Parsing xml that contains special character

Question

this is my xml file.
<?xml version="1.0" encoding="ISO-8859-1" ?>
<grid_assessment>
     <chart>
          <range>5</range>
          <sharing_charging>
               <score>3</score>
               <label><![CDATA[SHARING &#38; CHARGING POLICIES]]></label>
this is my java code.
          SAXParser parser = new SAXParser();
          parser.setContentHandler(this);
          parser.setErrorHandler(this);
          try
               fis = new FileInputStream(xmlFile);
          catch(IOException ioe)
               System.out.println( ioe.getMessage() );
          InputSource inputSource = new InputSource((InputStream)fis);
          try
               parser.parse(inputSource);
          catch(SAXException saxe)
               System.out.println( saxe.getMessage() );
          catch(IOException ioe)
               System.out.println(ioe.getMessage());
when i parse the xml file, i got an error message like this.
org.xml.sax.SAXParseException: The entity name must immediately follow the '&' in the entity reference.Stopping after fatal error: The entity name must immediately follow the '&' in the entity reference.
is there anybody who knows how to parse the xml file that contais special character?
i tried "&#38;" instead of "&". but it didn't work...
please help...
thanks in advance...

Answer 1

this is my java code.
          SAXParser parser = new SAXParser();If that is javax.xml.parsers.SAXParser then your code won't compile; i suspect you might be using some non-standard parser?
          parser.setContentHandler(this);
          parser.setErrorHandler(this);These methods are deprecated.
when i parse the xml file, i got an error message like this.
org.xml.sax.SAXParseException: The entity name must
immediately follow the '&' in the entity
reference.Stopping after fatal error: The entity name
must immediately follow the '&' in the entity
reference.I don't; maybe it's your parser. What parser are you using, and what version?
is there anybody who knows how to parse the xml file
that contais special character?There is nothing more you need to do; the codeimport javax.xml.parsers.*;
import org.xml.sax.helpers.DefaultHandler;
import org.xml.sax.*;
import java.io.*;
public class CeasarKim1Parser extends DefaultHandler {
  public static void main (String[] args) {
    try {
      SAXParser parser = SAXParserFactory.newInstance().newSAXParser();
      FileInputStream fis = null;
      fis = new FileInputStream(args[0]);
      InputSource inputSource = new InputSource((InputStream)fis);
      parser.parse(inputSource, new CeasarKim1Parser () );
    } catch(SAXException saxe) {
      saxe.printStackTrace();
    } catch(IOException ioe) {
      ioe.printStackTrace();
    } catch (ParserConfigurationException pce) {
      pce.printStackTrace();
  public void characters(char[] ch, int start, int length) {
    System.out.println(new String(ch, start, length));
// similar implementations of the other content handler methods
}which is basically a compilable and non-deprecated version of yours, with the file<?xml version="1.0" encoding="ISO-8859-1" ?>
<grid_assessment>
  <chart>
    <range>5</range>
    <sharing_charging>
      <score>3</score>
      <label><![CDATA[SHARING & CHARGING POLICIES]]></label>
    </sharing_charging>
  </chart>
</grid_assessment>does not generate any exceptions and parses the CDATA section correctly. That is using 1.4.1 and the default org.apache.crimson.jaxp.SAXParserImpl parser.
Pete