Order by -- complex sorting?
Hello:
How can one accomplish the following:
Let's say I have the following scenario:
Select value2 from table2 IF this value exists. Else, select value 1 from table1. --
Then: I would like to ORDER BY all of the above results (sometimes the value may be value1, other times vaule2, etc). How can one do such an ORDER BY? Is this even possible via a query?
Hi,
In most cases, you can use functions and CASE expressions (or more specialized if-then-else expressions, like COALESCE) to sort things the way you want.
For example, if you want to pass a parameter, :p_sort_key, a VARCHAR2 that tells if you want to sort by value1, value2or value3, then you can do this:
ORDER BY CASE :p_sort_key
WHEN 'V1' THEN value1
WHEN 'V2' THEN value2
WHEN 'V3' THEN value3
ENDThis assumes value1, value2 and value3 all hafve the same datatype. If not, use TO_CHAR or some other conversion function on one or more of them.
Now say we want to sort by table2.value4 if it is present, and otherwise by the expression above.
Depending on your exact requirements, you could say
ORDER BY table2.value4 NULLS LAST
, CASE :p_sort_key
WHEN 'V1' THEN value1
WHEN 'V2' THEN value2
WHEN 'V3' THEN value3
ENDThis will sort by table2.value4, and then, as a tie-breaker, by the other value. (NULLS LAST is the default, so you don't have to say explicitly say it, but you can for clarity's sake.)
if you really want the second expression only to have effect when table2.value2 is NULL, then you could use a NVL statement, or incorporate value4 into the CASE:
ORDER BY CASE
WHEN table2.value4 IS NOT NULL
THEN table2.value4
WHEN :p_sort_key = 'V1' THEN value1
WHEN :p_sort_key = 'V2' THEN value2
WHEN :p_sort_key = 'V3' THEN value3
ENDIf all else fails, there's always dynamic SQL.
In SQL*Plus, for example, you could run a preliminary query that produces a sting like
SUBSTR (value1, 1, 2),
value3,
TRUNC (entry_date, 'YYYY') and sets the substitution variable &order_txt to that value.
Then, in your main query, you say:
ORDER BY &order_txt
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Hi!
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Here's a solution if you don't want to rename all the tracks with s single artist (if there is more than one):
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Message was edited by: tyPod18
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Performance - using JDBC call with 'order by' vs sorting data on app server
Hello! I need some valid thoughts on the performance of using a JDBC call versus processing information on the application server.
Here is the somewhat simplified scenario:
I need to retrieve customer information (name, e-mail, telephone), display it in HTML format and then be able to redisplay it in a different order. For example, initially the list would be displayed sorted by last name, but then a user might choose to sort it by e-mail address. Initial call to DB uses 'order by' in the SQL stmt to get me the initial ordering by last name. Results are stored in 2D array. However, when a user selects a different sort I have two options:
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import java.io.*;
import java.math.*;
import java.util.*;
import java.util.Arrays.*;
public class Test {
public static void main(String[] args) throws Exception {
Test test = new Test();
test.testSortingPerformance();
public void testSortingPerformance() {
Object[] objArray2 = new Object[]{};
Vector v = new Vector();
Date start, end;
