Opera changes inside table border to white?

I am using a mac and when I preview my site in firefox and safari it looks great.
But when I preview in opera it changes the table with a collapsed 1px black border to white and leaves the outer border black.
Does anyone know why this is happening and how to fix it?
Thanks

Example code and screenshot, please! You may simply need to define an additional attribute. What you describe sounds very much like Opera is falsly using a 3D-line style instead of flat solid lines...
Mylenium

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How do I change an image border color to another color - Dreamweaver CS5?

Good day,
I have just learned how to add a border to an image with Dreamweaver CS5 within the Properties Inspector.
After typing the width in pixels in the Border Text Field and pressing the Enter key, Dreamweaver created a black border.
How do I change the image border color to another color?

I added your suggested rule to the Style Sheet "in any order" as you explained. See the image below.
However this did not change the image border from black to light blue. In fact, nothing changed.
Nothing changed because the CSS that has been written into DW is incorrectly written.
You want the following (exactly as written below)
img {border: 4px solid #0062C8;}
You've inadvertently wrapped the rule inside a #main_image container rendering it meaningless.
It's easiest to go into Code View and change
#main_image {
img {border: 4px solid #0062C8;
to
img { border: 4px solid #0062C8; }
The Property Inspector added a border exactly as I wanted it, other than the color I wanted the border to be. What is the use of this function in Property Inspector if it can add a border within Property Inspector but not let me change the COLOR of the black border that Property Inspector added, to another color?
That's a deceptively simple, yet valid, question with a long answer.
Back in the dark old days of web design web designers were restricted to inline HTML formatting which offered border properties but no colors.
CSS styling offers colors and more but has to be written differently.
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I just upgraded to DW CS5.5. and now when I try to use the same procedure, the Design View image gets scrambled after I paste the button code in code view. The table format is no longer in place, and I can no longer see where the cells of the table are. However, when I go to Live View, everything looks fine including the table and the buttons.
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<form target="paypal" action="https://www.paypal.com/cgi-bin/webscr" method="post">
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PLEASE can someone out there help me.
Many thanks.

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I find a bug using CheckBox inside table, this are steps to get the bug.
1.Create a view object from database table.
2.Create a where clause in view Object
3.Create a parameter form (using where clause)
4.Create a editable table with filter enable
-- AFTER TEST, ALL WORK
5. Convert inputText to af:selectBooleanCheckbox
-- AFTER TEST GET THIS ERROR:
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My attribute is not boolean but I fix it in viewRowImplementation accesor:
public String getProgramada() {
        String dbValue= (String) getAttributeInternal(PROGRAMADA);
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        else
            return "false";
public void setProgramada(String value) {
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        else
            valorSeleccionado = "N";
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SOLUTION:
1. Revert the viewRowImpl to default accesor.
2. Modify page definition in tis way using idea from Vinay Agarwal
<tree IterBinding="VSiriusCorreriasUsuView1Iterator" id="VSiriusCorreriasUsuView1">
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          <Item Value="Correria"/>
          <Item Value="Descripcion"/>
          <Item Value="Instleer"/>
          <Item Value="Descargadas"/>
          <Item Value="Ejecutadas"/>
          <Item Value="Codusuario"/>
          <Item Value="Codterminal"/>
          <Item Value="Placaveh"/>
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        <Item Value="N"/>
      </ValueList>
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My checkbox value is get from tree component:
<af:selectBooleanCheckbox value="#{row.bindings.Programada.inputValue}"
                                             shortDesc="#{bindings.VSiriusCorreriasUsuView1.hints.Programada.tooltip}"
                                             id="it7" label="#{bindings.Programada.label}" simple="true" autoSubmit="true">
</af:selectBooleanCheckbox>

Why does my IN operator change the datatype

Hi
This doesn't make any sense, but i'm hoping there's an obvious answer which you guys have seen a million times before.
I have this criteria in my WHERE clause
AND rpg_id = (SELECT rpg_id
                                         FROM integration.rep_elig_groups
                                        WHERE pel_id IN(34))because of this clause no results are return in my query. However if i use a to_number function like this:
AND rpg_id = to_number(SELECT rpg_id
                                         FROM integration.rep_elig_groups
                                        WHERE pel_id IN(34))OR
AND to_char(rpg_id) = (SELECT rpg_id
                                         FROM integration.rep_elig_groups
                                        WHERE pel_id IN(34))i get the expected results returned.
The sub query:-
SELECT rpg_id
                                         FROM integration.rep_elig_groups
                                        WHERE pel_id IN(34)returns the value 226. rpg_id in this table is a NUMBER datatype. As is rpg_id in the original outer query.
I looked at synonyms, views, and other objects it might be using for the rep_elig_groups table, but there are none.
Then i tried changing the IN operator for an EQUALS operator and would you believe it, it worked.
AND rpg_id = (SELECT rpg_id
                                         FROM integration.rep_elig_groups
                                        WHERE pel_id IN(34))can someone please explain what ORACLE is thinking here!!!
Many thanks
Edited by: tri_harder on Dec 9, 2008 4:48 PM missed the closing bracket in the final piece of code!
Edited by: tri_harder on Dec 10, 2008 8:44 AM

