Page Table Owner

Question

Hello everybody,
I made the following query to get table and column names handled by a application/page:
select APEX_APPLICATION_PAGE_DB_ITEMS.ITEM_NAME,
APEX_APPLICATION_PAGE_DB_ITEMS.DB_TABLE_NAME,
APEX_APPLICATION_PAGE_DB_ITEMS.DB_COLUMN_NAME,
APEX_APPLICATION_PAGE_ITEMS.FORMAT_MASK
from APEX_APPLICATION_PAGE_DB_ITEMS,
APEX_APPLICATION_PAGE_ITEMS
where APEX_APPLICATION_PAGE_DB_ITEMS.APPLICATION_ID = APEX_APPLICATION_PAGE_ITEMS.APPLICATION_ID
and APEX_APPLICATION_PAGE_DB_ITEMS.PAGE_ID = APEX_APPLICATION_PAGE_ITEMS.PAGE_ID
and APEX_APPLICATION_PAGE_DB_ITEMS.ITEM_ID = APEX_APPLICATION_PAGE_ITEMS.ITEM_ID
and APEX_APPLICATION_PAGE_DB_ITEMS.APPLICATION_ID = 37891
and APEX_APPLICATION_PAGE_DB_ITEMS.PAGE_ID = 55
How can I improve it to get DB table owner?
Thanks,

Answer 1

P - The table owner isn't exposed by that view (APEX_APPLICATION_PAGE_DB_ITEMS), but you could change it to pull out what you want and compile the new view in the Application Express product schema. This wouldn't hurt anything but it wouldn't be supported, of course.
The change would be where you see, in the current view source:       r := dbms_lob.substr(c1.process_sql_clob,255,1);Change that to:       l_owner := replace(substr(r,1,instr(r,':')-1),'F|',null);     
       r := dbms_lob.substr(c1.process_sql_clob,255,1);...along with adding a declaration for l_owner. Then you'll need to replace #OWNER# with the f.owner value.
Scott