Please help in this sql query

I have table a with columns ca1,ca2,ca3
and I have a table b with columns cb1, cb2,cb3
and a and b tables are related with a table's ca2 and b table's cb2
ca1 not null,ca2 can be null and cb2 is a not null column, cb3 not null
I want the output of ca1 and cb3
If ca2 is null then the output should contain ca1 value and null for cb3
If ca2 is not nulll comparing both it has to return cb3 value..
Could anybody help me in tis???
Thanks in advance..

Hope I understood your requirement.
SELECT NVL(ca2,ca1) ca1, DECODE(ca2,NULL,ca2,cb3) cb3
FROM a, b
WHERE ca2=cb2

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How many garments has each dressmaker constructed? You should give the number of garments and the name, house number and post code of each dressmaker.
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Not to be a jerk, but this forum is really not intended for homework. Show a little effort, and try it out. Post some results, and maybe someone will help you out. Getting others to do your homework will not help you when you get out of school.

Please need help on this SQL query ..

hi peers,
here is my situation :
Field1 Field2 Field3
xa group1 req_id1
xb group2 req_id2
xc group3 req_id3
xa group4 req_id4
xb group5 req_id5
i need to pull only the group3 record that comes right away after group2. Req_id's are in chronological order and groupx are texts
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thanks

Hi,
Use the analytic LAG function to get a value from an earlier row:
WITH     got_prev_field2     AS
     SELECT     field1, field2, field3
     ,     LAG (field2) OVER (ORDER BY field3)     AS prev_field2
     FROM     my_situation
SELECT     field1, field2, field3
FROM     got_prev_field2
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;Like all analytic functions, LAG is computed after the WHERE clause is applied. To use the value returned by LAG in a WHERE clause, we have to compute it in a sub-query.
I hope this answers your question.
If not, post a little sample data (CREATE TABLE and INSERT statements, relevant columns only), and also post the results you want from that data.

Please help me with SQL query...

I need some help to figure out how to do this query...
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1 1234 10:20
1 5FE2 10:55
1 EA33 10:50
2 4667 11:10
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select
country.country,
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hi All,
I have the below query -
SELECT DISTINCT OFFC.PROV_ID
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WHEN OFFC.WK_DAY ='TUESDAY' THEN 2
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WITH UR;
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thanks,
iamhere

Hi,
Welcome to the forum!
That's called a Pivot .
Instead of having 1CASE expression, have 14, one for the opening and one for the closing time each day, and do GROUP BY to combine them onto one row.
SELECT       OFFC.PROV_ID
,       MIN (CASE WHEN OFFC.WK_DAY ='MONDAY'    THEN OFFC.OFFC_OPENG_TIME END)     AS mon_opn
,       MIN (CASE WHEN OFFC.WK_DAY ='MONDAY'    THEN OFFC.OFFC_CLSNG_TIME END)     AS mon_cls
,       MIN (CASE WHEN OFFC.WK_DAY ='TUESDAY'   THEN OFFC.OFFC_OPENG_TIME END)     AS tue_opn
,       MIN (CASE WHEN OFFC.WK_DAY ='TUESDAY'   THEN OFFC.OFFC_CLSNG_TIME END)     AS tue_cls
FROM        GGDD.PROV_OFFC_HR OFFC
WHERE       OFFC.PROV_ID     = '0000600'
GROUP BY offc.prov_id
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The staement above works in Oracle 8.1 and up, but there's a better way (SELECT ... PIVOT) available in Oracle 11. What version are you using? (It's always a good idea to include this when you post a question.)
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Help Needed In SQL Query

