Parent partition of subpartitions that move to a new TS

PLATFORM_NAME: Solaris[tm] OE (64-bit)
VERSION: 11.2.0.2.0
In our system we have several tables that are partitioned by range. Some of these tables are then sub-partitioned by list. Well initially we were creating a new tablespace every month and creating the new monthly partition on the new tablespace. Well I got annoyed by this, so I decided to move all of the partitions/subpartitions to a single tablespace. And this went smooth, at first, in my dev region. I moved all of the segments to the new tablespace, but then I noticed something odd...
Example:
CREATE TABLE me.sub_partitioned_table
my_range_partitioned_column date,
my_list_partitioned_column varchar2(30)
PARTITION BY RANGE (my_range_partitioned_column)
SUBPARTITION BY LIST (my_list_partitioned_column)
SUBPARTITION TEMPLATE
(SUBPARTITION value4 VALUES (4),
SUBPARTITION value23 VALUES (23),
SUBPARTITION value60 VALUES (60),
SUBPARTITION "DEFAULT" VALUES (DEFAULT)
PARTITION P_HIST VALUES LESS THAN (TO_DATE(' 2007-09-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN'))
TABLESPACE P_HIST
( SUBPARTITION P_HIST_value4 VALUES (4) TABLESPACE MONTHLY_PARTITION,
SUBPARTITION P_HIST_value23 VALUES (23) TABLESPACE MONTHLY_PARTITION,
SUBPARTITION P_HIST_value60 VALUES (60) TABLESPACE MONTHLY_PARTITION,
SUBPARTITION P_HIST_DEFAULT VALUES (DEFAULT) TABLESPACE MONTHLY_PARTITION ),
...... and there are a lot more partitions/subpartitions
So I create all of my alter table move subpartition statements, and the execute as they should. If I do:
select tablespace_name from dba_tab_subpartitions where table_name = 'SUB_PARTITIONED_TABLE' and table_owner = 'ME', I see that all of my subpartitions are on the new, single tablespace. BUUUUUUT, if I do:
select tablespace_name from dba_tab_partitions where table_name = 'SUB_PARTITIONED_TABLE' and table_owner = 'ME', I see all of the old tablespace names are still listed for my partitions.
My question is, can this be changed? Did I screw something up? Is this a bug? If I try to alter the table and move the partition I get an error because I'm trying to move something that isn't a segment. Any help would be appreciated. Hopefully this makes sense. If you need clarification on anything, please let me know.
Thanks!

I found my answer...
ALTER TABLE ME.sub_partitioned_table MODIFY DEFAULT ATTRIBUTES FOR PARTITION MONTHLY_PARTITION TABLESPACE NEW_BIG_TS;

Similar Messages

Where did the Partitions and SubPartitions go?

I created a table with partition Range (Transaction_Date, Retention_Period) and hash (Record_Id) subpartition template (for 32 subpartitions)
Then I add more partitions and while the loop is going on I can get counts of partitions and subpartitions. The job finished and my log table shows about 1800 partitions added and there should be 32 subpartitions for each of the partitions. However, user_tab_partitions shows zero records for the table, and user_tab_subpartitions also show zero record. After a few minutes the partitions show up but no subpartitions. The indexes on the table have also disappeared (one local and one global)
Any explanation for this behaviour?
Working on Exadata 11.2.0.3
Querying
USER_TABLES
USER_TAB_PARTITIONS
USER_TAB_SUBPARTITIONS
USER_INDEXES

