Printing exactly 2 decimal places

Question

I'm trying to print my double type variables to exactly 2 places. but numbers such as 3.00 and 124.00 keep printing as 3.0 and 124.0. Is there an easy way to force the printing to two decimal places on a primitive double type value without having to cast it to a Double object and playing around with NumberFormat and all that entails?
thanks much,
jh

Answer 1

darelln has exactly the right answer, except that you must do the thing you don't want to do. If it were me, I'd go with his example. It's less work and much cleaner.
import java.text.*;
public class DoubleTest {
static double[] numbers = {3000, 124.12, 123.122, 3.0, 124.0, 10.2, 12.14, 1234.55};
static final NumberFormat f = new DecimalFormat("#.00");
    public static void main(String [] args) {
        System.out.println("Goofy way!\n");
        for (int i=0 ; i<numbers.length ; i++) {
            printD(numbers);
System.out.println("\nRight way!\n");
for (int i=0 ; i<numbers.length ; i++) {
System.out.println(f.format(numbers[i]));
static void printD(double dbl) {
if (dbl % 10 == 0) {
System.out.println(dbl + "0");
} else {
String sdbl = "" + dbl;
String predot = sdbl.substring(0, sdbl.indexOf("."));
String atdot = sdbl.substring(sdbl.indexOf("."), sdbl.length());
String postdot = sdbl.substring(sdbl.indexOf(".") + 1, sdbl.length());
if (postdot.length() == 2) {
System.out.println(sdbl);
} else if (postdot.length() < 2) {
System.out.println(predot + "." + postdot.substring(0,1) + "0");
} else {
System.out.println(predot + "." + postdot.substring(0,2));
java DoubleTest
Goofy way!
3000.00
124.12
123.12
3.00
124.00
10.20
12.14
1234.55
Right way!
3000.00
124.12
123.12
3.00
124.00
10.20
12.14
1234.55
and the results are identical!