I ran the expain plans in TOAD for both queries, with the only difference changing the operator from IN to =. I'm very surprised there is such a difference between the two!!
SELECT   tim_id,
              rpg_id,
                             ROUND(SUM(retail_value), 2) retail_value,
                             ROUND(SUM(salesidx), 2) salesidx,
                             ROUND(SUM(VALUE), 2) VALUE,
                             ROUND(SUM(bva_salesidx), 2) bva_salesidx,
                             ROUND(SUM(bva_value), 2) bva_value,
                             ROUND(SUM(bva_retail_value), 2) bva_retail_value
                        FROM ms_stats_ol_ms
                       WHERE 1 = 1
                         AND fmt_id IN(SELECT ID
                                         FROM formats
                                        WHERE car_id = 0 OR 0 = 0)
                         AND fmt_id NOT IN(
                               SELECT fmt.ID
                                 FROM formats fmt,
                                      class_formats clf
                                WHERE fmt.ID = clf.fmt_id
                                  AND clf.cla_id IN(3, 6)
                                  AND fmt.car_id = 2)
                         AND cla_id = 3
                         AND rpg_id = (SELECT rpg_id
                                         FROM rep_elig_groups
                                        WHERE pel_id IN(34))
                         AND tim_id BETWEEN 4985 AND 5418
                    GROUP BY tim_id, rpg_idSo this is my original query that returned no results and produced the following Explain Plan:-
Plan
SELECT STATEMENT ALL_ROWSCost: 10,842 Bytes: 1,505 Cardinality: 35
     17 HASH GROUP BY Cost: 10,842 Bytes: 1,505 Cardinality: 35
          16 HASH JOIN Cost: 10,836 Bytes: 1,587,345 Cardinality: 36,915
               1 TABLE ACCESS FULL TABLE INTEGRATION.FORMATS Cost: 2 Bytes: 90 Cardinality: 15
               15 HASH JOIN RIGHT ANTI Cost: 10,833 Bytes: 1,456,912 Cardinality: 39,376
                    6 VIEW VIEW SYS.VW_NSO_1 Cost: 4 Bytes: 6 Cardinality: 2
                         5 HASH JOIN Cost: 4 Bytes: 24 Cardinality: 2
                              2 TABLE ACCESS FULL TABLE INTEGRATION.FORMATS Cost: 2 Bytes: 12 Cardinality: 2
                              4 INLIST ITERATOR
                                   3 INDEX RANGE SCAN INDEX (UNIQUE) INTEGRATION.CLF_PK Cost: 1 Bytes: 60 Cardinality: 10
                    14 TABLE ACCESS BY INDEX ROWID TABLE CHARTDEV.MS_STATS_OL_MS Cost: 10,829 Bytes: 1,530,034 Cardinality: 45,001
                         13 BITMAP CONVERSION TO ROWIDS
                              12 BITMAP AND
                                   8 BITMAP INDEX SINGLE VALUE INDEX (BITMAP) CHARTDEV.MSST_OL_MS_RPG_ID_I
                                        7 INDEX FAST FULL SCAN INDEX (UNIQUE) INTEGRATION.REG_PK Cost: 2 Bytes: 6 Cardinality: 1
                                   10 BITMAP MERGE
                                        9 BITMAP INDEX RANGE SCAN INDEX (BITMAP) CHARTDEV.MSST_OL_MS_TIM_ID_I
                                   11 BITMAP INDEX SINGLE VALUE INDEX (BITMAP) CHARTDEV.MSST_OL_MS_CLA_ID_I      The following script has the very small change of the operator changed from IN to =
SELECT   tim_id,
              rpg_id,
                             ROUND(SUM(retail_value), 2) retail_value,
                             ROUND(SUM(salesidx), 2) salesidx,
                             ROUND(SUM(VALUE), 2) VALUE,
                             ROUND(SUM(bva_salesidx), 2) bva_salesidx,
                             ROUND(SUM(bva_value), 2) bva_value,
                             ROUND(SUM(bva_retail_value), 2) bva_retail_value
                        FROM ms_stats_ol_ms
                       WHERE 1 = 1
                         AND fmt_id IN(SELECT ID