>
Step 1. Create Table xyz (c1 date, c2 integer c3 integer, etc)
partition by range (c1,c2)
subpartition template (s01, s02... s32)
create index i1 on xyz (c1,c2,c3) local;
Then, since I want to create about 1800 partitions I have a procedure that has a "loop around" ALTER TABLE add Partition .. until all the partitions are created. This is the "Job" which while running I query USER_TAB_PARTITIONS and USER_TAB_SUBPARTITIONS to see how things are progressing. And Yes ALTER Table has no progressing to verify.
So al the partitions get created. No errors from the procedure to go through creating all the partitions. So I would expect that at the end I should get to see all the new partitions for the Table. Instead I get "no records" from USER_TAB_PARTITIONS and USER_TAB_SUBPARTITIONS.
I am also aware that "ALTER TABLE ADD PARTITION .." cannot make indexes go away. However, if the query on USER_INDEXES returns nothing, what happend to the Index created before the partitions were added?
I am not using DBMS_REDEFINITION. The only procedure is to add partitions one at a time for each date for 3 years. If you have a better way than a procedure please advise accordingly.
>
In order to help you the first step is to understand what problem you are dealing with. Then comes trying to determine what options are available for addressing the problem. There are too many times , and yours may, or may not, be another one, where people seem to have settled on a solution before they have really identified the problem.
Anytime someone mentions the use of dynamic SQL it raises a red flag. And when that use is for DDL, rather than DMl, it raises a REALLY BIG red flag.
Schema objects need to be managed properly and the DDL that creates them needs to be properly written and kept in some sort of version control.
Scripts and procedures that use dynamic SQL are more properly used to create DDL, not to execute it. That is, rather than use a procedure to dynamically create or alter a table you would use the procedure to dynamically create a DDL script that would create or alter the table.
Let's assume that you know for certain that your table really needs to have 1800 partitions, be subpartitioned the way you say and have partition and subpartitions names that you assign. Well, that would be a pain to hand-write 1800 partition definitions.
So you would create a procedure that would produce a CREATE TABLE script that had the proper clauses and syntax to specify those 1800 partitions. Your 'loop' would not EXECUTE an ALTER TABLE for each partition but would create the partition specification and modify the partition boundaries for each iteration through the loop. Sort of like
for i from 1 to 365 loop
add partition spec for startDate + i
end loop;The number of iterations would be a parameter and you would start with 2 or 3. Always test with the smallest code that will produce the correct results. If the code works for 3 days it will work for any larger reasonable number.
Then you would save that script in your version control system and run it to create the table. There would be nothing to monitor since there is just one script and when it is done it is done.
That would be a proper use of dynamic sql: to produce DDL, not to execute it.
Back to your issue. If I were your manager then based on what you posted I would expect you to already have
1. a requirements document that stated the problem (e.g. performance, data management) that was being addressed
2. test results that showed that your proposed solution (a table partitioned the way you posted) solves the problem
The requirements doc would have detail about what the performance/management issues are and what impact they are having
You also need to document what the possible solutions are, the relative merits of each solution and the factors you considered when ranking the solutions. That is, why is your particular partitioning scheme the best solution for the problem.
You should have test results that show the execution plans and performance you achieved by using a test version of your proposed table and indexes.
Until you have 'proven' that your solution will work as you expect I wouldn't recommend implementing the full-blown version of it.
1. Create a table MANUALLY that has 2 or three days worth of partitions.
2. Load those partitions with a representative amount of data
3. Execute test queries to query data from one of those partitions
4. Execute the same test queries against your current table
5. Capture the execution plans (the actual ones) for those queries. Verify that you are getting the performance improvements that you expected.
Once ALL of that prep work is done and you have concluded that your table/index design is correct then go back to work on writing a script/procedure that will produce (not execute) DDL to produce the main table and partitioning you designed.
Just an aside on what you posted. The indexes should be created AFTER the table and its partitions are created. If you are creating your local index first, as you post suggests, you are forcing Oracle to revamp it 1800 times when each partition is added. Just create the index after the table.
p.s. the number of posts anyone has is irrevelant. The only thing that matters is whether the advice or suggestions they provide is helpful. And the helpfullness of those is limited to, and based on, ONLY the information a poster provides. For exampe, your proposed partitioning scheme might be perfectly appropriate for your use case or it could be totally inappropriate. We have no way of knowing without knowing WHY you chose that scheme.
But I haven't seen one like that so it makes me suspicious that you really need to get that complicated.