java.util.Random rd = new java.util.Random(2000);
for (int i = 0; i < 2000; i++){
v.add(new Object[]{new String("" + rd.nextInt())});
v.add(new Object[]{null});
objArray2 = v.toArray();
Object[] innerObjArray2 = new Object[]{};
MyComparator2 myComp = new MyComparator2();
start = new Date();
java.util.Arrays.sort(objArray2, myComp);
end = new Date();
for (int i = 0; i < objArray2.length; i++) {
System.out.println();
innerObjArray2 = (Object[])objArray2;
for (int j = 0; j < innerObjArray2.length; j++) {
System.out.print(innerObjArray2[j] + " ");
System.out.println(v.size());
System.out.println("Start " + start + " End " + end);
import java.util.*;
public class MyComparator2
implements Comparator {
//position in the inner array to use for comparison
private int position = 0;
//default empty constructor
public MyComparator2() {
//implement compare method
public int compare(Object o1, Object o2) {
Object[] strAr1 = (Object[]) o1;
Object[] strAr2 = (Object[]) o2;
if (strAr1[0] == null){
if (strAr2[0] == null){
return 0;
else{
return -1;
else if (strAr2[0] == null){
return 1;
return ( (String) strAr1[0]).compareTo( (String) strAr2[0]); -
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thanks
SELECT p.nkisi_uygulama_id, p.nvardiya_id,
p.dbaslangic_tarih AS dper_vardiya_bas_tarih,
p.dbitis_tarih AS dper_vardiya_bit_tarih, p.nper_vardiya_id,
v.nvad AS nvvardiya_ad, v.nvaciklama, v.nvbaslama_saat,
v.ntoplam_saat, TO_CHAR (d.tarih, 'DAY') AS nvgun,
TO_DATE (d.tarih || ' ' || v.nvbaslama_saat,
'DD.MM.YYYY HH24:MI'
) AS dbaslangic_zaman,
TO_DATE (d.tarih || ' ' || v.nvbitis_saat,
'DD.MM.YYYY HH24:MI'
+ CASE
WHEN TO_DATE (d.tarih || ' ' || v.nvbitis_saat,
'DD.MM.YYYY HH24:MI'
) <
TO_DATE (d.tarih || ' ' || v.nvbaslama_saat,
'DD.MM.YYYY HH24:MI'
THEN 1
ELSE 0
END AS dbitis_zaman,
(SELECT bvardiya_izin
FROM iky_tnm_vardiya_gun vi
WHERE vi.nvardiya_id = v.nvardiya_id
AND TO_CHAR (d.tarih, 'D') =
CASE
WHEN vi.ntip_gun_id = 781
THEN 1
WHEN vi.ntip_gun_id = 782
THEN 2
WHEN vi.ntip_gun_id = 783
THEN 3
WHEN vi.ntip_gun_id = 784
THEN 4
WHEN vi.ntip_gun_id = 785
THEN 5
WHEN vi.ntip_gun_id = 786
THEN 6
WHEN vi.ntip_gun_id = 787
THEN 7
END) AS bvardiya_izin
FROM iky_tnm_vardiya v,
iky_hrk_per_vardiya p,
TABLE (pck_iky_func.f_tbl_per_vardiya_zaman ()) d
WHERE p.nvardiya_id = v.nvardiya_id
AND d.ID = p.nper_vardiya_id
AND p.nvardiya_id IS NOT NULL
AND TO_CHAR (d.tarih, 'D') IN (
SELECT CASE
WHEN g1.ntip_gun_id = 781
THEN 1
WHEN g1.ntip_gun_id = 782
THEN 2
WHEN g1.ntip_gun_id = 783
THEN 3
WHEN g1.ntip_gun_id = 784
THEN 4
WHEN g1.ntip_gun_id = 785
THEN 5
WHEN g1.ntip_gun_id = 786
THEN 6
WHEN g1.ntip_gun_id = 787
THEN 7
END
FROM iky_tnm_vardiya_gun g1
WHERE
v.nvardiya_id = g1.nvardiya_id)
ORDER BY nkisi_uygulama_id;Listen to Billy & Centinul. You'll need to figure out why the query is really slow, and the notes on tuning should help.
Looking at your query: the sorting won't help performance. Make sure it is not sorting to disk (you can use AUTOTRACE in SQL*PLUS or SQL*DEVELOPER for this).
Select list inline views are notorious for a couple of reasons. First, they can decrease performance by executing for every row. Second, under just the wrong conditions their actvity will not show up in execution plans - I just rewrote one as a insert/select from in 10gR2 to PL/SQL and the original execution plan only showed the insert with a cost of 2 (!); this is standard behavior on 9i (in my case I was able to consolidate multiple queries with a possible 50% per-line run time according to dbms_profiler).