HI All,
Oracle sql clarification required
Sample Table:
empno empname Job mgr_id hire_date salary deptno
7788 SCOTT ANALYST 7566 19-APR-87 3000 20
7902 FORD ANALYST 7566 03-DEC-81 3000 20
7934 MILLER CLERK 7782 23-JAN-82 1300 10
7900 JAMES CLERK 7698 03-DEC-81 950 30
7369 SMITH CLERK 7902 17-DEC-80 800 20
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Need "single / one" sql for this requirement statement:
There will be 2 drop down boxes (1st - Job list, 2nd - empno) in the form in which the following result set is expected
1) When user selects value from 1st drop down box (job) as "ANALYST" leaving the second drop down unselected, the result expected is 2 (no. of rows for that job)
2) When user selects value from 1st drop down box (job) as "ANALYST" and the value from 2nd drop down box as 7902, the result expected is 1 (no of rows for that job and empno)
Sqls which I have tried from my side (given below) didn't give the expected result and please do help me in correcting this
select count(1) from scott.emp where job='ANALYST' and ( empno = :empno or empno is null ) ;
Please help for this requirement. Any help is deeply appreciated.
Thanks
Zaheer

Hi,
welcome to the forum.
Please read SQL and PL/SQL FAQ
When you put some code or output please enclose it between two lines starting with {noformat}{noformat}
i.e.:
{noformat}{noformat}
SELECT ...
{noformat}{noformat}
For your question the following will both work:SQL> select * from emp
where job='ANALYST' and (empno =:empno or :empno is null)
EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
7788 SCOTT ANALYST 7566 19/04/1987 00:00:00 3000 20
7902 FORD ANALYST 7566 03/12/1981 00:00:00 3000 20
2 rows selected.
SQL> select * from emp
where job='ANALYST' and empno =NVL(:empno, empno)
EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
7788 SCOTT ANALYST 7566 19/04/1987 00:00:00 3000 20
7902 FORD ANALYST 7566 03/12/1981 00:00:00 3000 20
2 rows selected.
Regards.
Al

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Need help on oracle sql query

Hi team,
Please help me on below query,
I have table like given below
Tran_Id tran_date   amount. Actorid
   1.         10-apr-15.   100.         1
   2.         11-apr-15.   100.         1
   3.         11-apr-15.   900.         1
   4.         12-apr-15.   100.         1
   5.         13-apr-15.   350.         1
   6.         14-apr-15.   400.         1
Now please find the query,
I want all the actor ids whos tran amount
>1500 and the date when the tran amount
Has breached
Ex:
Actor-id. Breached-date.    Total
1.              13-apr-15.            1900
How can I write a query for above requirement?
Regards,
Rajendra