                                         FROM formats
                                        WHERE car_id = 0 OR 0 = 0)
                         AND fmt_id NOT IN(
                               SELECT fmt.ID
                                 FROM formats fmt,
                                      class_formats clf
                                WHERE fmt.ID = clf.fmt_id
                                  AND clf.cla_id IN(3, 6)
                                  AND fmt.car_id = 2)
                         AND cla_id = 3
                         AND rpg_id IN (SELECT rpg_id
                                         FROM rep_elig_groups
                                        WHERE pel_id IN(34))
                         AND tim_id BETWEEN 4985 AND 5418
                    GROUP BY tim_id, rpg_idAnd this returned the expected results and produced the following Explain plan:-
Plan
SELECT STATEMENT ALL_ROWSCost: 10,996 Bytes: 1,610 Cardinality: 35
     30 TEMP TABLE TRANSFORMATION
          10 LOAD AS SELECT SYS.SYS_TEMP_0FD9D6614_166B4444
               9 MERGE JOIN CARTESIAN Cost: 6 Bytes: 570 Cardinality: 30
                    5 VIEW VIEW SYS.VW_NSO_1 Cost: 4 Bytes: 26 Cardinality: 2
                         4 HASH JOIN Cost: 4 Bytes: 24 Cardinality: 2
                              1 TABLE ACCESS FULL TABLE INTEGRATION.FORMATS Cost: 2 Bytes: 12 Cardinality: 2
                              3 INLIST ITERATOR
                                   2 INDEX RANGE SCAN INDEX (UNIQUE) INTEGRATION.CLF_PK Cost: 1 Bytes: 60 Cardinality: 10
                    8 BUFFER SORT Cost: 6 Bytes: 90 Cardinality: 15
                         7 TABLE ACCESS BY INDEX ROWID TABLE INTEGRATION.FORMATS Cost: 1 Bytes: 90 Cardinality: 15
                              6 INDEX UNIQUE SCAN INDEX (UNIQUE) INTEGRATION.FMT_PK Cost: 0 Cardinality: 1
          29 HASH GROUP BY Cost: 10,990 Bytes: 1,610 Cardinality: 35
               28 HASH JOIN Cost: 10,989 Bytes: 4,600 Cardinality: 100
                    11 TABLE ACCESS FULL TABLE (TEMP) SYS.SYS_TEMP_0FD9D6614_166B4444 Cost: 2 Bytes: 180 Cardinality: 30
                    27 HASH JOIN RIGHT SEMI Cost: 10,987 Bytes: 34,280 Cardinality: 857
                         12 INDEX FAST FULL SCAN INDEX (UNIQUE) INTEGRATION.REG_PK Cost: 2 Bytes: 6 Cardinality: 1
                         26 TABLE ACCESS BY INDEX ROWID TABLE CHARTDEV.MS_STATS_OL_MS Cost: 10,984 Bytes: 1,310,574 Cardinality: 38,546
                              25 BITMAP CONVERSION TO ROWIDS
                                   24 BITMAP AND
                                        16 BITMAP MERGE
                                             15 BITMAP KEY ITERATION
                                                  13 INDEX FAST FULL SCAN INDEX (UNIQUE) INTEGRATION.REG_PK Cost: 2 Bytes: 6 Cardinality: 1
                                                  14 BITMAP INDEX RANGE SCAN INDEX (BITMAP) CHARTDEV.MSST_OL_MS_RPG_ID_I
                                        18 BITMAP MERGE
                                             17 BITMAP INDEX RANGE SCAN INDEX (BITMAP) CHARTDEV.MSST_OL_MS_TIM_ID_I
                                        22 BITMAP MERGE
                                             21 BITMAP KEY ITERATION
                                                  19 TABLE ACCESS FULL TABLE (TEMP) SYS.SYS_TEMP_0FD9D6614_166B4444 Cost: 2 Bytes: 13 Cardinality: 1
                                                  20 BITMAP INDEX RANGE SCAN INDEX (BITMAP) CHARTDEV.MSST_OL_MS_FMT_ID_I
                                        23 BITMAP INDEX SINGLE VALUE INDEX (BITMAP) CHARTDEV.MSST_OL_MS_CLA_ID_I           Can anybody suggest what's going on?? Why do i get results with one and not the other!!
Edited by: tri_harder on Dec 10, 2008 10:00 AM
altered the first query to change the IN operator to =

