Problem in passing parameters in command line in desktop
Hi,
I am trying to generate reports from command line (Oracle Discoverer 4i Version 4.1.42.04.00) but I am facing problems when I try to pass date or numeric parameters. It seems to work with strings
The following command is successful when i pass string as parameters
C:\orant\DISCVR4\dis4usr.exe /connect reports/reports@orcl /opendb load_report_1 /batch /sheet 2 /parameter "P Date" "31-JUL-2006 Month End" /export xls c:\Temp\load_report_!
But in the following commands the command line execution stops when a worksheet with parameters is encountered. Once then parameter is entered the command line is executed successfully. In these problem cases it seems like the /parameter option is not being recognized. I have tried to pass parameters with double quotes, single quotes, without any quotes.
C:\orant\DISCVR4\dis4usr.exe /connect reports/reports@orcl /opendb "load report 2" /sheet 3 /parameter "Select P Day" "20-JUN-2006" /batch /export xls c:\Temp\load_Report_2
C:\orant\DISCVR4\dis4usr.exe /connect reports/reports@orcl /opendb "load report 3" /batch /sheet 1 /parameter "Enter Date Using Format YYYYMMDD" 20060703 /export xls c:\Temp\load_report_3
The only difference I can see is that I have not used double quotes in the command line that is successful in generating reports with parameters.
Any inputs will be appreciated - we are stuck in our project due to this issue. Many thanks.
Warm regards
Sucharita
Hi
I work in the same team as the original poster.
We tried by changing NLS_DATE_FORMAT for the oracle_home.
Just to clarify our issue I am describing it one more time below -
Using Disc desktop (4.1.42) we are trying to run the reports using command line interface. Any report that takes character input for the parameters ,is running fine in the batch mode without prompting.
Any report that takes Date/Numeric input for the parameters, though in batch mode, is prompting for user to give the parameters.We tried with quotes as well.
For Example -
1. Character input : when we run this command supplying the input parameter values (which are characters), report runs fine without prompting for values.
C:\orant\DISCVR4\dis4usr.exe /connect rep/rep@orals /opendb Schd_Report /batch /sheet 2 /parameter "Process Date" "31-JUL-2006 Month End" /export xls c:\audit_report_5
2. Date Input -
C:\orant\DISCVR4\dis4usr.exe /connect rep/rep@orals /opendb "DLS.Arrears Reports" /batch /sheet 1 /parameter "Please Enter Date Using Format YYYYMMDD" 20060703 /export xls c:\CA_arr
When we submit this we get a window prompting for the input values. So his is the issue.
Thanks
Raman
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2,b
3,c
4,d
$
$Note that the "test6.lst" on my system had the prompt "SQL>". You will have to tweak that regular expression so that it works for the prompt in your "test6.lst" file.
pratz -
Problem with tokenized input from command line
I am trying to take an input from the command line, parse it to tokens and perform whatever operation is needed depending on the name of the token, on a binary tree of stacks for example, if i type 1 2 1 3 printLevelOrder, then the root of the tree should have 3, 2,1 in the stack, the left child should have 1 and the right child should be empty. and then a level order print of the tree should be performed.
however what is happening when i run this code is the numbers are being put into the right stacks of the tree, but any commands such as printLevelOrder or PrintPopRoot are entering the code that is for placing numbers onto the stack instead of executing that command and skipping past this piece of code.
so my question is, why is the if statement if (word =="printLevelOrder") not being executed when thats whats in the word ?
example input and output shown below code fragment.
