > >www.filip.net
          > >"Bill Blackmon" <[email protected]> wrote in message
          > >news:[email protected]...
          > >>
          > >> The code you are reading in the message here was pasted in and
          > >> looks bad, so maybe that's what you are referring to? The dispatcher
          code
          > >is called
          > >> in the service() method of the servlet.
          > >> I have a suspicion that the jsp directory needs to be defined someplace
          > >-
          > >weblogic.properties
          > >> or web.xml?, though I don't see this in any of the examples that come
          > >with
          > >the product.
          > >>
          > >>
          > >>
          > >> "Simon Ng" <[email protected]> wrote:
          > >> >
          > >> >Hello Bill,
          > >> > Did you put a <BR>
          > >> >return;
          > >> ><BR>
          > >> >statement right after the dispatcher.forward() statement? Well, I am
          > >assuming
          > >> >your
          > >> >code is in the doPost() or doGet() methods.
          > >> >
          > >> >Simon
          > >> >
          > >> >
          > >> >"Filip Hanik" <[email protected]> wrote:
          > >> >>if you do http://localhost:7001/root/jsp/myjsp.jsp
          > >> >>
          > >> >>do you get a result?
          > >> >>
          > >> >>make sure you have the right character case on the filename.
          > >> >>
          > >> >>Filip
          > >> >>
          > >> >>--
          > >> >>~
          > >> >>Namaste - I bow to the divine in you
          > >> >>~
          > >> >>Filip Hanik
          > >> >>Software Architect
          > >> >>[email protected]
          > >> >>www.filip.net
          > >> >>"Bill Blackmon" <[email protected]> wrote in message
          > >> >>news:[email protected]...
          > >> >>>
          > >> >>> Given the following webapp directory structure:
          > >> >>> root/
          > >> >>> jsp/
          > >> >>> ..all jsp files
          > >> >>> web-inf/
          > >> >>> classes/
          > >> >>> /servlets
          > >> >>> ..all servlet files
          > >> >>> /com
          > >> >>> ..all other java class files
          > >> >>>
          > >> >>>
          > >> >>> I have the jsp directory coded as: jspdir = "/jsp/" (and have tried
          > >> >>variations
          > >> >>> on this theme)
          > >> >>> I try to open a new jsp page with the following code in a servlet
          > >in
          > >> >the
          > >> >>above
          > >> >>> servlet directory:
          > >> >>> RequestDispatcher rd;
          > >> >>> rd = getServletContext().getRequestDispatcher(jspdir + myjsp.jsp);
          > >> >>> rd.forward(req, res);
          > >> >>>
          > >> >>> rd continues to return null.
          > >> >>>
          > >> >>> The jsp pages are not registered in the web.xml file for this
          webapp,
          > >> >>if
          > >> >>that
          > >> >>> makes any difference.
          > >> >>>
          > >> >>> Does anyone have any suggestions?
          > >> >>>
          > >> >>
          > >> >>
          > >> >
          > >>
          > >
          > >
          >
          [filipInclude.jsp]
          [filipForward.jsp]
          [filip.jsp]

I want to send a response from the servlet and then call another servlet.

Hi,
I want to send a response from the servlet and then call another servlet. can this happen. Here is my scenario.
1. Capture all the information from a form including an Email address and submit it to a servlet.
2. Now send a message to the browser that the request will be processed and mailed.
3. Now execute the request and give a mail to the mentioned Email.
Can this be done in any way even by calling another servlet from within a servlet or any other way.
Can any one Please help me out.
Thanks,
Ramesh

