Oracle search string help required

select  'NOT(C 4KF70_MOT=IN ''M9R A'',''M9R B'')'
from dualthe output is "NOT(C4KF70_MOT     =IN 'M9R A','M9R B'     )"
condition is IF THERE IS A WORD LIKE KF70 in the string then search shoud go backwards to find the word NOT (. if it is there then my query should return only M9R A AND M9R B (ie) the words inside the quotes.
Pls help
the output should be 'M9R A','M9R B'

HAI
ur analysis is good. but for me still more functinality required.
WITH t AS
(SELECT '  NOT ( MOT IN  ''BRK'' ) AND  (C 4 KF70_MOT=IN ''M9R A'',''M9R B'')' c1 FROM dual UNION ALL
SELECT 'NOT(C     4     KF70_MOT= IN      ''M9R A'',''M9R B'')' c1 FROM dual UNION ALL
SELECT 'NOT(C 4KxxF70_MOT=IN ''M9R A'',''M9R B'')' c1 FROM dual)
SELECT REGEXP_SUBSTR(c1, '''.*''')
FROM   t
WHERE  REGEXP_LIKE(c1, 'NOT.*KF70_MOT')output is
'BRK' ) AND  (C 4 KF70_MOT=IN 'M9R A','M9R B'
'M9R A','M9R B'it should not be like this because
NOT should be present only before the first occurance of KF70 that is before bracket '(' example is second condition.
Pls help
S

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