PHP/MySQL Relational Database

Hi,
I am fairly new to php/MySQL. I am stuck on how to make a cross linking database.
I have two tables "users" and "comments" and would like to set up a page that a logged in user can see and edit the comments they have made.
So far I have tried to make an advanced recordset but all i have managed to do is display all of the records that share a user_id.
I am using dreamweaver CS5.5 and PHP and MySQL.
Thanks in advance for your help
Eddie

That should just be a basic query to SELECT * FROM {comment-tbl} WHERE userid = $_SESSION['user'].
Are you using Sessions or Cookies at this point or are you just trying to write this into a query without them?

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On Fri, 23 Nov 2007 16:21:50 +0000 (UTC), "MacDaddy333"
<[email protected]> wrote:
>Hello,
>
> All of the sites that have this issue are secure, one is
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>
>
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>
> You will need to create a user account and then log in
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bouldersp wrote:
> I typed in all the
> information and when I clicked "Test" or to browse for
the appropriate database
> it pops up an error message saying "An unidentifiable
error has occurred".
That usually means that something is preventing communication
between
Dreamweaver and the testing server. It could be a firewall or
anti-virus
software. In the Testing Server section of the Advanced tab
in Site
definition, Host directory and URL prefix should both point
to the same
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your site, the
second is the URL you enter into a browser address bar to get
to the
same location.
> I'm using Dreamweaver CS3, PHP/MySQL on a remote server
as I still can't get
> my local web server functioning properly under Leopard.
You might find this tutorial on my website helps:
http://foundationphp.com/tutorials/php_leopard.php
David Powers, Adobe Community Expert
Author, "The Essential Guide to Dreamweaver CS3" (friends of
ED)
Author, "PHP Solutions" (friends of ED)
http://foundationphp.com/

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PHP/MySQL search record

Hi,
I have a form where a user will enter their desired user name
and their
e-mail address. Once I see that both fields are filled in, I
need to check
to see if the username and/or e-mail address they entered are
already in the
database.
The table is called "login_table" and the field for the
username is "usr"
and the field for e-mail is "email" - again, I need to check
to see that
these are not duplicated before I enter the data into the
table.
I'm a little unsure (actually, I don't know how), to do this.
If someone
could provide any code that would achieve this, that would be
greatly
appreciated.
Thanks (if you need more info, let me know).
Shane H
[email protected]
http://www.avenuedesigners.com
=============================================
Blog:
http://avenuedesigners.com/blog/
Web dev articles, photography, and more:
http://sourtea.com
=============================================
Proud GAWDS member
http://www.gawds.org/showmember.php?memberid=1495
Delivering accessible websites to all ...
=============================================

Well, I got around it. It's probably not the best way, but
essentially I did
a str_replace to get rid of all the additional data in the
mysql_error()
except for the username/email that is duplicated, and just
made a general
error message regarding which one was already in the
database.
Shane H
[email protected]
http://www.avenuedesigners.com
=============================================
Blog:
http://avenuedesigners.com/blog/
Web dev articles, photography, and more:
http://sourtea.com
=============================================
Proud GAWDS member
http://www.gawds.org/showmember.php?memberid=1495
Delivering accessible websites to all ...
=============================================
"Shane H" <[email protected]> wrote in
message
news:[email protected]...
> Hi Joe,
>
> Yeah that does work. I set UNIQUE for both the "usr" and
the "email"
> field. I do have one question now. Is there anyway for
me to tell which
> one is giving the error, so I can tailor a custom error
message?
>
> If I let MySQL give me the error, like -
>
> mysql_error();
>
> It gives me -
>
> "Duplicate entry for blah blah blah"
>
> I'd like to be able to customize my error message, and I
know how to do
> that if I could only determine how to tell which one is
throwing the
> error...
>
> --
> Shane H
> [email protected]
>
http://www.avenuedesigners.com
>
> =============================================
> Blog:
>
http://avenuedesigners.com/blog/
>
> Web dev articles, photography, and more:
>
http://sourtea.com
> =============================================
> Proud GAWDS member
>
http://www.gawds.org/showmember.php?memberid=1495
>
> Delivering accessible websites to all ...
> =============================================
>
>
> "Joe Makowiec" <[email protected]> wrote in
message
>
news:[email protected]...
>> On 05 May 2007 in macromedia.dreamweaver, Shane H
wrote:
>>
>>> I have a form where a user will enter their
desired user name and
>>> their e-mail address. Once I see that both
fields are filled in, I
>>> need to check to see if the username and/or
e-mail address they
>>> entered are already in the database.
>>>
>>> The table is called "login_table" and the field
for the username is
>>> "usr" and the field for e-mail is "email" -
again, I need to check
>>> to see that these are not duplicated before I
enter the data into
>>> the table.
>>>
>>> I'm a little unsure (actually, I don't know
how), to do this. If
>>> someone could provide any code that would
achieve this, that would
>>> be greatly appreciated.
>>
>> Most (R)DBMS[1] systems allow for requiring that all
values in a field
>> be unique; for a primary key, it's required. Look
through your DBMS's
>> help files or reference for how to make a field a
primary key, and how
>> to set up a UNIQUE index. For MySQL:
>>
>>
http://dev.mysql.com/doc/refman/5.0/en/constraint-primary-key.html
>>
>> [1] (Relational) DataBase Management System
>> --
>> Joe Makowiec
>>
http://makowiec.net/
>> Email:
http://makowiec.net/contact.php
>
>

