Order rows on the basis of score

Question

I have a table like this format:
ID
COL1
COL2
1
i am a boy
good is male
2
i am a good boy
good is male
3
i am a good girl
gender is female
Now the user will enter a keyword (in this example, 'good'). Based on that, if the keyword is found in column1, score will be given 2, and if the keyword is found in column2, score will be given 5.
And at the end, I have to display the ID column based on the score (max score at the top).
So the results should come like this:
ID
SCORE
2
5
1
7
3
2
How can I do?

Answer 1

For example like this
with sample_table as (
                       select 1 id,'i am a boy' col1,'good is male' col2 from dual union all
                       select 2,'i am a good boy','good is male' from dual union all
                       select 3,'i am a good girl','gender is female' from dual union all
                       select 4,'goodie girl','gender is female' from dual union all
                       select 5,'good girl','gender is female good' from dual
select  id,
CASE WHEN
         case
           when regexp_like(col1, '(^| )' || :keyword || '( |$)') then 2
           else 0
        end +
        case
          when regexp_like(col2, '(^| )' || :keyword || '( |$)') then 5
          else 0
        end  = 0
THEN 10
ELSE
         case
           when regexp_like(col1, '(^| )' || :keyword || '( |$)') then 2
           else 0
        end +
        case
          when regexp_like(col2, '(^| )' || :keyword || '( |$)') then 5
          else 0
        end
END score
  from  sample_table
  order by score desc