Odd string algorithm (string is for Runtime for linux/unix browser popup)

Question

I was given this code snippet from this forum in an attempt to popup a web brower in linux/unix operating systems. It doesn't work.
I have never seen the part of code in bold (the for loop) below, so I can't really make sense of it (the '?' and ':' are new operators to me). When I print the StringBuffer, I show some memory addresses, so I suspect the bold code to be the problem (perhaps needs to specify array indexes?).
If anyone can either decipher the bold code for me or offer a solution that would work, I would be very grateful.
Thanks!
static boolean showInBrowser(String url)
    String os = System.getProperty("os.name").toLowerCase();
    Runtime rt = Runtime.getRuntime();
    try
            if (os.indexOf( "nix") >=0 || os.indexOf( "nux") >=0)
              String[] browsers = {"epiphany", "firefox", "mozilla", "konqueror",
                  "netscape","opera","links","lynx"};
              StringBuffer cmd = new StringBuffer();
for (int i=0; i<browsers.length; i++)
cmd.append( (i==0 ? "" : " || " ) + browsers +" \"" + url + "\" ");
              rt.exec(new String[] { "sh", "-c", cmd.toString() });
              //System.out.println(cmd.toString());
           else
             return false;
    catch (IOException e)
        e.printStackTrace();
        return false;
    return true;
}

Answer 1

?: is like an if-else operator: i==0?foo:bar is
if(i==0) value_of_expression = foo else value_of_expression = bar.
You probably get memory addresses because in the loop "browsers" should really be browsers
Plain "browsers" just keeps giving you the memory address of the array (or if you want to get nitpicky the hash code which is not really the address.)