try {
BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
String line = "";
while (line != "***") {
System.out.print("> prompt ");
line = in.readLine();
StringTokenizer tokenizer = new StringTokenizer(line," ");
String word = new String();
while (tokenizer.hasMoreTokens()) {
word = tokenizer.nextToken();
boolean notCommand = true;
if (word =="printLevelOrder") {
theTree.printLevelOrder();
System.out.println("(word ==printLevelOrder)");
notCommand=false;
if (word == "printPopLevelOrder") {
theTree.printPopLevelOrder();
notCommand=false;
if (word == "printPopInorder") {
theTree.printPopInorder();
notCommand=false;
if (word == "printPopPreorder") {
theTree.printPopPreorder();
notCommand=false;
if (word == "printPopRoot") {
theTree.printPopRoot();
notCommand=false;
if (word == "***") {
notCommand=false;
if (notCommand == true) {
System.out.println("(notCommand == true)");
boolean notPlaced = true;
int v = 1;
while ((notPlaced==true) && (v < theTree.size())) {
if (theTree.element(v).isEmpty()) {
theTree.element(v).push(Integer.valueOf(word));
System.out.println("Inserting"+word);
System.out.println("in empty stack at location: "+v);
notPlaced=false;
if (notPlaced==true) {
if ( Integer.valueOf(word) >= Integer.valueOf( theTree.element(v).top().toString() ) ) {
theTree.element(v).push(Integer.valueOf(word));
System.out.println("Inserting"+word);
System.out.println("in stack at location: "+v);
notPlaced=false;
v++;
}valid inputs: int value, printLevelOrder, printPopLevelOrder, printPopInorder, p
rintPopPreorder, printPopRoot, *** to quit
prompt 1 3 2 4 2 printLevelOrder(notCommand == true)
Inserting1
in empty stack at location: 1
(notCommand == true)
Inserting3
in stack at location: 1
(notCommand == true)
Inserting2
in empty stack at location: 2
(notCommand == true)
Inserting4
in stack at location: 1
(notCommand == true)
Inserting2
in stack at location: 2
(notCommand == true)
Exception in thread "main" java.lang.NumberFormatException: For input string: "printLevelOrder"
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48)
at java.lang.Integer.parseInt(Integer.java:447)
at java.lang.Integer.valueOf(Integer.java:553)
at TreeStack.main(TreeStack.java:73)
Press any key to continue . . .lol aww, shame that you forgot to do that. i had 10 / 10 for mine, and seing as the deadline is now well and trully over,
here is the entire source for anybody who was following the discussion or whatever and wanted to experiment.
additional files needed >
http://users.cs.cf.ac.uk/Paul.Rosin/CM0212/Stack.java
http://users.cs.cf.ac.uk/Paul.Rosin/CM0212/ArrayStack.java
http://users.cs.cf.ac.uk/Paul.Rosin/CM0212/StackEmptyException.java
http://users.cs.cf.ac.uk/Paul.Rosin/CM0212/StackFullException.java
/*TreeStack.java - reads command line input of values and assigns them to stacks in a binary tree and performs
operations on the ADT. valid inputs: <int>, printLevelOrder, printPopLevelOrder,
printPopInorder, printPopPreOrder, printPopRoot. Terminates on invalid input.
Written by George St. Clair.
S/N:0208456 22/11/2005
import java.util.Vector;
import java.io.*;
import java.util.StringTokenizer;
public class TreeStack {
private final int TREE_CAPACITY = 7 + 1;
private final int STACK_CAPACITY = 10;
Vector tree = new Vector(TREE_CAPACITY) ;
//collect input from command line, add values to stacks at nodes of the teee
//and perform required operations on the treestack
public static void main (String [] args) {
//create a tree of stacks
TreeStack theTree = new TreeStack ();
try {
//collect standard input
BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
String line = "";
while (line != null) {
System.out.print("");
line = in.readLine();
//tokenise input
StringTokenizer tokenizer = new StringTokenizer(line," ");
String word = new String();
while (tokenizer.hasMoreTokens()) {
//assign word to the token
word = tokenizer.nextToken();
boolean notCommand = true;
//perform operation on treestack depending on what word is
if (word.equals("printLevelOrder")) {
System.out.println("printLevelOrder");
theTree.printLevelOrder();
notCommand=false;
if (word.equals("printPopLevelOrder")) {
System.out.println("printPopLevelOrder");
theTree.printPopLevelOrder();
notCommand=false;
if (word.equals("printPopInorder")) {
System.out.println("printPopInorder");
theTree.printPopInorder();
notCommand=false;
if (word.equals("printPopPreorder")) {
System.out.println("printPopPreorder");
theTree.printPopPreorder();
notCommand=false;
if (word.equals("printPopRoot")) {
System.out.println("printPopRoot");
theTree.printPopRoot();
notCommand=false;
//if word was not a command it must be a number
if (notCommand == true) {
boolean notPlaced = true;
int v = 1;
//starting at the root, find suitable place for number
while ((notPlaced==true) && (v < theTree.size())) {
//if the stack at v is empty, number goes here
if (theTree.element(v).isEmpty()) {
theTree.element(v).push(Integer.valueOf(word));
System.out.println("inserting: "+word);
System.out.println("in empty stack at location: "+(v-1));
notPlaced=false;
//if the stack is not empty
if (notPlaced==true) {
//if the value on the top of the stack is smaller than number, number goes onto the stack
if ( Integer.valueOf(word) > Integer.valueOf( theTree.element(v).top().toString() ) ) {
theTree.element(v).push(Integer.valueOf(word));
System.out.println("inserting: "+word);
System.out.println("in stack at location: "+(v-1));
notPlaced=false;
//if that node was no good, check the next one for suitability
v++;
catch (Exception e) {
//occurs when user inputs something that is neither a command, or a number, or upon EOF, or stack is full
public TreeStack () {
//create the TreeStack ADT by adding stacks in the vector, note vector 0 is instantiated but not used.
