Only get Users that match all Links

Question

Seemingly a very simple problem, but I can't seem to figure it out.
Table below is a table that holds UserId' s and LinkId's.
CREATE TABLE UserLink (UserId NUMBER, LinkId NUMBER );
ALTER TABLE UserLink ADD PRIMARY KEY (UserId, LinkId);
INSERT INTO UserLink VALUES (1, 1);
INSERT INTO UserLink VALUES (1, 2);
INSERT INTO UserLink VALUES (3, 1);
INSERT INTO UserLink VALUES (4, 1);
I'm looking for a query in which I can plug a List of LinkId's that outputs only users that have a relationship with ALL LinkId's provided.
In this example you may assume that the List is equal to (1, 2), but you can't make any assumptions about the size of the list, other than size != 0.
The query to find users that match ANY of the provided LinkId's is quite simple:
SELECT UserId FROM UserLink
WHERE LinkId IN (1,2)
The correct query should output:
USERID
1
And it should work for any size > 0 list of values.

Answer 1

Here's one way:
with ID_LIST as (select 1 LINKID from DUAL union all select 2 from DUAL)
select distinct USERID from USERLINK a
where not exists (
                  select LINKID from ID_LIST
                  minus
                  select B.LINKID
                    from USERLINK B
                   where B.USERID=a.USERID                  
In 11g here is a different way using UNPIVOT to build the list of Link IDs.  This may be less cumbersome than a long UNION ALL list.
with ID_LIST as (select  1 a,2 b from DUAL)
select distinct USERID from USERLINK a
where not exists (
                  select LINKID from ID_LIST UNPIVOT (LINKID for COL in(a,b))
                  minus
                  select B.LINKID
                    from USERLINK B
                   where B.USERID=a.USERID