Using PARTITION FOR/SUBPARTITION FOR syntax to insert

We are trying to use PARTITION FOR syntax (or, better, SUBPARTITION FOR syntax) to insert into a subpartitioned table.
http://docs.oracle.com/cd/E11882_01/server.112/e26088/sql_elements009.htm#i165979
08:26:46 GM_CS_CDR@oradev02> select * from v$version;
BANNER
Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production
PL/SQL Release 11.2.0.3.0 - Production
CORE    11.2.0.3.0      Production
TNS for Solaris: Version 11.2.0.3.0 - Production
NLSRTL Version 11.2.0.3.0 - Production
5 rows selected.This table is has interval partitions on DATA_ORIGIN_ID and list subpartitions on TABLE_NAME.
First, a basic insert without specifying partitions:
08:10:05 GM_CS_CDR@oradev02> insert into key_ids2 (
08:11:51   2 DATA_ORIGIN_ID         ,
08:11:51   3 TABLE_NAME             ,
08:11:51   4 DUR_UK                 ,
08:11:51   5 DUR_UK_ID              )
08:11:51   6 select
08:11:51   7 12         ,
08:11:51   8 TABLE_NAME             ,
08:11:51   9 DUR_UK                 ,
08:11:51 10 DUR_UK_ID
08:11:51 11 from key_ids where table_name = 'PART'
08:11:51 12 and rownum <= 10;
10 rows created.Verifying SUBPARTITION FOR syntax on a SELECT:
08:19:43 GM_CS_CDR@oradev02>
08:26:45 GM_CS_CDR@oradev02>
08:26:45 GM_CS_CDR@oradev02>
08:26:45 GM_CS_CDR@oradev02>
08:26:45 GM_CS_CDR@oradev02> select count(*) from key_ids2
08:26:45   2 subpartition for(12,'PART');
COUNT(*)
        10
1 row selected.But when we add a subpartition specification (to limit the lock to a single subpartition), we get a syntax error:
08:14:57 GM_CS_CDR@oradev02> insert into key_ids2 subpartition for(12,'PART') (
08:14:57   2 DATA_ORIGIN_ID         ,
08:14:57   3 TABLE_NAME             ,
08:14:57   4 DUR_UK                 ,
08:14:57   5 DUR_UK_ID              )
08:14:57   6 select
08:14:57   7 14         ,
08:14:57   8 TABLE_NAME             ,
08:14:57   9 DUR_UK||'!'                 ,
08:14:57 10 DUR_UK_ID
08:14:57 11 from key_ids
08:14:57 12 where table_name = 'PART'
08:14:57 13 and rownum <= 10;
insert into key_ids2 subpartition for(12,'PART') (
ERROR at line 1:
ORA-14173: illegal subpartition-extended table name syntaxSpecifying at the partition level did not work either:
08:14:58 GM_CS_CDR@oradev02> insert into key_ids2 partition for(14) (
08:15:23   2 DATA_ORIGIN_ID         ,
08:15:23   3 TABLE_NAME             ,
08:15:23   4 DUR_UK                 ,
08:15:23   5 DUR_UK_ID              )
08:15:23   6 select
08:15:23   7 14         ,
08:15:23   8 TABLE_NAME             ,
08:15:23   9 DUR_UK||'!'                 ,
08:15:23 10 DUR_UK_ID
08:15:23 11 from key_ids
08:15:23 12 where table_name = 'PART'
08:15:23 13 and rownum <= 10;
insert into key_ids2 partition for(14) (
ERROR at line 1:
ORA-14108: illegal partition-extended table name syntaxBut specifying explicit partition and subpartition does work:
08:17:45 GM_CS_CDR@oradev02> insert into key_ids2 partition (SYS_P15127) (
08:18:23   2 DATA_ORIGIN_ID         ,
08:18:23   3 TABLE_NAME             ,
08:18:23   4 DUR_UK                 ,
08:18:23   5 DUR_UK_ID              )
08:18:23   6 select
08:18:23   7 12         ,
08:18:23   8 TABLE_NAME             ,
08:18:23   9 DUR_UK||'!'                 ,
08:18:23 10 DUR_UK_ID
08:18:23 11 from key_ids
08:18:23 12 where table_name = 'PART'
08:18:23 13 and rownum <= 10;
10 rows created.
08:18:24 GM_CS_CDR@oradev02> insert into key_ids2 subpartition (SYS_SUBP15126) (
08:19:42   2 DATA_ORIGIN_ID         ,
08:19:42   3 TABLE_NAME             ,
08:19:42   4 DUR_UK                 ,
08:19:42   5 DUR_UK_ID              )
08:19:42   6 select
08:19:42   7 12         ,
08:19:42   8 TABLE_NAME             ,
08:19:42   9 DUR_UK||'!#'                 ,
08:19:42 10 DUR_UK_ID
08:19:42 11 from key_ids
08:19:42 12 where table_name = 'PART'
08:19:42 13 and rownum <= 10;
10 rows created.We have been successful in using the PARTITION FOR syntax for tables that were partitioned but not subpartitioned.
Any ideas?
Thanks,
Mike