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Sample movie order:
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Slideshow - Order of Images - Sorting
The only sorting optons for collections and playing a slideshow are:
Capture time
Import order
Edit time
Edit count
Rating
Pick
Color Label
File Name
File Extension
File Type
Aspect ratio
User order
Through a combination of ratings and color labels, I have trimmed 2400 photos to about 500. For the most part, I want the photos arranged in the order of the capture time. But for wide and closeup shots of the same scene, I want the wide shots to appear first in the slideshow, followed by the related close-up shots. At this point, and given the large number of photos for the slide show, the only alternative above that allows for rearranging the order is "User order".
I don't see where the user specifies the input field or metadata for "user order." I thought it may be related to the order the user clicks images into the collection, but this is not the case.
It appears there is no way to drag and drop or insert images using a mouse to rearrange the order. That would be ideal and consistent with the visual design of Lightroom.
Can anyone help with rearranging the order? I don't want to edit the image capture time solely to rearrange a slideshow. This would be very cumbersome.
Kent
San franciscoAfter more testing with a smaller sample, the user order is the sequence the photos were added to the collection. When I first experimented with this, the user order of my test sample was the same as image capture time because I did a massive import to the collection (rather than photo by photo). When I was expecting a different sort order for image capture vs user order, I did not realize the sort order in my particular situation would be identical.
So the work-around to specify a precise order is to first select and edit all of the photos for inclusion or exclusion from the slideshow. Then add the draft slide show picks into a second collection one by one in the exact order desired in the final slideshow. For sorting the final collection, select the last option - User select.
There should be an easier way to accomplish this task. With 500 photos to arrange in order, it would be easy to make a mistake and miss a photo or put one in the wrong place. Perhaps you could change the color code after adding a photo to a collection to help in keeping track of the rearranging / sorting. This adds time to the already slow and tedious process.
Any other ideas?
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San Francisco -
Paul McCartney Pre-Order Problem with Sorting
I pre-ordered the new McCartney album last week (at which point it downloaded the "Ever Present Past" single) and when it became available today I downloaded the rest fine, except "Ever Present Past" (which should be song number 2) had a different album title ("Ever Present Past Single" or something like that) and thus didn't sort correctly with the rest of the album... so I edited the track to match the same album name and correct track number (being very careful to make sure that all of the fields in the Get Info window match the other tracks, and that there are no invisible spaces throwing it off), but it refuses to sort with the rest of the album... even tried to rebuild the iTunes Library file but that didn't work either... just curious if anyone else has a similar problem and/or a possible solution. Thanks.
This is ridiculous that this issue isn't being
> addressed. Same problem here, and I guarantee that
> I'm not alone.
Check out the emails I got from Apple on this:
"I understand that the single " Memory Almost Full" from the album you pre-ordered, will did not download with the album and now you're unable to listen to the album without it stopping to get to the single. Please note that re-downloading the album, will not resolve this issue. You are correct when you mentioned that this issue will happen because iTunes sees it as two different albums because it was downloaded separately. Don't worry. To resolve this issue, I recommend creating a playlist for the album itself. That way, you can arrange the contents of the album so that they will play without interruption.
This article will show you how to do this:
Organizing your music and video using playlists
http://docs.info.apple.com/article.html?path=iTunesWin/7.0/en/517win.html
I hope you continue to enjoy using the iTunes Store."
Well, that's great...so not only do I have to isolate the album from the rest of my iTunes collection, it also does nothing to fix the issue on my iPod. So I responded to them as such, and got this response:
"You did mention very valid points when stating your disappointment with the way pre-ordered albums are downloaded and Apple recognizes that no one is better qualified to provide feedback about iTunes than the people who use it.
I encourage you to use the iTunes Feedback page to submit your comments:
http://www.apple.com/feedback/itunesapp.html
Your efforts to share your feedback are very much appreciated.
I hope you continue to enjoy using the iTunes Store.
Is this ridicuous or what? Unbelievable. If I bought a CD in a store and the tracks were incorrectly burned on the CD, the store would take it back or at least try to exchange it for a new copy that wasnt defective. This TECHNICAL ISSUE needs to be resolved.
iMac 17" 1.83 GHz Intel, iBook G4 12.1" Mac OS X (10.4.6)
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