Maybe that will help you (This is registration sample):
1.You have Registration.html;
2.You have Registration servlet;
3.You have CheckUser servlet;
4.And last you have Dispatcher between all.
See the code:
Registration.html
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<HTML>
<HEAD>
    <TITLE>Hello registration</TITLE>
</HEAD>
<BODY>
<H1>Entry</H1>
<FORM ACTION="helloservlet" METHOD="POST">
<LEFT>
User: <INPUT TYPE="TEXT" NAME="login" SIZE=10><BR>
Password: <INPUT TYPE="PASSWORD" NAME="password" SIZE=10><BR>
<P>
<TABLE CELLSPACING=1>
<TR>
<TH><SMALL>
<INPUT TYPE="SUBMIT" NAME="logon" VALUE="Entry">
</SMALL>
<TH><SMALL>
<INPUT TYPE="SUBMIT" NAME="registration" VALUE="Registration">
</SMALL>
</TABLE>
</LEFT>
</FORM>
<BR>
</BODY>
</HTML>
Dispatcher.java
package mybeans;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.ServletException;
import java.io.IOException;
import javax.servlet.RequestDispatcher;
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
public class Dispatcher extends HttpServlet {
    protected void forward(String address, HttpServletRequest request,
                           HttpServletResponse response)
                           throws ServletException, IOException {
                               RequestDispatcher dispatcher = getServletContext().
                               getRequestDispatcher(address);
                               dispatcher.forward(request, response);
Registration.java
package mybeans;
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
public class Registration extends Dispatcher {
    public String getServletInfo() {
        return "Registration servlet";
    public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        ServletContext ctx = getServletContext();
        if(request.getParameter("logon") != null) {
            this.forward("/CheckUser", request, response);
        else if (request.getParameter("registration") != null) {
            this.forward("/registration.html", request, response);
CheckUser.java
package mybeans;
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
import java.sql.*;
public class CheckUser extends Dispatcher {
    Connection conn;
    Statement stat;
    ResultSet rs;
      String cur_UserName;
    public static String cur_UserSurname;;
    String cur_UserOtchestvo;
    public String getServletInfo() {
        return "Registration servlet";
    public void service(HttpServletRequest request, HttpServletResponse response)
    throws ServletException, IOException {
        try{
            ServletContext ctx = getServletContext();
            Class.forName("oracle.jdbc.driver.OracleDriver");
            conn = DriverManager.getConnection("jdbc:oracle:oci:@eugenz","SYSTEM", "manager");
            stat = conn.createStatement(ResultSet.TYPE_SCROLL_SENSITIVE, ResultSet.CONCUR_UPDATABLE);
           String queryDB = "SELECT ID, Login, Password FROM TLogon WHERE Login = ? AND Password = ?";
            PreparedStatement ps = conn.prepareStatement(queryDB);
           User user = new User();
        user.setLogin(request.getParameter("login"));
        String cur_Login = user.getLogin();
        ps.setString(1, cur_Login);
        user.setPassword(request.getParameter("password"));
        String cur_Password = user.getPassword();
        ps.setString(2, cur_Password);
     Password = admin");
        rs = ps.executeQuery();
             String sn = "Zatoka";
        String n = "Eugen";
        String queryPeople = "SELECT ID, Surname FROM People WHERE ID = ?";
       PreparedStatement psPeople = conn.prepareStatement(queryPeople);
                  if(rs.next()) {
            int logonID = rs.getInt("ID");
            psPeople.setInt(1, logonID);
            rs = psPeople.executeQuery();
            rs.next();
                   user.setSurname(rs.getString("Surname"));
          FROM TLogon, People WHERE TLogon.ID = People.ID";
                   ctx.setAttribute("user", user);
            this.forward("/successLogin.jsp", request, response);
        this.forward("/registration.html", request, response);
        catch(Exception exception) {
}CheckUser.java maybe incorrect, but it's not serious, because see the principe (conception).
Main is Dispatcher.java. This class is dispatcher between all servlets.

Calling a servlet from af:button

Hi
I am invoking a servlet using af:commandbutton. I am trying that this servlet be invoked by authenticated user. For this, I injected ADFContext.getCurrent.getSecurityContext().isAuthenticated(); in servlet.
Based, on the *...isAuthenticated()* method value , doGet() should execute code.
But this warning is coming -
<ADFContext> <getCurrent> Automatically initializing a DefaultContext for getCurrent.
Caller should ensure that a DefaultContext is proper for this use.
Memory leaks and/or unexpected behaviour may occur if the automatic initialization is performed improperly.
This message may be avoided by performing initADFContext before using getCurrent(). Is this right to use ADFContext in servlet? Should I ignore warning?
I cannot use 'isAuthenticated()' as a parameter from commandbutton's managed bean. Since user can see the servlet parameter url in browser & without authentication , they can call the servlet.
What is the way to avoid this type of situation?
Using Jdev 11.1.1.5 with ADF RC with WLS 10.3.5.