I've created a simplified script to reproduce our issue. The use of the syntax on an INSERT INTO using VALUES still produces the same error.
Thanks,
Andy
select * from v$version;
create table part_test_tbl
data_origin_id NUMBER not null,
table_name VARCHAR2(30) not null,
dur_uk     VARCHAR2(250) not null,
dur_uk_id NUMBER
partition by range (data_origin_id) INTERVAL (1)
subpartition by list (TABLE_NAME)
SUBPARTITION TEMPLATE(
subpartition BLUE values ('BLUE'),
subpartition RED values ('RED'),
subpartition YELLOW values ('YELLOW'),
subpartition GREEN values ('GREEN'),
subpartition ORANGE values ('ORANGE')
(PARTITION DFLT_INTRVL VALUES LESS THAN (0)
subpartition BLUE values ('BLUE'),
subpartition RED values ('RED'),
subpartition YELLOW values ('YELLOW'),
subpartition GREEN values ('GREEN'),
subpartition ORANGE values ('ORANGE')
-- Create/Recreate indexes
create index PART_TEST_TBL_PK on PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
compress 2 local;
create unique index PART_TEST_TBL_UK on PART_TEST_TBL (TABLE_NAME, DUR_UK_ID)
compress 1;
-- Create/Recreate primary, unique and foreign key constraints
alter table PART_TEST_TBL
add constraint PART_TEST_TBL_PK primary key (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK) USING INDEX PART_TEST_TBL_PK;
alter table PART_TEST_TBL
add constraint PART_TEST_TBL_UK unique (TABLE_NAME, DUR_UK_ID) USING INDEX PART_TEST_TBL_UK;
--Add test data
BEGIN
   insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
   values (0, 'BLUE', '1', 1);
   insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
   values (0, 'BLUE', '2', 2);
   insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
   values (0, 'YELLOW', '3', 3);
   insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
   values (0, 'GREEN', '4', 4);
   insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
   values (0, 'ORANGE', '5', 5);
   insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
   values (1, 'BLUE', '6', 6);
   insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
   values (1, 'BLUE', '7', 7);
   insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
   values (1, 'YELLOW', '8', 8);
   insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
   values (1, 'GREEN', '9', 9);
   insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
   values (1, 'ORANGE', '10', 10);
   insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
   values (2, 'BLUE', '11', 11);
   insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
   values (2, 'BLUE', '12', 12);
   insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
   values (2, 'YELLOW', '13', 13);
   insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
   values (2, 'GREEN', '14', 14);
   insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
   values (2, 'ORANGE', '15', 15);
   insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
   values (10, 'BLUE', '16', 16);
   insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
   values (10, 'BLUE', '17', 17);
   insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
   values (10, 'YELLOW', '18', 18);
   insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