Can't connect PHP/MySQL 404 error

Wow, the learning curve is killing me. Yet another challenge. I'm using Dreamweaver CC and this tutorial http://www.adobe.com/devnet/dreamweaver/articles/setup_php.html
I'm at this step:
Open comments.php. You must have a PHP page open in the Document window to create a MySQL connection.
In the Databases panel (choose Window > Databases), click the Plus button on the panel and select MySQL Connection.The MySQL Connection dialog box appears.
Type connTest as the connection name.
For the MySQL Server, type localhost.If you are using the MAMP default ports on a Mac, use localhost:8889.
For the User Name, type phptestuser.
Type the password you chose for the phptestuser account in the Password field.
For the Database, type php_test.Note: You don't need to precede the underscore with a backslash here. It was inserted by phpMyAdmin in the previous section (see Figure 20) only because phpMyAdmin uses a query that permits wildcard characters.
Click Test.Dreamweaver attempts to connect to the database. If the connection fails, do the following:
Double-check the server name, user name, and password.
Check the settings for the folder Dreamweaver uses to process dynamic pages (see Specifying a Testing Server for Dreamweaver).
Verify that the web and MySQL servers are both running.
Temporarily disable any firewall or security program. If the connection works, you need to configure the security program to permit communication between Dreamweaver and MySQL.
Click OK. The new connection appears in the Databases panel.
Expand the connTest connection, and then expand the Tables branch. You'll see the comments table in the database, which you can expand to reveal the details of the table columns (see Figure 23).
As far as I can tell I have followed this tutorial to the letter.
As far as I can tell, XAMPP/php mySQL are all running fine, the files are in the correct place and everything should be working. However when I hit test I get a 404 error. (Same error when I hit the select button.)
The suggested problems on the 404 message are:
1. There is no testing server running on the server machine.
Pretty sure the testing server is running. Is there any way to test this, other than to note that xampp is definitely running right now and that I can log into phpMYadmin no problem?
2. The testing server specified for this site does not map to the http://localhost/php_test/_MMServerScripts/MMHTTPDB.php URL Verify that the URL Prefix maps to the root of the site.
Ummm...I'm pretty sure I put things where I was told to put them in the tutorial, but I'm lost at this point where I should verify what. A clue here? The files are where they are supposed to be, but maybe I entered something wrong? Except...I'm not sure what that could be or where to find it. Whatever IT is.
Everything in local files is looking good.
Thanks for your help!
PS: Extra points to anyone who figures out how to make copy/pasteable error messages! These buggers are the bane of my life!

Bgupta, you rock!
I hope you have copied the "mysql.php" and "MMHTTPDB.php" files from "C:\Users\username\AppData\Roaming\Adobe\Dreamweaver CC\locale\Configuration\Connections\Scripts\PHP_MySQL\_mmDBScripts" to "C:\xampp\htdocs\phptest\_mmServerScripts"
This was EXACTLY the problem. I checked the tutorial and I couldn't even find where the tutorial said to do this. (If I missed it, let me know where in the tutorial it was, please.)
Fixed!

Show if field is not empty - PHP/MySQL

Is there a way I can only show bits of a page if a recordset
has entries in a certain field, automatically hiding the area if
the field is empty. (PHP/MySQL)
To put it in real terms, I have loads of products listed in a
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ADDT is certainly a great help, as it - among many other
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display videos icon here
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I use Dreamweaver CS3 to create my sites on a Windows/Apache
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error which causes the page to not load:
PHP Warning: mysql_query(): supplied argument is not a valid
MySQL-Link resource in
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on line 63
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This is the first time I've used Adobe products so if the
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far) or the format is incorrect please forgive me.
I'm new to Dreamweaver CS3 and as I was reading the "first
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Asp Javascript
Asp VbScript
Asp.net#
Asp.net Vb
Cold Fusion
JSP
Php MySql.
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She did mention that I have a windows hosting account and Php
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formats mentioned above (if so which one) - or select the No
option. If I do select the No option at the very beginning, will I
have problems with my site uploading and working correctly?
Thank you
Travis

