PL/SQL query that has a link to other website

I want to do a query that list books info (Date published, name, category, etc). The part I can't figure out is how would I create an HTML link on the "Name?" The website is on a separate server (i.e. http://mybookstore.com). The links are in the table with the Name and category.
I would like to use PL/SQL or Java (but prefer PL/SQL).
Any help would be appreciated.
Ken

Hi Ken,
try the following for the query .....
select category , <A href = 'target_page'>name </A>, date_published from table_name;
Where exactly you want to use the query ... Is it for a report in Portal ...
Regds..
Sajith

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In a SQL query whihc has join, How to reduce Multiple instance of a table

in a SQL query which has join, How to reduce Multiple instance of a table
Here is an example: I am using Oracle 9i
is there a way to reduce no.of Person instances from the following query? or can I optimize this query further?
TABLES:
mail_table
mail_id, from_person_id, to_person_id, cc_person_id, subject, body
person_table
person_id, name, email
QUERY:
SELECT p_from.name from, p_to.name to, p_cc.name cc, subject
FROM mail, person p_from, person p_to, person p_cc
WHERE from_person_id = p_from.person_id
AND to_person_id = p_to.person_id
AND cc_person_id = p_cc.person_id
Thnanks in advance,
Babu.

SQL> select * from mail;
        ID          F          T         CC
         1          1          2          3
SQL> select * from person;
       PID NAME
         1 a
         2 b
         3 c
--Query with only ne Instance of PERSON Table
SQL> select m.id,max(decode(m.f,p.pid,p.name)) frm_name,
2         max(decode(m.t,p.pid,p.name)) to_name,
3         max(decode(m.cc,p.pid,p.name)) cc_name
4 from mail m,person p
5 where m.f = p.pid
6 or m.t = p.pid
7 or m.cc = p.pid
8 group by m.id;
        ID FRM_NAME   TO_NAME    CC_NAME
         1 a          b          c
--Expalin plan for "One instance" Query
SQL> explain plan for
2 select m.id,max(decode(m.f,p.pid,p.name)) frm_name,
3         max(decode(m.t,p.pid,p.name)) to_name,
4         max(decode(m.cc,p.pid,p.name)) cc_name
5 from mail m,person p
6 where m.f = p.pid
7 or m.t = p.pid
8 or m.cc = p.pid
9 group by m.id;
Explained.
SQL> select * from table(dbms_xplan.display);
PLAN_TABLE_OUTPUT
Plan hash value: 902563036
| Id | Operation           | Name   | Rows | Bytes | Cost (%CPU)| Time     |
|   0 | SELECT STATEMENT    |        |     3 |   216 |     7 (15)| 00:00:01 |
|   1 | HASH GROUP BY      |        |     3 |   216 |     7 (15)| 00:00:01 |
|   2 |   NESTED LOOPS      |        |     3 |   216 |     6   (0)| 00:00:01 |
|   3 |    TABLE ACCESS FULL| MAIL   |     1 |    52 |     3   (0)| 00:00:01 |
|* 4 |    TABLE ACCESS FULL| PERSON |     3 |    60 |     3   (0)| 00:00:01 |
PLAN_TABLE_OUTPUT
Predicate Information (identified by operation id):
   4 - filter("M"."F"="P"."PID" OR "M"."T"="P"."PID" OR
              "M"."CC"="P"."PID")
Note
   - dynamic sampling used for this statement
--Explain plan for "Normal" query
SQL> explain plan for
2 select m.id,pf.name fname,pt.name tname,pcc.name ccname
3 from mail m,person pf,person pt,person pcc
4 where m.f = pf.pid
5 and m.t = pt.pid
6 and m.cc = pcc.pid;
Explained.
SQL> select * from table(dbms_xplan.display);
PLAN_TABLE_OUTPUT
Plan hash value: 4145845855
| Id | Operation            | Name   | Rows | Bytes | Cost (%CPU)| Time     |
|   0 | SELECT STATEMENT     |        |     1 |   112 |    14 (15)| 00:00:01 |
|* 1 | HASH JOIN           |        |     1 |   112 |    14 (15)| 00:00:01 |
|* 2 |   HASH JOIN          |        |     1 |    92 |    10 (10)| 00:00:01 |
|* 3 |    HASH JOIN         |        |     1 |    72 |     7 (15)| 00:00:01 |
|   4 |     TABLE ACCESS FULL| MAIL   |     1 |    52 |     3   (0)| 00:00:01 |
|   5 |     TABLE ACCESS FULL| PERSON |     3 |    60 |     3   (0)| 00:00:01 |
PLAN_TABLE_OUTPUT
|   6 |    TABLE ACCESS FULL | PERSON |     3 |    60 |     3   (0)| 00:00:01 |
|   7 |   TABLE ACCESS FULL | PERSON |     3 |    60 |     3   (0)| 00:00:01 |
Predicate Information (identified by operation id):
   1 - access("M"."CC"="PCC"."PID")
   2 - access("M"."T"="PT"."PID")
   3 - access("M"."F"="PF"."PID")
PLAN_TABLE_OUTPUT
Note
   - dynamic sampling used for this statement
25 rows selected.
Message was edited by:
        jeneesh
No indexes created...