   values (10, 'GREEN', '19', 19);
   insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
   values (10, 'ORANGE', '20', 20);
   COMMIT;
END;
--Validate the subpartition_extended syntax
select count(*) from PART_TEST_TBL subpartition for(10,'BLUE');
--Show subpartition_extended syntax does not work on INSERT INTO
INSERT /*+APPEND */ INTO PART_TEST_TBL SUBPARTITION FOR (10,'BLUE')
(data_origin_id
,table_name
,dur_uk
,dur_uk_id)
VALUES
(10
,'BLUE'
,'16!'
,1016);
--Show subpartition_extended syntax does not work on INSERT INTO
INSERT /*+APPEND */ INTO PART_TEST_TBL SUBPARTITION FOR (10,'BLUE')
(data_origin_id
,table_name
,dur_uk
,dur_uk_id)
SELECT ptt.data_origin_id
      ,ptt.table_name
      ,ptt.dur_uk || '!' dur_uk
      ,ptt.dur_uk_id + 1000 dur_uk_id
FROM PART_TEST_TBL ptt
WHERE ptt.table_name = 'BLUE'
   AND ptt.data_origin_id = 10;
DROP TABLE part_test_tbl PURGE;-----
SQL> select * from v$version;
BANNER
Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production
PL/SQL Release 11.2.0.3.0 - Production
CORE 11.2.0.3.0 Production
TNS for Solaris: Version 11.2.0.3.0 - Production
NLSRTL Version 11.2.0.3.0 - Production
SQL> create table part_test_tbl
2 (
3    data_origin_id NUMBER not null,
4    table_name VARCHAR2(30) not null,
5    dur_uk     VARCHAR2(250) not null,
6    dur_uk_id NUMBER
7 )
8 partition by range (data_origin_id) INTERVAL (1)
9 subpartition by list (TABLE_NAME)
10 SUBPARTITION TEMPLATE(
11    subpartition BLUE values ('BLUE'),
12    subpartition RED values ('RED'),
13    subpartition YELLOW values ('YELLOW'),
14    subpartition GREEN values ('GREEN'),
15    subpartition ORANGE values ('ORANGE')
16 )
17 (PARTITION DFLT_INTRVL VALUES LESS THAN (0)
18    (
19    subpartition BLUE values ('BLUE'),
20    subpartition RED values ('RED'),
21    subpartition YELLOW values ('YELLOW'),
22    subpartition GREEN values ('GREEN'),
23    subpartition ORANGE values ('ORANGE')
24    )
25 );
Table created
SQL> -- Create/Recreate indexes
SQL> create index PART_TEST_TBL_PK on PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
2    compress 2 local;
Index created
SQL> create unique index PART_TEST_TBL_UK on PART_TEST_TBL (TABLE_NAME, DUR_UK_ID)
2    compress 1;
Index created
SQL> -- Create/Recreate primary, unique and foreign key constraints
SQL> alter table PART_TEST_TBL
2    add constraint PART_TEST_TBL_PK primary key (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK) USING INDEX PART_TEST_TBL_PK;
Table altered
SQL> alter table PART_TEST_TBL
2    add constraint PART_TEST_TBL_UK unique (TABLE_NAME, DUR_UK_ID) USING INDEX PART_TEST_TBL_UK;
Table altered
SQL> --Add test data
SQL> BEGIN
2
3     insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
4     values (0, 'BLUE', '1', 1);
5
6     insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
7     values (0, 'BLUE', '2', 2);
8
9     insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
10     values (0, 'YELLOW', '3', 3);
11
12     insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
13     values (0, 'GREEN', '4', 4);
14
15     insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
