Object class....new a[ ]

Question

The following program is giving a compile error, because b[0] can't be accessed....i don't want to make it work by completely changeing it, but to understand what I should change to access that vector ....using "*Object b=a;*".....
public class test{
   public static void main(String args[]){
      int a[]={2,6};
     Object b=a;
   /* I've tryed:
       System.out.print(a+" "+b+" ");// they have the same adress
       System.out.print(b.getClass().getName());//console: *[I* .....so it is a vector,and it is int type
    System.out.print(b[0]+" ");
}So...the problem is that I don't understand what is wrong and I want to use the same idea....
It should write 2; I mean, if b is a vector of integers an is a pointer for a (have the same adress....)
I hope I've explain enough clear.
Thanks!

Answer 1

elena_mishu wrote:
The following program is giving a compile error, because b[0] can't be accessed....i don't want to make it work by completely changeing it, but to understand what I should change to access that vector ....using "*Object b=a;*".....
public class test{
public static void main(String args[]){
int a[]={2,6};
Object b=a;
/* I've tryed:
System.out.print(a+" "+b+" ");// they have the same adress
System.out.print(b.getClass().getName());//console: *[I* .....so it is a vector,and it is int type
System.out.print(b[0]+" ");
}So...the problem is that I don't understand what is wrong and I want to use the same idea....
It should write 2; I mean, if b is a vector of integers an is a pointer for a (have the same adress....)
I hope I've explain enough clear.
Thanks!What are you trying to accomplish? If you just want to print the array, you can use [java.util.Arrays.toString|http://java.sun.com/javase/6/docs/api/java/util/Arrays.html#toString(int[])], or, if that doesn't meet your need, write your own method that iterates over the array and prints the elements you want.
And yes, a and b have the same address. That's the way reference variable assignment works in Java. It never copies an object, just a reference, so that two references now point to the same object.