PHP/MySQL issue after security update 2010-005

Hello,
I run Apache/PHP/MySQL on my MBP for testing Web sites.
After the 2010-005 security update I can't connect to my databases anymore.
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coloma wrote:
etresoft, thanks for sharing this ... I decided to go with the TriangleJuice suggestion instead for two reasons ... first is that I wasn't sure where to find this launchd file.
There is nothing wrong with TriangleJuice's suggestion. My only issue with creating a php.ini file is that now I have to worry about all those other settings in the ini file. If something else in PHP breaks, I have to figure out if I am the one who broke it.
Apple ships MySQL with MacOS X Server. They probably adjusted the PHP settings to match how they have MySQL setup in MacOS X Server.
For MySQL's, no, Sun's - drat! no, Oracle's part, they still haven't acknowledged the fact that Apple has shipped MacOS X 10.4. MySQL still ships with a Startup Item. If you don't know where the launchd file is, it is because you don't have one. You probably have a MySQL entry in /Library/StartupItems or maybe /System/Library/StartupItems. Startup Items were deprecated in 10.4. Oracle should be creating a file named com.mysql.mysqld.plist in /Library/LaunchDaemons.
Here is what mine looks like now:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE plist PUBLIC "-//Apple//DTD PLIST 1.0//EN" "http://www.apple.com/DTDs/PropertyList-1.0.dtd">
<plist version="1.0">
<dict>
<key>KeepAlive</key>
<true/>
<key>Label</key>
<string>com.mysql.mysqld</string>
<key>ProgramArguments</key>
<array>
<string>/usr/local/mysql/bin/mysqld</string>
<string>--socket=/var/mysql/mysql.sock</string>
<string>--basedir=/usr/local/mysql</string>
<string>--datadir=/usr/local/mysql/data</string>
<string>--user=mysql</string>
<string>--log-error=/usr/local/mysql/data/Pele.local.err</string>
<string>--pid-file=/usr/local/mysql/data/Pele.local.pid</string>
</array>
<key>RunAtLoad</key>
<true/>
</dict>
</plist>
I also don't have a /var/mysql directory and wasn't sure whether I should just create one or if this meant my configuration was different. If you feel like explaining any of this, I'd be curious to know.
You have to create one. Such a directory probably already exists on MacOS X Server. Just make sure it is owned by mysql.
sudo mkdir /var/mysql
sudo chown _mysql:staff /var/mysql
sudo chmod 0755 /var/mysql
[jdaniel@Pele:516] /var $ ls -al /private/var | grep mysql
drwxr-xr-x 3 _mysql staff 102 Aug 26 20:03 mysql
Of course, /var is a symbolic link to /private/var. Long story there.

Spry accordion with php mysql as data

Hello
I`m trying to create a spry accordion where the Labels are pulled from a mysql database table and the Content of that label is pulled from data in the same database. I tried adding first the spry accordion and then created 1 recordset for the labels and a second recordset for the content , then I added a repeat region for the labels DIV and inside this div I added a repeat region for the content.
Unfortunatly when viewed in the browsers the accordion doesn`t work.
Can anyone look at the code and tell me where is the mistake.
Thanks
<?php require_once('Connections/log.php'); ?>
<?php
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function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "")
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$totalRows_log_year = mysql_num_rows($log_year);mysql_select_db($database_log, $log);
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$log_year = mysql_query($query_log_year, $log) or die(mysql_error());
$row_log_year = mysql_fetch_assoc($log_year);
$totalRows_log_year = mysql_num_rows($log_year);
$mhour_log_mon = "0";
if (isset($row_log_year['yy'])) {
$mhour_log_mon = $row_log_year['yy'];
mysql_select_db($database_log, $log);
$query_log_mon = sprintf("SELECT DISTINCT DATE_FORMAT(`23849`.acoff, '%%M') AS mon , DATE_FORMAT(`23849`.acoff, '%%m') AS m , sum(`23849`.ablock) as toth FROM `23849` WHERE YEAR(`23849`.acoff) = %s GROUP BY m ORDER BY m ", GetSQLValueString($mhour_log_mon, "int"));
$log_mon = mysql_query($query_log_mon, $log) or die(mysql_error());
$row_log_mon = mysql_fetch_assoc($log_mon);
$totalRows_log_mon = mysql_num_rows($log_mon);
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>testing ajax php mysql</title>
<script src="SpryAssets/SpryAccordion.js" type="text/javascript"></script>
<link href="SpryAssets/SpryAccordion.css" rel="stylesheet" type="text/css" />
</head>
<body>
<div id="Accordion1" class="Accordion" tabindex="0">
<div class="AccordionPanel">
    <?php do { ?>
      <div class="AccordionPanelTab"><?php echo $row_log_year['yy']; ?></div>
      <?php } while ($row_log_year = mysql_fetch_assoc($log_year)); ?>
<div class="AccordionPanelContent">
<table width="100%" border="0" cellspacing="5" cellpadding="5">
    <?php do { ?>
      <tr>
        <td><?php echo $row_log_mon['mon']; ?></td>
        <td><?php echo $row_log_mon['toth']; ?></td>
      </tr>
      <?php } while ($row_log_mon = mysql_fetch_assoc($log_mon)); ?>
</table>
</div>
</div>
</div>
<script type="text/javascript">

</script>
</body>
</html>
<?php
mysql_free_result($log_year);
mysql_free_result($log_mon);
?>

You only have 1 "AccordianPanel" which contains a list of "AccordianPanelTab" elements, then a list of "AccordianPanelContent" elements.
You need to have a list of "AccordianPanel" elements, each containing a pair or "AccordianPanelTab" and "AccordianPanelContent" elements.
HTH,
Randy

PHP/MySQL Relational Database

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