16     values (0, 'ORANGE', '5', 5);
17
18     insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
19     values (1, 'BLUE', '6', 6);
20
21     insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
22     values (1, 'BLUE', '7', 7);
23
24     insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
25     values (1, 'YELLOW', '8', 8);
26
27     insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
28     values (1, 'GREEN', '9', 9);
29
30     insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
31     values (1, 'ORANGE', '10', 10);
32
33     insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
34     values (2, 'BLUE', '11', 11);
35
36     insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
37     values (2, 'BLUE', '12', 12);
38
39     insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
40     values (2, 'YELLOW', '13', 13);
41
42     insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
43     values (2, 'GREEN', '14', 14);
44
45     insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
46     values (2, 'ORANGE', '15', 15);
47
48     insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
49     values (10, 'BLUE', '16', 16);
50
51     insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
52     values (10, 'BLUE', '17', 17);
53
54     insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
55     values (10, 'YELLOW', '18', 18);
56
57     insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
58     values (10, 'GREEN', '19', 19);
59
60     insert into PART_TEST_TBL (DATA_ORIGIN_ID, TABLE_NAME, DUR_UK, DUR_UK_ID)
61     values (10, 'ORANGE', '20', 20);
62
63     COMMIT;
64 END;
65 /
PL/SQL procedure successfully completed
SQL> --Validate the subpartition_extended syntax
SQL> select count(*) from PART_TEST_TBL subpartition for(10,'BLUE');
COUNT(*)
         2
SQL> --Show subpartition_extended syntax does not work on INSERT INTO
SQL> INSERT /*+APPEND */ INTO PART_TEST_TBL SUBPARTITION FOR (10,'BLUE')
2 (data_origin_id
3 ,table_name
4 ,dur_uk
5 ,dur_uk_id)
6 VALUES
7 (10
8 ,'BLUE'
9 ,'16!'
10 ,1016);
INSERT /*+APPEND */ INTO PART_TEST_TBL SUBPARTITION FOR (10,'BLUE')
(data_origin_id
,table_name
,dur_uk
,dur_uk_id)
VALUES
(10
,'BLUE'
,'16!'
,1016)
ORA-14173: illegal subpartition-extended table name syntax
SQL> --Show subpartition_extended syntax does not work on INSERT INTO
SQL> INSERT /*+APPEND */ INTO PART_TEST_TBL SUBPARTITION FOR (10,'BLUE')
2 (data_origin_id
3 ,table_name
4 ,dur_uk
5 ,dur_uk_id)
6 SELECT ptt.data_origin_id
7        ,ptt.table_name
8        ,ptt.dur_uk || '!' dur_uk
9        ,ptt.dur_uk_id + 1000 dur_uk_id
10    FROM PART_TEST_TBL ptt
11   WHERE ptt.table_name = 'BLUE'
12     AND ptt.data_origin_id = 10;
INSERT /*+APPEND */ INTO PART_TEST_TBL SUBPARTITION FOR (10,'BLUE')
(data_origin_id
,table_name
,dur_uk
,dur_uk_id)
SELECT ptt.data_origin_id
      ,ptt.table_name
      ,ptt.dur_uk || '!' dur_uk
      ,ptt.dur_uk_id + 1000 dur_uk_id
FROM PART_TEST_TBL ptt
WHERE ptt.table_name = 'BLUE'
   AND ptt.data_origin_id = 10
ORA-14173: illegal subpartition-extended table name syntax
SQL> DROP TABLE part_test_tbl PURGE;
Table dropped
SQL>