Reg: sql query that prints all sundays in the year

Hi all,
Please give me sql query that prints all sundays in year. And when ever we execute that query then that will prints the sysdate(that is execution date).
Thanks in Advance,
-prasad.
Edited by: prasad_orcl on Jun 5, 2009 9:13 PM

Hi,
Plz try this and let me know this works or not...
SELECT DATE DATES,TO_CHAR(DATE,'DAY') DAYS FROM FISCAL_CALENDAR
WHERE DATE_YEAR = 2009 AND
DATE BETWEEN TRUNC(SYSDATE,'YEAR') AND
ADD_MONTHS(TRUNC(SYSDATE,'YEAR'),12) -1 AND
TRIM(TO_CHAR(DATE,'DAY')) = 'SUNDAY'
ORDER BY DATE
OUTPUT:
DATES     DAYS
1/4/2009     SUNDAY
1/11/2009     SUNDAY
1/18/2009     SUNDAY
1/25/2009     SUNDAY
2/1/2009     SUNDAY
2/8/2009     SUNDAY
2/15/2009     SUNDAY
2/22/2009     SUNDAY
3/1/2009     SUNDAY
3/8/2009     SUNDAY
3/15/2009     SUNDAY
3/22/2009     SUNDAY
3/29/2009     SUNDAY
4/5/2009     SUNDAY
4/12/2009     SUNDAY
4/19/2009     SUNDAY
4/26/2009     SUNDAY
5/3/2009     SUNDAY
5/10/2009     SUNDAY
5/17/2009     SUNDAY
5/24/2009     SUNDAY
5/31/2009     SUNDAY
6/7/2009     SUNDAY
6/14/2009     SUNDAY
6/21/2009     SUNDAY
6/28/2009     SUNDAY
7/5/2009     SUNDAY
7/12/2009     SUNDAY
7/19/2009     SUNDAY
7/26/2009     SUNDAY
8/2/2009     SUNDAY
8/9/2009     SUNDAY
8/16/2009     SUNDAY
8/23/2009     SUNDAY
8/30/2009     SUNDAY
9/6/2009     SUNDAY
9/13/2009     SUNDAY
9/20/2009     SUNDAY
9/27/2009     SUNDAY
10/4/2009     SUNDAY
10/11/2009SUNDAY
10/18/2009SUNDAY
10/25/2009SUNDAY
11/1/2009     SUNDAY
11/8/2009     SUNDAY
11/15/2009SUNDAY
11/22/2009SUNDAY
11/29/2009SUNDAY
12/6/2009     SUNDAY
12/13/2009SUNDAY
12/20/2009SUNDAY
12/27/2009SUNDAY
Regards
Thiyag

OTL I am trying to wright a SQL query that will return the date the timesheet was submitted and date/time it was approved, can anyone guide me on this?

