PHP Code: Using a variable to name the file in an Include

Question

I have a series of case statements assigning a value to the
variable $theme
based on the current month. Then I have a set of files
(january.txt,
february.txt, etc.). The variable values are those file
names:
// get current month as a number
$month = date('n');
// select theme for the month
switch($month) {
case 3:
$theme = 'march.txt';
break;
case 4:
$theme = 'april.txt';
break;
[etc.]
What is the correct syntax for a PHP Include that will use
the current value
of $themes for the filename?
Thanks
Walt

Answer 1

<?php include('_inc/'.$theme); ?>
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"Walt F. Schaefer" <[email protected]> wrote in
message
news:gqutqv$qbf$[email protected]..
>I have a series of case statements assigning a value to
the variable $theme
>based on the current month. Then I have a set of files
(january.txt,
>february.txt, etc.). The variable values are those file
names:
> // get current month as a number
> $month = date('n');
> // select theme for the month
> switch($month) {
> case 3:
> $theme = 'march.txt';
> break;
> case 4:
> $theme = 'april.txt';
> break;
> [etc.]
> What is the correct syntax for a PHP Include that will
use the current
> value of $themes for the filename?
>
> Thanks
>
> --
>
> Walt
>
>
>