CSS issue when changing the table row height to 16px

Hello,
After changing the table row height through css like this:
.table-row-cell, .table-cell {
-fx-cell-size: 16;
the table rows are correctly displayed with a 16px height but the cell bottoms seem to be incorrectly set.
For example the following css style (a red 3px bottom border):
.table-cell {
-fx-border-width: 0 0 3 0;
-fx-border-color: red;
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www.alt-web.com/
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Getting Compilation error when used SET or MULTISET operator on nested tabl

Dear All,
I am getting Compilation error when used SET or MULTISET operator on nested tables inside a procedure.
This is working fine in other DB installations of 10g but does not work in another 10g DB.
it says "wrong number of parameter or datatype used in SET"
Can any one suggest what went wrong here?
Thanks in advance.

Can any one suggest what went wrong here?Only if you would post the query and Oracle versions on both databases.
Besides, this forum deals with issues in Oracle product installation. So post this query in SQL PL/SQL forum for better response.

Compilation error when used SET or MULTISET operator on nested tables

Dear All,
I am getting Compilation error when used SET or MULTISET operator on nested tables inside a procedure.
This is working fine in other DB installations of 10g but does not work in another 10g DB.
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Can any one suggest what went wrong here?
Thanks in advance.

Hi,
Thanks for ur reply...
Since MULTISET and SET operators are the new additions in base 10g release for manipulation of nested tables data, I am surprised that same is working in similar 5 DBs installations with 10.2.0.1.0 version, but does not work in the sixth.
SET and MULTISET operators are used inside the PL/SQL procedure which is getting compiled in the above mentioned 5 DBs but not in sixth DB.
it gives
On line: 3112
PLS-00306: wrong number or types of arguments in call to 'SET'
Hope this clarifies the issue...

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le chin wrote:
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The color in the Inspector is for the table background, not the border.
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Hi,
I try to use the JEditorPane to view the html file. Everythings work fine except
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<tr><td><img src="http://somewhere/b.jpg"></td></tr>
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[image]
[image]
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Controlling spry menu inside table

My code is below. I am trying to insert spry menu bar inside table but for some reason the
bar does not move with the table.
<body>
<table width="741" height="800" border="0" align="center">
<tr>
<td width="738" height="100" align="left"><table width="750" height="64" border="0">
    <tr>
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<ul id="MenuBar1" class="MenuBarHorizontal">
<li><a href="#">Item 1</a>          </li>
<li><a href="#">Item 2</a></li>
<li><a href="#">Item 3</a>          </li>
<li><a href="#">Item 4</a></li>
</ul>
</td>
</tr>
</table></td>

le chin wrote:
My code is below. I am trying to insert spry menu bar inside table but for some reason the
bar does not move with the table.
<body>
<table width="741" height="800" border="0" align="center">
<tr>
<td width="738" height="100" align="left"><table width="750" height="64" border="0">
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      <td>
<ul id="MenuBar1" class="MenuBarHorizontal">
<li><a href="#">Item 1</a>          </li>
<li><a href="#">Item 2</a></li>
<li><a href="#">Item 3</a>          </li>
<li><a href="#">Item 4</a></li>
</ul>
</td>
</tr>
</table></td>
Why nested tables? What are you try to do? Centre the menu or have it aligned to the left?
Steve

Table Border not Showing

Hi there - for some reason a page on my site is not
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testomonials one-by-one from the bottom up hoping I could learn
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Click here
to see that page

Hi Jon,
Would you try changing the padding in your Tableborder CSS
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padding: 23px;
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I discovered removing the <em> tag fixed it. Not a good
solution.
I tried to use CSS instead of the <em> tag, same
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I put the <em> tag back in and experimented some more
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"Jon G" <[email protected]> wrote in message
news:[email protected]...
> Hi there - for some reason a page on my site is not
displaying the right
> table
> border. All the other pages are working fine. When I
delete all of the
> testimonials (the content for the page in question),
then the border
> shows. I
> deleted the testomonials one-by-one from the bottom up
hoping I could
> learn
> which testimonials has the issue. There must be a
character that is
> throwing
> it off. Any help would be appreciated.
>
> Jon
>
>
http://www.avenuebdesign.com/rtc/testimonials.htm
>

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Thanks,
Hallie

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Opera changes inside table border to white?

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