Palm Desk Top 6.2 Address Look Up Function Does Not Work In Windows 7

Question

I recently upgraded my desk top computer's operating system from Windows Vista Home Premium to Windows 7 Home Premium.  I synchronize with a Palm Tx PDA.  HP PalmOS customer support Chat helped me work through a compatibility issue that was preventing display of Address, Calendar, Memo and To Do items on my desk top computer via the Palm Desk Top 6.2 application.  I now find that the address look up function does not work (although it worked fine when I was running Vista).  Without success, I tried running the repair tool as well as reloading the software (both overlay and clean reinstall).  I would appreciate any help or suggestions to fix?
Post relates to: Palm TX

Answer 1

Hi,
844869 wrote:
CREATE TABLE TEST_EMPLOYEES
FIRST_NAME VARCHAR2(26 CHAR),
GRADE VARCHAR2(5 CHAR)
INSERT INTO TEST_EMPLOYEES (FIRST_NAME, GRADE) VALUES ( 'William', 45 ); ...Thanks for posting the CREATE TABLE and INSERT statements; that's very helpful.
William&45     1
Robin 43     1
Raymond          43     1
Richard          43     1
Karen          28     1
Michelle               1
Jonathan               1
Mark               1
Ann               1You may have noticed that this site normally doesn't display multiple spaces in a row.
Whenever you post formatted text (such as query results) on this site, type these 6 characters:
\(small letters only, inside curly brackets) before and after each section of formatted text, to preserve spacing.
This is one of the many helpful things found in the forum FAQ {message:id=9360002}
Are the results above what you're getting with some existing query, or are they the results you want? 
If those are your current results, post your query.  In that case, what are the results you want?  Do you want this?FIRST_NAME GRADE RNK
William 45 1
Robin 43 2
Raymond 43 2
Richard 43 2
Karen 28 5
Michelle 6
Jonathan 6
Mark 6
Ann 6
Edited by: Frank Kulash on Feb 21, 2013 2:39 PM
I see you've added the desired results to your original message.
Here's one way to do that:SELECT first_name
,     grade
,     RANK () OVER (ORDER BY grade NULLS FIRST)     AS rnk
FROM     test_employees
ORDER BY grade          DESC     NULLS LAST