Open, Open Containing Folder in Windows Explorer Using java

How to open a file using the default application using java code?
Ex: - Open a JPG file using its default image viewer (Ex: Piscasa 3)..... (Not Inside the Java Application)
Then how to open a file containing folder with that file selected?
Couldn't find any sources in the internet, Not sure whether my search terms are correct....
Please Help
Thanks!!!

Madushan.UoM wrote:
Thanks Andrew...
I've did opening the file using
try {
Desktop desktop = null;
if (Desktop.isDesktopSupported()) {
desktop = Desktop.getDesktop();
desktop.open(new File(path));
} catch (IOException ioe) {
ioe.printStackTrace();
}Also able to open the directory by setting the "path" variable into the directory path
But how to highlight the needed file after the Explorer is opened???Also, to be completely safe, you'd want to call Desktop#open() only if isDesktopSupported() returns true, otherwise you'll get a NullPointerException.
if (Desktop.isSupported()) {
   try {
      Desktop.getDesktop().open(new File(path));
   } catch (IOException ioe) {
      ioe.printStackTrace();
}

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