You can ignore this warning

How to call a servlet in new window without toolbar from OA page

How to call a servlet in new window without toolbar from a OA page?Please provide sample code

I have tried with the way suggested in Mukul's blog using javascript in Destination URI property.
I tried to open a OA Page and from which forwarded it to a servlet..
It is showing the error:
Error Page
Exception Details.
oracle.apps.fnd.framework.OAException: The application id or shortname () you entered does not exist.
     at oracle.apps.fnd.framework.webui.OAPageErrorHandler.prepareException(OAPageErrorHandler.java:1223)
     at oracle.apps.fnd.framework.webui.OAPageBean.preparePage(OAPageBean.java:1969)
     at oracle.apps.fnd.framework.webui.OAPageBean.preparePage(OAPageBean.java:502)
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     at oracle.jsp.runtime.HttpJsp.service(HttpJsp.java:119)
     at oracle.jsp.app.JspApplication.dispatchRequest(JspApplication.java:385)
     at oracle.jsp.JspServlet.doDispatch(JspServlet.java:259)
     at oracle.jsp.JspServlet.internalService(JspServlet.java:178)
     at oracle.jsp.JspServlet.service(JspServlet.java:148)
     at javax.servlet.http.HttpServlet.service(HttpServlet.java:588)
     at oracle.jsp.provider.Jsp20RequestDispatcher.forward(Jsp20RequestDispatcher.java:162)
     at oracle.jsp.runtime.OraclePageContext.forward(OraclePageContext.java:175)
     at oa_html._OA._jspService(_OA.java:96)
     at oracle.jsp.runtime.HttpJsp.service(HttpJsp.java:119)
     at oracle.jsp.app.JspApplication.dispatchRequest(JspApplication.java:385)
     at oracle.jsp.JspServlet.doDispatch(JspServlet.java:259)
     at oracle.jsp.JspServlet.internalService(JspServlet.java:178)
     at oracle.jsp.JspServlet.service(JspServlet.java:148)
     at javax.servlet.http.HttpServlet.service(HttpServlet.java:588)
     at org.apache.jserv.JServConnection.processRequest(JServConnection.java:456)
     at org.apache.jserv.JServConnection.run(JServConnection.java:294)
     at java.lang.Thread.run(Thread.java:534)
## Detail 0 ##
oracle.apps.fnd.framework.OAException: The application id or shortname () you entered does not exist.
     at oracle.apps.fnd.framework.webui.OAWebBeanFactoryImpl.getAppId(OAWebBeanFactoryImpl.java:5391)
     at oracle.apps.fnd.framework.webui.OAPageBean.preparePage(OAPageBean.java:969)
     at oracle.apps.fnd.framework.webui.OAPageBean.preparePage(OAPageBean.java:502)
     at oracle.apps.fnd.framework.webui.OAPageBean.preparePage(OAPageBean.java:423)
     at oa_html._OA._jspService(_OA.java:86)
     at oracle.jsp.runtime.HttpJsp.service(HttpJsp.java:119)
     at oracle.jsp.app.JspApplication.dispatchRequest(JspApplication.java:385)
     at oracle.jsp.JspServlet.doDispatch(JspServlet.java:259)
     at oracle.jsp.JspServlet.internalService(JspServlet.java:178)
     at oracle.jsp.JspServlet.service(JspServlet.java:148)
     at javax.servlet.http.HttpServlet.service(HttpServlet.java:588)
     at oracle.jsp.provider.Jsp20RequestDispatcher.forward(Jsp20RequestDispatcher.java:162)
     at oracle.jsp.runtime.OraclePageContext.forward(OraclePageContext.java:175)
     at oa_html._OA._jspService(_OA.java:96)
     at oracle.jsp.runtime.HttpJsp.service(HttpJsp.java:119)
     at oracle.jsp.app.JspApplication.dispatchRequest(JspApplication.java:385)
     at oracle.jsp.JspServlet.doDispatch(JspServlet.java:259)
     at oracle.jsp.JspServlet.internalService(JspServlet.java:178)
     at oracle.jsp.JspServlet.service(JspServlet.java:148)
     at javax.servlet.http.HttpServlet.service(HttpServlet.java:588)
     at org.apache.jserv.JServConnection.processRequest(JServConnection.java:456)
     at org.apache.jserv.JServConnection.run(JServConnection.java:294)
     at java.lang.Thread.run(Thread.java:534)
oracle.apps.fnd.framework.OAException: The application id or shortname () you entered does not exist.
     at oracle.apps.fnd.framework.webui.OAWebBeanFactoryImpl.getAppId(OAWebBeanFactoryImpl.java:5391)
     at oracle.apps.fnd.framework.webui.OAPageBean.preparePage(OAPageBean.java:969)
     at oracle.apps.fnd.framework.webui.OAPageBean.preparePage(OAPageBean.java:502)
     at oracle.apps.fnd.framework.webui.OAPageBean.preparePage(OAPageBean.java:423)
     at oa_html._OA._jspService(_OA.java:86)
     at oracle.jsp.runtime.HttpJsp.service(HttpJsp.java:119)
     at oracle.jsp.app.JspApplication.dispatchRequest(JspApplication.java:385)
     at oracle.jsp.JspServlet.doDispatch(JspServlet.java:259)
     at oracle.jsp.JspServlet.internalService(JspServlet.java:178)
     at oracle.jsp.JspServlet.service(JspServlet.java:148)
     at javax.servlet.http.HttpServlet.service(HttpServlet.java:588)
     at oracle.jsp.provider.Jsp20RequestDispatcher.forward(Jsp20RequestDispatcher.java:162)
     at oracle.jsp.runtime.OraclePageContext.forward(OraclePageContext.java:175)
     at oa_html._OA._jspService(_OA.java:96)
     at oracle.jsp.runtime.HttpJsp.service(HttpJsp.java:119)
     at oracle.jsp.app.JspApplication.dispatchRequest(JspApplication.java:385)
     at oracle.jsp.JspServlet.doDispatch(JspServlet.java:259)
     at oracle.jsp.JspServlet.internalService(JspServlet.java:178)
     at oracle.jsp.JspServlet.service(JspServlet.java:148)
     at javax.servlet.http.HttpServlet.service(HttpServlet.java:588)
     at org.apache.jserv.JServConnection.processRequest(JServConnection.java:456)
     at org.apache.jserv.JServConnection.run(JServConnection.java:294)
     at java.lang.Thread.run(Thread.java:534)