Hi
I am trying to wright a SQL query that will return the date the timesheet was submitted and date/time it was approved, can anyone guide me on this?
I basically need person name who submitted, date - time it was submitted for approval, then the person who approved it and the date - time that it was approved
Thanks
Ruby

Ruby,
you can start with HXC_TIMECARD_SUMMARY table for submitter detail. But for approver details, i think you need WF tables to get the data for item type HXCEMP.

Need Sql Query that Suppress the repeating rows.

Hi Sir,
I have below data set.
DeptID Sum(SAL) Avg(Sal)
10      1300      1300
10      2450      1300
10      5000      1300
20      800        800
20      1100      800
20      2975      800
20      3000      800
30      800        800
30      1100      800
30      2975      800
40      3000      800
40      4000      900
I Need SQL query that can remove the duplicate or suppress.Just like below data set.
Output:
DeptID Sum(SAL) Avg(Sal)
10      1300      1300
            2450      1300
            5000      1300
20       800        800
            1100      800
            2975      800
            3000      800
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30      1100      800
            2975      800
40      3000      800
           4000      900
Could you please help me on this..

Your requiremnt is more of a reporting request which should not be handled in SQL. For example in SQL Plus you can use the BREAK command
SQL> break on deptno
SQL> select deptno, ename from emp order by deptno;
    DEPTNO ENAME
        10 KING
           CLARK
        20 JONES
           SCOTT
           SMITH
           ADAMS
        30 TURNER
           MARTIN
           WARD
           ALLEN
           BLAKE
11 rows selected.
SQL>
But if you still wish to do it in SQL you can use ROW_NUMBER analytic function and achieve it like this
select decode(rno, 1, deptno) deptno
     , ename
from (
          select row_number() over(partition by deptno order by ename) rno
               , deptno
               , ename
            from emp

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In the article "What are App Tabs", there's the following statement:
"Links to other websites open in a new tab so that your App Tab doesn't change." That doesn't happen when I make an App Tab in FF 7.01 in Win 7. I want it to happen, but it doesn't. Sometimes I want to keep Gmail open while I open an link in an email. When I click on the link, I expect a new tab to open, but it doesn't. Instead, the App Tab the contains gmail goes to the linked website. How can I stop this from happening?

*Tabberwocky: https://addons.mozilla.org/firefox/addon/14439
*Tab Mix Plus: https://addons.mozilla.org/firefox/addon/1122

Browser will not open links to other websites using linpus on acer 1

i have an acer 1 running linpus and firefox 2.0.014, i can't update it for some reason and now it has stopped browsing links to other websites, i have cleared all the history, caches, allowed the websites to accept cookies but still nothing any one out there help me? this is being posted from my desktop as my acer can't interact with the web....

Do you mean you cannot upgrade Firefox version or upgrade the plug-in?
I suggest you can forword your detail to Linpus HelpDesk ([email protected]).

Producing links to other websites

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What has this got to do with Adobe Acrobat - are you uploading a PDF file?
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Links to Other Websites

Hi -
I am setting up a new website and am pretty new to this. I'm not sure if this can be done but can you create links to other websites (not just a page within my site)? i.e. Can I have a link to a friend's website?
Thank you for the help!
Regards,
Pete

Absolutely!
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If you use text as your link, you can format it at to colour, rollover colour, underline or not, etc.
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Same sql query with multiple database links

Hi All,
i want to execute an sql query for a SELECT LIST Item. which should use database links in it's query.
i'm having a list of database links in the region. say :LOC which is having 10 items each linking to different databases.
i want to use following query for another item in same page.
select customer_name from working_lines@:LOC where
phone_no:phone_no
can i do this.
Thank you All.