ORA 2266 -- Drop parent partition with no child records exists

Hi Team ,
Here I have a parent partitioned table and child refrenced non-partition table .
To drop parent partition I am doing
1)delete from child
2)delete from parent partition
3)alter table drop parent partition
---and its working fine .
I am trying to do below which is not working , Could you please guide me why it is not
1)delete from child
2)alter table drop parent partition -- throwing below error
Summarizing ,
Why I am not able to drop/trunc a parent partition(no corresponding rows exists in child tables) where as able to do after deleting the rows from parent partition .
From Doc :
Error: ORA 2266
Text: table has some unique/primary keys that are referenced by some foreign k
eys
Cause: Attempt to drop the table while the table still has some unique/
primary keys that are referenced by some foreign keys.
Action: Remove all such references to the keys before dropping the table
Oracle Database 11g Enterprise Edition Release 11.2.0.2.0 - 64bit Production
PL/SQL Release 11.2.0.2.0 - Production
CORE     11.2.0.2.0     Production
TNS for Linux: Version 11.2.0.2.0 - Production
NLSRTL Version 11.2.0.2.0 - Production

Oracle decides what the rules are & you must conform to them
bcm@bcm-laptop:~$ oerr ora 2266
02266, 00000, "unique/primary keys in table referenced by enabled foreign keys"
// *Cause: An attempt was made to truncate a table with unique or
//         primary keys referenced by foreign keys enabled in another table.
//         Other operations not allowed are dropping/truncating a partition of a
//         partitioned table or an ALTER TABLE EXCHANGE PARTITION.
// *Action: Before performing the above operations the table, disable the
//          foreign key constraints in other tables. You can see what
//          constraints are referencing a table by issuing the following
//          command:
//          SELECT * FROM USER_CONSTRAINTS WHERE TABLE_NAME = "tabnam";

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To change to manually managing an iPod you don't "unselect" sync music, you "select" manually manage songs and videos. If you want to delete songs from iTunes and keep them on the iPod you need to change the update option of your iPod by checking the box beside "manually manage songs and videos" in the Summary tab and clicking Apply. Your iPod will not sync with iTunes in this mode so it can have different content, you can get details here:
Managing content manually on iPod
iPod 101: Fill 'er Up
One major word of caution. If you delete songs or videos from your computer and have no back up other than the iPod you will risk losing them permanently if your iPod fails or you find you have to restore it to solve a problem. You should consider investing in an additional internal or external hard drive to store/back up your music. Alternatively at the very least back up anything you can't replace such as iTunes downloads to CD or DVD: How to back up your media in iTunes
Something else to be aware of when using an iPod in manual mode is that the "Do Not Disconnect" message will remain on the display until you physically eject the device. In that case use Safely Remove Hardware icon in the Windows system tray on your desktop or check this link: Safely Disconnect IPod
I don't have any TV shows so I can't speak from experience here but looking at the TV tab it appears you can only sync shows, there's no manually manage option. Syncing would require that you keep the shows on your computer otherwise they would be removed from the iPod the next time you syncronised with iTunes.

Doubt in partition and subpartition

hi gems...good afternoon...
I have a doubt redgarding partitioning and subpartitioning...This may be a silly question, but i am really not getting this...please help me..
I have a table which has Range-Hash composite partitioning.
The Range partitioning is on the default tablespace TS_PROD (because I didnt mention any tablespace name in the Range partitions).
The Hash subpartitioning are on the corresponding partition tablespaces (TS_PART1,TS_PART2,TS_PART3....TS_PART6).
I have created total 8 Range partitions and the number of Hash subpartitions are 6 for each of them.
Now when I query the DBA_TAB_PARTITIONS, then I got the desired output i.e. all the Range partitions are in the default tablespace.
When I query the DBA_TAB_SUBPARTITIONS, then also I got the desired output i.e. all the Hash subpartitions are in the separate partition tablespaces.
But when I have inserted data in that table, then I found that both the default tablespace and partition tablespaces are getting filled up.
Moreover, the sum of the increase in sizes of the partition tablespaces is equal to the increase in default tablespace.
I am not getting the concept of this. Where are the datas are getting stored??? In the default tablespace or in the partition tablespaces??
Thanks a lot in advance..