How to call a servlet from another servlet

hi everybody,
i have a problem, i have to call one servlet from another one.
Everything works on my pc, but when i install the application on the customer's server i got an error about an Uknown URL followed by the name of the machine.
Wjat i do is the folloqing :
String urlString = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+"/"+servletName;
URL url = new URL(urlString);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
the variable servletName is the name of the servlet i have to call.
Is there another way to call the servlet ?
All the servlet are installed in the same server.
Any suggestion ?
Cheers.
Stefano

Sweep is correct about requestDispatcher being another approach for inter-servlet delegation; the only issue that i recall with this approach is that it defaults the method of the destination servlet to the one it was called from...for example, calling servlet2 from within servlet1.post() resulted in the dispatcher attempting to utilize servlet2.post() - i believe that i searched for a parameterize solution to no avail :( (ended up handling the request by placing a "fake" doPost() in servlet2 that simply called servlet2.doGet())
however, if your application is functioning correctly on your pc/webserver then the problem may be external to servlet communication (e.g. client webserver's ports not configured or blocked, missing runtime classes, etc.)
my suggestion would be to set aside the programmatic concerns for the moment - what is the response if you open a browser on a client's machine and access the URL in question (i.e. http://clientserver:port/stefanoServlet)? If it will not respond to access in this manner then it certainly won't when your application calls for it.
It's possible that there is a coding error but, given the info supplied, i'd start examining the environment, first. Let us know if you have any luck with the test i recommended or not (please provide abundant detail). Or, if you've found the solution then you may want to post back with a quick blub so the next person knows how to escape the trap.
D

How can I display the HTML page from servlet which is called by an applet

How can I display the HTML page from servlet which is called by an
applet using the doPost method. If I print the response i can able to see the html document. How I can display it in the browser.
I am calling my struts action class from the applet. I want to show the response in the same browser.
Code samples will be appreciated.

hi
I got one way for this .
call a javascript in showDocument() to submit the form

How can i call a servlet from a servlet ?

Hello,
Can i call a Servlet from within a Servlet ?
and is it "right thing" to Do ?
Thanks

JMO, but I wouldn't do it like this.
Don't have a remote object like a servlet doing database queries for your app. That will mean TWO network hops for every query if the database resides on another machine. The network is the biggest bottleneck you've got.
Write a JavaBean that does the database stuff for you and just have the first servlet instantiate it when it needs it. A Bean has a better chance of being reused, too. Write a TableGateway or DAO for your object.
Or write an EJB to do it.
The only time I've done a servlet-to-servlet connection like that was for one servlet running in a DMZ that would authenticate a user and then forward the request to another servlet running inside the second firewall.
I wouldn't encapsulate database query logic in a servlet like that. JMO - MOD

Getting error while calling ejb business methods from servlet

Hi
Iam getting error when i try to call a ejb method from servlet.Error is
"com.netscape.server.eb.UncheckedException: unchecked exception nested exception is:java.lang.NullPointerException".
I build the application and deployed it successfully.Iam using IAS 6.O with windows NT 4.0.
This is just a method which takes values from database and return as an array of bean to servlet.
Any help on this.Thanks Shank