Your solution (same as Saubhik's) is incorrect. Look at source data - multiple transactions can occur same day. Therefore, your qury will return wrong results if breached amount is 1000:
with trans as (
select 1 tran_Id, to_date('10-apr-15', 'dd-mon-yy') tran_date, 100 amount, 1 actorid from dual union all
select 2, to_date('11-apr-15', 'dd-mon-yy'), 100, 1 from dual union all
select 3, to_date('11-apr-15', 'dd-mon-yy'), 900, 1 from dual union all
select 4, to_date('12-apr-15', 'dd-mon-yy'), 100, 1 from dual union all
select 5, to_date('13-apr-15', 'dd-mon-yy'), 350, 1 from dual union all
select 6, to_date('14-apr-15', 'dd-mon-yy'), 400, 1 from dual union all
select 7, to_date('12-apr-15', 'dd-mon-yy'), 300, 2 from dual union all
select 8, to_date('13-apr-15', 'dd-mon-yy'), 1200, 2 from dual union all
select 9, to_date('14-apr-15', 'dd-mon-yy'), 300, 2 from dual union all
select 10, to_date('15-apr-15', 'dd-mon-yy'), 300, 2 from dual
trans_running_tot as (
select tran_id, tran_date,
sum(amount) over (partition by actorid order by tran_date) tot_amt, actorid
from trans
trans_ranked as (
select actorid,tran_id, tran_date,
rank() over (partition by actorid order by tot_amt) rk
from trans_running_tot
where tot_amt > 1000
select * from trans_ranked where rk=1
   ACTORID    TRAN_ID TRAN_DATE         RK
         1          2 11-APR-15          1 -- here total amount was only 200
         1          3 11-APR-15          1
         2          8 13-APR-15          1
SQL>
As you can see, 2 rows were returned for actor 1. Why? Default for analytic ORDER BY is RANGE BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW. Therefore, all rows with same transation_date will fall into same window:
SQL> with trans as (
2   select 1 tran_Id, to_date('10-apr-15', 'dd-mon-yy') tran_date, 100 amount, 1 actorid from dual union all
3   select 2, to_date('11-apr-15', 'dd-mon-yy'), 100, 1 from dual union all
4   select 3, to_date('11-apr-15', 'dd-mon-yy'), 900, 1 from dual union all
5   select 4, to_date('12-apr-15', 'dd-mon-yy'), 100, 1 from dual union all
6   select 5, to_date('13-apr-15', 'dd-mon-yy'), 350, 1 from dual union all
7   select 6, to_date('14-apr-15', 'dd-mon-yy'), 400, 1 from dual union all
8   select 7, to_date('12-apr-15', 'dd-mon-yy'), 300, 2 from dual union all
9   select 8, to_date('13-apr-15', 'dd-mon-yy'), 1200, 2 from dual union all
10   select 9, to_date('14-apr-15', 'dd-mon-yy'), 300, 2 from dual union all
11   select 10, to_date('15-apr-15', 'dd-mon-yy'), 300, 2 from dual
12   )
13 select tran_id, tran_date,
14    sum(amount) over (partition by actorid order by tran_date) tot_amt, actorid
15 from trans
16 /
   TRAN_ID TRAN_DATE    TOT_AMT    ACTORID
         1 10-APR-15        100          1
         2 11-APR-15       1100          1
         3 11-APR-15       1100          1
         4 12-APR-15       1200          1
         5 13-APR-15       1550          1
         6 14-APR-15       1950          1
         7 12-APR-15        300          2
         8 13-APR-15       1500          2
         9 14-APR-15       1800          2
        10 15-APR-15       2100          2
10 rows selected.
SQL>
So correct solution is to ORDER BY transation id. Also, just in case if amount can be 0, we should add tranaction id when ordering by sum:
with trans as (
select 1 tran_Id, to_date('10-apr-15', 'dd-mon-yy') tran_date, 100 amount, 1 actorid from dual union all
select 2, to_date('11-apr-15', 'dd-mon-yy'), 100, 1 from dual union all
select 3, to_date('11-apr-15', 'dd-mon-yy'), 900, 1 from dual union all
select 4, to_date('12-apr-15', 'dd-mon-yy'), 100, 1 from dual union all
select 5, to_date('13-apr-15', 'dd-mon-yy'), 350, 1 from dual union all
select 6, to_date('14-apr-15', 'dd-mon-yy'), 400, 1 from dual union all
select 7, to_date('12-apr-15', 'dd-mon-yy'), 300, 2 from dual union all
select 8, to_date('13-apr-15', 'dd-mon-yy'), 1200, 2 from dual union all
select 9, to_date('14-apr-15', 'dd-mon-yy'), 300, 2 from dual union all
select 10, to_date('15-apr-15', 'dd-mon-yy'), 300, 2 from dual
trans_running_tot as (
select tran_id, tran_date,
sum(amount) over (partition by actorid order by tran_id) tot_amt, actorid
from trans
trans_ranked as (
select actorid,tran_id, tran_date,
rank() over (partition by actorid order by tot_amt,tran_id) rk
from trans_running_tot
where tot_amt > 1000
select * from trans_ranked where rk=1
   ACTORID    TRAN_ID TRAN_DATE         RK
         1          3 11-APR-15          1
         2          8 13-APR-15          1
SQL>
SY.

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ENDIF.
lv_attr_name = 'BU_PARTNER'.
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<a href="http://">http://www.sapdevelopment.co.uk/dictionary/shelp/shelp_elementary.htm</a>
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After having experienced similar problems and having it back to work, I have a few suggestions:
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Please help in this sql query

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