What we have done before is to create a report based on a PL/SQL procedure that returns a SQL statement.
The PL/SQL code grabs the "selected" database link from :LOC and parses the SQL QUERY you want to execute replacing some token (like [LINK]) with '@DBNAME'.
Lets say your SQL statement is coded like this:
mySQL := 'SELECT cust_name FROM working_lines[LINK] where phone_no = :Phone;'
Then all you would have to do to replace '[LINK]' with the proper DB alias would be:
mySQL := REPLACE(mySQL, '[LINK]', '@'||:LOC);
and then return the new SQL ...
if :LOC has something like 'V10GPROD' your SQL would look like :
SELECT cust_name FROM working_lines@V10GPROD where phone_no = :Phone;
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SQL query that returns exclusive rows from groups

I'm using modified scott/tiger data for this.
I've got two tables
DEPT_X
DEPTNO     DNAME             LOC     CODE_ID     SUB_DEPTNO
10     ACCOUNTING     NEW YORK 111     101
10     SALES             ATWN      111     102
10     SALES             BTWN      112     103
20     RESEARCH     DALLAS      111     201
20     RESEARCH     CTWN      111     202
30     SALES             CHICAGO      111     301
40     OPERATIONS     BOSTON      112     401and
BI_PD
CODE_ID     PD_TYPE     BI_TYPE
111          -1
112     -1     I want to write a query that joins the code_ids of the two tables and lists out either only the records from DEPT_X who's code_ids have a -1 in the PD_TYPE(112) column and none of the code_ids that have a -1 in the BI_TYPE(111) column for each department or if that department has code_ids for the BI_TYPE (111), list out those rows. So for Deptno 10 you'll only get the row with SUB_DEPTNO = 103. But if for that DEPTNO= 20 you'll get the rows for both SUB_DEPTNO = 201 and 202.
So the result should look like
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10          103
20          201
20          202
30          301.
Basically I just want rows from each department that have code_ids = 111 not to show up if there are code_ids = 112.
What is the query to do this?
Message was edited by:
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Message was edited by:
user623359
Message was edited by:
user623359
Message was edited by:
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Message was edited by:
user623359

One way could be:
Connected to:
Oracle Database 10g Enterprise Edition Release 10.2.0.3.0 - 64bit Production
With the Partitioning, OLAP and Data Mining options
SQL> with dept_x as (
2      select 10 deptno, 'ACCOUNTING' dname, 'NEW YORK' loc, 111 code_id, 101 sub_deptno from dual
union all
3      select 10, 'SALES', 'ATWN', 111, 102 from dual union all
4      select 10, 'SALES', 'BTWN', 112, 103 from dual union all
5      select 20, 'RESEARCH', 'DALLAS', 111, 201 from dual union all
6      select 20, 'RESEARCH', 'CTWN', 111, 202 from dual union all
7      select 30, 'SALES', 'CHICAGO', 111, 301 from dual union all
8      select 40, 'OPERATIONS', 'BOSTON', 112, 401 from dual ),
9 --
10 bi_pd as(
11      select 111 code_id, null pd_type, -1 bi_type from dual union all
12      select 112, -1, null from dual),
13 --
14 t as(
15      select a.deptno,a.sub_deptno from dept_x a, bi_pd b
16      where a.code_id = b.code_id and b.pd_type = -1)
17 --
18 select a.deptno,a.sub_deptno
19 from dept_x a, bi_pd b
20 where a.code_id = b.code_id and b.bi_type = -1 and
21        (a.deptno) not in (select deptno from t)
22 union
23 select deptno,sub_deptno from t;
    DEPTNO SUB_DEPTNO
        10        103
        20        201
        20        202
        30        301
        40        401

Can a report be developed using free hand SQL(Sql Query) using a DB Link

Hello All,
A report to be developed based on query in OBIEE dashboards
Select Query -----1
UNION
Select Query------2
First select query is coming from one database schema and second is coming from the other.
Is there any way to develop the report using free hand SQL based on a DB link?
Is there any feature to use Database link (DB link)?
Thank in Advance,
SMA

What you ask is the direct database request capabilities :
http://gerardnico.com/wiki/dat/obiee/presentation_service/obiee_direct_database_request
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Cheers
Nico

Get column names into a VB program, for an SQL query that joins tables

use [mydatabase]
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Where can I download photoshop 12 elements the tech gave me a link that has no link to download

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SQL Query to get Testcases linked with a SAPTAO component in HP ALM 11

Hi,
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PL/SQL query that has a link to other website

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