thanks a lot RP for your reply...
and sorry for the late and miscommunication...
Actually i am not so experienced in the DBA line and in my company suddenly my senior DBA left and i am the only one here...I got tensed... :( :(
I have started reading documentation of Oracle, have started the Administrator's Guide first...
Anyways...now i got the concept of the partitioning and subpartitioning i was doing...
The mistake which I was doing is: I was not mentioning the primary key index tablespace and that segment is going into the default tablespace and thats why the size was increasing for both default tablespace and partitioned tablespaces. Because of that fact I was getting confused again and again.
As soon as I mentioned the primary key index tablespace, the size of the default tablespace stopped increasing...
Now the script from which I am getting the size of the tablespaces: (join of dba_datafiles and dba_free_space)
select /* + RULE */ t.tablespace, t.totalspace as " Totalspace(MB)",
round((t.totalspace-fs.freespace),2) as "Used Space(MB)",
fs.freespace as "Freespace(MB)",
round(((t.totalspace-fs.freespace)/t.totalspace)*100,2) as "% Used",
round((fs.freespace/t.totalspace)*100,2) as "% Free"
from
(select round(sum(d.bytes)/(1024*1024)) as totalspace, d.tablespace_name tablespace
from dba_data_files d
group by d.tablespace_name) t,
(select round(sum(f.bytes)/(1024*1024)) as freespace, f.tablespace_name tablespace
from dba_free_space f
group by f.tablespace_name) fs
where t.tablespace=fs.tablespace
order by t.tablespace;
Thanks a lot RP for your help... :)

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If you would like to delete previously purchased content off of your iPhone, you may find the steps outlined in the following article helpful:
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This machine is FAST & it can't handle a little gadget. (7.2/7.3 Windows Experience subscores on all but hard disk, which is 5.9) Didn't have this issue in Vista x64 Home Prem.
edit:
Checked the Win7 Resource Monitor CPU tab:
sidebar.exe - While not under heavy CPU load, "Analyze Wait Chain..." from context menu continually shows "One or more threads of sidebar.exe are waiting to finish network I/O", and indicates thread 4140 which is WinInet.dll (Internet Extensions for Win32 application extension.) Under heavy CPU load, several other threads starting from sidebar.exe were indicated from the same message from "Analyze Wait Chain..." as well.
All other non-sidebar processes indicate "running normally" from "Analyze Wait Chain..."
Another clue: If I login using the "Administrator" account, there is *** no performance problem ***! The sidebar.exe shows as "running normally" from "Analyze Wait Chain..."
So I also tried:
- w/UAC turned off on the normal user (administrator rights) account (no fix)
- tried creating a *new* normal user (administrator rights) account; still sloooowwww (also try this one w/o UAC, still bad)
-Problem Status: normal User Accounts have the sidebar performance problem, Administrator account runs fine.
Edit: 12/31/09
SOLVED!!!!
After digging into the sidebar.exe output from Sysinternals Process Monitor, I noticed a peculiar difference between the output for the properly functioning Administrator account & my User accounts. The admin acct showed the monitor profile for a good number of operations, while the User accts showed the wsRGB.cdmp value for the same operations, which was peculiar because I had my User accounts configured to use the system defaults, the same way I had the admin acct configured.
Going into the Windows Color Management, Advanced tab, I found that if I chose either of the "virtual device model profile" choices for the "Device Profile" setting, the performance hit was instant. If I used any of the "normal" icm profiles, performance was good. So I changed my system default Device Profile from "sRGB virtual device model profile" to the std sRGB.icm profile & everything is working great!
Note: In addition to the Gadgets, this also impacted the Windows Media Center Internet TV listings performance, which was also back to good performance after this WCM setting change. I'd expect there are numerous other apps that could be affected by the "virtual device model profile" handling. Googling "virtual device model profile" seems to bear that out, as I see others who ran into app problems when using that in the WCM applet.

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C:\Documents and Settings\(username)\Application Data\Apple Computer\MobileSync\Backup\
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Try going here and emailing the store about the issue
http://www.apple.com/support/itunes/musicstore/download/

I have an iPhone under my parents account. Now that I have my own, I would like to change the Apple id on the phone to my own (new) account. If I do so, will I lose all of my apps, music, contacts, etc?

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SMinsk wrote:
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No.

Parent partition of subpartitions that move to a new TS

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