for (int i = 1;i<=TREE_CAPACITY;i++)
tree.add(new ArrayStack(STACK_CAPACITY));
public int size() {
//return the size of the tree +1 (as 0 is not used)
return tree.size();
public ArrayStack element (int v) {
//return the ArrayStack at v
return (ArrayStack)tree.get(v);
public int leftChild (int v ) {
//return left child of v
return v*2;
public int rightChild (int v ) {
//return the right child of v
return v*2+1;
public boolean children (int v ) {
//search for children of v and return true if one exists
for (int i =v;i<size();i++) {
if (i/2==v ) {
//left child found at i
return true;
if ((i-1)/2==v ) {
//right child found at i
return true;
//no children found
return false;
public boolean isInternal (int v ) {
//test whether node v is internal (has children)
if (children (v)== true) {
//has children
return true;
return false;
//print the top value in each stack encountered on a level-order traversal of tree
public void printLevelOrder() {
//for every node of tree v
for (int v = 1;v<size();v++) {
if (!element(v).isEmpty() ) {
//print the top value in stack v
System.out.println(" "+element(v).top());
else {
//stack at v is empty
System.out.println(" -");
//pop off and print the top value in each stack encountered on a level-order traversal of tree
public void printPopLevelOrder () {
//pop off and print the top value in stack v
for (int v = 1;v<size();v++) {
//for each node of tree v
if (!element(v).isEmpty() ) {
//if v isnt empty print the top value in stack v
System.out.println(" "+element(v).top());
//pop the top value in the stack at v
element(v).pop();
else {
//stack at v is empty
System.out.println(" -");
//pop off and print the top value in each stack encountered on an in-order traversal of tree
public void printPopInorder () {
printPopInorder (1);
public void printPopInorder (int v) {
boolean isInternal = false;
if (isInternal (v)) {
//use a boolean for isInternal to save on running the method twice
isInternal = true;
//recursively search left subtree
printPopInorder (leftChild(v));
//pop off and print the top value at v
if (element(v).isEmpty() ) {
//stack at v is empty
System.out.println(" -");
else {
//if v isnt empty print the top value in stack v then pop
System.out.println(" "+element(v).top());
element(v).pop();
if (isInternal ) {
//recursively search right subtree
printPopInorder (rightChild(v));
//pop off and print the top value in each stack encountered on an pre-order traversal of tree
public void printPopPreorder() {
printPopPreorder(1);
public void printPopPreorder(int v) {
//pop off and print the top value at v
if (!element(v).isEmpty() ) {
//if v isnt empty print the top value in stack v then pop
System.out.println(" "+element(v).top());
element(v).pop();
else {
//stack at v is empty
System.out.println(" -");
if (isInternal (v)) {
//recursively search left and right subtrees
printPopPreorder (leftChild(v));
printPopPreorder (rightChild(v));
//pop off and print all values from the stack at the root
public void printPopRoot (){
//while the root stack has values left
while (!element(1).isEmpty()) {
//print, then pop
System.out.println(" "+element(1).top());
element(1).pop();
} -
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