NumberFormat parse() bug ? Please Help

Question

It seems like parse() method of NumberFormat fails silently for string with a number in scientific notation such as "1.456000E+05" -- I had to use a doubleValue(0 from Double().
This very short piece illustrates it -- Can anyone please comment on any fallacies here ?
Thanks.
// Numberformat parse() fails when parsing
// string to get double value
// But Double.doubleValue() works
import java.io.*;
import java.text.*;
public class jf {
public static void main(String args[]) {
String str = "1.456000E+05";
System.out.println("Original string: str="+str);
NumberFormat nf = NumberFormat.getInstance();
try{
double val = nf.parse(str).doubleValue();
System.out.println("NumberFormat.parse() gives: val="+val);
} catch (Exception e) {;}
Double Val = new Double(str);
System.out.println("Double.doubleValue(): val="+Val.doubleValue());

Answer 1

Thanks, but changing to DecimalFormat ...
import java.io.*;
import java.text.*;
public class jf2 {
   public static void main(String args[]) {
      String str = "1.456000E+05"; // 145600.00 in E format
      System.out.println("Original string: str="+str);
      DecimalFormat df = new DecimalFormat();
      try{
         double val = df.parse(str,(new ParsePosition(0))).doubleValue();
         System.out.println("DecimalFormat.parse() gives: val="+val);
      } catch (Exception e) {;}
      Double Val = new Double(str);
      System.out.println("Double.doubleValue(): val="+Val.doubleValue());
}Still gave:
Original string: str=1.456000E+05
DecimalFormat.parse() gives: val=1.456
Double.doubleValue(): val=145600.0Does this indicate a bug ? jre is 1.3.1