Hi
I was using the session bean.Your suggestion helped me a lot.Perfect.
I debug my program and found that from ejbCreate()exception is getting.
I was getting the datasource object thro ejb create() initialisation.
Somehow the look up jndi which i mentioned was not interpretting from ejb-jar.xml ias-ejb-jar.xml and datasource ref .Due to this iam getting jndi Namenotfound exception which in turns to null pointer as datasource is getting null.
when i hardcoded in the ejb the the jndi name for datasource it is working fine.Bit worried all the existing ejbs working with the xml referenced datasource and jndi,but when i added a new ejb with same properties it is failing to get the jndi name.
Piece of code from ias-ejb-jar.xml
<resource-ref>
          <res-ref-name>myDataSource</res-ref-name>
          <jndi-name>jdbc/nb/myData</jndi-name>
</resource-ref>
Piece of code from ejb-jar.xml
<resource-ref>
          <res-ref-name>myDataSource</res-ref-name>
          <res-type>javax.sql.DataSource</res-type>
          <res-auth>Container</res-auth>
</resource-ref>
Thanks a lot meka

What is the best way to call a servlet from another servlet?

I have a project with 9 servlets (class project). The way I have been moving from servlet to servlet is like this
doPost(...)
{ response.setContentType(CONTENT_TYPE);
PrintWriter out = response.getWriter();
out.println("<html>");
out.println("<head><title>Functions</title>");
out.println(f"<form name=frm6 method=post action=/servlet2");
out.println("<input type=submit name='btn' value='servlet2'>");
out.println("</form>");
So I have these 9 servlets - I call any 8 of them from the first servlet so I have 8 buttons on 8 forms <form=frm1, frm2, ...frm8 method = post...> But when I bring up the first servlet only 6 buttons show up. I was thinking about using hyperlinks instead, but I would like to do this with buttons. I wanted to do this with javascript and the location object, but I was advised to use jsp. I just want to move from one servlet to the next. Any suggestions appreciated for the best/preferred method for moving from one servlet to the next.
Thanks

I think you may need some clarification of terminology etc..
First off, JSP isn't an alternative to javascript, it's an alternative to coding a servlet. A JSP is a mixture of java code and HTML and is translated into a servlet by the system. JSPs are primarilly for generating HTML pages with variable content. JSPs very frequently generate HTML which includes Javascript.
You probably shouldn't think of what you're doing as one servlet invoking another, that does happen; a servlet can transfer an transaction to another servlet or JSP. In fact it's standard practice that a servlet does the logical stuff (like interpretting form data) then transfers to a JSP to generate the response page. However in this case it's the browser that can invoke one of the 8 servlets, the first servlet merely creates the page from which they are invoked.
It's not obvious why only some of your buttons are showing up. In a case like this use the "view source" option on your browser to find out what HTML the servlet is actually delivering. What's wrong should be evident from that.
You can put a hyperlink arround a button, or an image. Mostly people turn up their noses at the buttons supplied by HTML and use their own images for buttons. You
can do somthing like this:
<img src="/images/button3.png" border="0">
(Of course this arrives as a GET transaction not a POST).
Or you can do a bit of javascript like:
<img src="/images/button3.png" style="Cursor: pointer;"
onclick="document.locations.href='/servlet3';">

Help needed to call a servlet from an applet

Hi,
can someone help me with the way to call a servlet from an applet.
actually on click of a button i wanna call my servlet and save some data in DB.
i am not able to call my servlet. see the sample code which i am trying..
public void actionPerformed(ActionEvent event) {
if (event.getActionCommand().equals("Upload")) {
try {
System.out.println("Upload button has been clicked -----------");
URL url = new URL("http://localhost:8084/uploadApp/TestServlet");
URLConnection urlConnection = url.openConnection();
urlConnection.setDoInput(true);
urlConnection.setDoOutput(true);
urlConnection.setUseCaches(false);
ObjectOutputStream objOut = new ObjectOutputStream (urlConnection.getOutputStream());
objOut.writeBytes(userId); // pass parameter to servlet
objOut.flush();
objOut.close();
} catch (MalformedURLException ex) {
Logger.getLogger(ButtonListener.class.getName()).log(Level.SEVERE, null, ex);
} catch (IOException ex) {
Logger.getLogger(ButtonListener.class.getName()).log(Level.SEVERE, null, ex);
is there any problem with the code? please suggest.

hii,
checkout my add from, HTH
[http://forums.sun.com/thread.jspa?threadID=5419921&messageID=10885709#10885709]
... kopik

NT Lan Manager call from servlet

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