Overloading Issue

Question

If overloaded functions like below are defined
     void move(double dx) { System.out.println("double"); }
     void move(Object dx) { System.out.println("Object"); }
     void move(String dx) { System.out.println("String"); }Invoking them as
          move(new String(""));
          move(new Object());
          move(null);
Results in
String
Object
String
How does the compiler decide to call the String version of move when null is passed ?

Answer 1

How does the compiler decide to call the String version of move when null is passed ?It matches the most specialized, and String is a subclass of Object. However, if you were to add another method with a signature such as Integer, the compile would refuse to compile. String and Integer do not share the same inheritance hierarchy.