Please help with Applet in New Window?

I am trying to write a html page which opens appet into new window.
Tha'ts what i want. My applet has user/passwd authentication and then
makes a socket connection. However i am facing tow problems(kind of one):
1. If i close my applet browser window, socket connection is still active.
(if i use appletviewer.. every thing works perferctly)
2. on my web page, if i click again to open my appet window it refreshes my applet window again ....if it 's already opened. in other words, my applet does not really gets reloaded from my webserver..
Please advise..
Here is my HTML Code
index.html
<HEAD>
<SCRIPT TYPE="text/javascript">
<!--
function popup(mylink, windowname)
if (! window.focus)return true;
var href;
if (typeof(mylink) == 'string')
   href=mylink;
else
   href=mylink.href;
window.open(href, windowname, 'width=840,height=630,scrollbars=yes');
return false;
</SCRIPT>
<A
   HREF="NewJApplet.html"
   onClick="return popup(this, 'notes')">Loads Streamer </A>
</HEAD>NewJApplet.html
<HTML>
<BODY>
<P>
<APPLET code="NewJApplet.class" width=800 height=560></APPLET>
</P>
<HR WIDTH="100%"><FONT SIZE=-1>
</BODY>
</HTML>

You can open a frame, and have a very small applet on your html page. Perhaps you can set the applet size to (0, 0).
You could also open a new browser window that is not resizable and contains your applet in its full size and without the toolbar buttons and menubar. I think you need javascript to configure the new browser window like that.

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Microsoft (R) Windows Debugger Version 6.12.0002.633 AMD64
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Use !analyze -v to get detailed debugging information.
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SYSTEM_SERVICE_EXCEPTION (3b)
An exception happened while executing a system service routine.
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nt!KeReleaseSemaphore+1e4
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r11=fffff8a00a3e3130 r12=0000000000000001 r13=fffff880009ec180
r14=fffff880009b3101 r15=fffffa8010760948
iopl=0         nv up ei pl nz na po cy
cs=0010 ss=0018 ds=002b es=002b fs=0053 gs=002b             efl=00010207
nt!KeReleaseSemaphore+0x1e4:
fffff800`02ae88a4 0fb6462b        movzx   eax,byte ptr [rsi+2Bh] ds:002b:0a1001c9`ea0fd678=??
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version 11g
please Help me in assiging new person id for dirrerent persons if there middle name is different
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WITH NAMES AS(
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o/P Required
ID    LAST_NAME    FIRST_NAME    MIDDLE_NAME
47540310    WO      ROBERT          C
99999990    WO      ROBERT          W                   -- New Sequence Number
99999991     WO      ROBERT         X                   -- New Sequence Number
47540300    AMATUZIO    ALBERT    J
99999992    AMATUZIO    ALBERT                          -- New Sequence Number
99999993    AMATUZIO    ALBERT    L                     -- New Sequence Number
17540300    AMARONE    JOSEPH    J
17540300    AMARONE    JOSEPH    Thanks
Edited by: new learner on Jun 7, 2012 2:12 PM

I don't understand what this line is doing:
FIRST_VALUE (fn_get_person_id) -- sequence for the functionI have the impression that the only difference with my query is to select distinct values not to consider duplicates. Correct me if I'm wrong.
To me this one should give the same result as your query:
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new ids from sequence*/
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                 FROM   DUAL
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               SELECT   47540310 ID,
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                        'ROBERT' FIRST_NAME,
                        'W' MIDDLE_NAME
                 FROM   DUAL
               UNION ALL
               SELECT   47540310 ID,
                        'WO' LAST_NAME,
                        'ROBERT' FIRST_NAME,
                        'X' MIDDLE_NAME
                 FROM   DUAL
               UNION ALL
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                 In the below case we have two values that can equate with null so assign three diffrent ids */
               SELECT   47540300 ID,
                        'AMATUZIO' LAST_NAME,
                        'ALBERT' FIRST_NAME,
                        'J' MIDDLE_NAME
                 FROM   DUAL
               UNION ALL
               SELECT   47540300 ID,
                        'AMATUZIO' LAST_NAME,
                        'ALBERT' FIRST_NAME,
                        NULL MIDDLE_NAME
                 FROM   DUAL
               UNION ALL
               SELECT   47540300 ID,
                        'AMATUZIO' LAST_NAME,
                        'ALBERT' FIRST_NAME,
                        'L' MIDDLE_NAME
                 FROM   DUAL
               UNION ALL
               /* Scenario3 NULL can be equal to any value if there is only one value to equate with
                 In the below case we have ONE VALUE that can equate with null so DONT ASSIGN ANY IDS*/
               SELECT   17540300 ID,
                        'AMARONE' LAST_NAME,
                        'JOSEPH' FIRST_NAME,
                        'K' MIDDLE_NAME
                 FROM   DUAL
               UNION ALL
               SELECT   17540300 ID,
                        'AMARONE' LAST_NAME,
                        'JOSEPH' FIRST_NAME,
                        'Y' MIDDLE_NAME
                 FROM   DUAL
               UNION ALL
               SELECT   17540300 ID,
                        'AMARONE' LAST_NAME,
                        'JOSEPH' FIRST_NAME,
                        NULL MIDDLE_NAME
                 FROM   DUAL
               UNION ALL
               SELECT   17540300 ID,
                        'AMARONE' LAST_NAME,
                        'JOSEPH' FIRST_NAME,
                        'M' MIDDLE_NAME
                 FROM   DUAL
               UNION ALL
               SELECT   17540300 ID,
                        'AMARONE' LAST_NAME,
                        'JOSEPH' FIRST_NAME,
                        'M' MIDDLE_NAME
                 FROM   DUAL
               UNION ALL
               SELECT   99999999 ID,
                        'LO' LAST_NAME,
                        'CHRISTY' FIRST_NAME,
                        NULL MIDDLE_NAME
                 FROM   DUAL
               UNION ALL
               SELECT   99999999 ID,
                        'LO' LAST_NAME,
                        'CHRISTY' FIRST_NAME,
                        'M' MIDDLE_NAME
                 FROM   DUAL
               UNION ALL
               SELECT   99999999 ID,
                        'LO' LAST_NAME,
                        'CHRISTY' FIRST_NAME,
                        'M' MIDDLE_NAME
                 FROM   DUAL),
sel_names AS ( SELECT id
                          , last_name
                          , first_name
                          , middle_name
                          , COUNT (middle_name) OVER (PARTITION BY id ORDER BY middle_name) cnt
                          , ROW_NUMBER () OVER (PARTITION BY id ORDER BY middle_name) rown
                       FROM (SELECT DISTINCT * FROM names) -- use SELECT DISTINCT here to remove duplicates
                   ORDER BY 1, 2, 3, 4
SELECT 8888888 new_id, id, last_name, first_name
     , middle_name
FROM sel_names
WHERE cnt > 1 AND rown > 1;As you can see I have only replace the the table with an inline view using SELECT DISTINCT *
                       FROM (SELECT DISTINCT * FROM names) -- use SELECT DISTINCT here to remove duplicatesFor the new id I have put a dummy value 888888, you may use a function or a sequence according to your needs.
Regards.
Al

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