Problem with leap years in Calendar demo

I've just looked at the Calendar demo component:
http://developers.sun.com/prodtech/javatools/jscreator/reference/codesamples/samplecomps/calendar.html
There is a little bug : it doesn't seem to manage leap years.
Go to february 2008, and you won't the the 29th of February 2008 in the calendar.
Please try to correct this bug quickly. It is a bad idea to let people get source code with bugs as a a demo.
Thanks
Thibaut REGNIER
See TastePhone, my Open Source app made whith Java Studio Creator:
http://www.club-java.com/TastePhone/J2ME/MIDP_mobile.jsp

The Calendar Component does take account of the leap year.
If you look at the code, it has
if ((month == FEBRUARY) && (isLeapYear(year))) numCells++;Not sure what went wrong. I'll take a look at it.
- Winston

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How to do a date validation with leap years

I'm doing a date validation program in my Java class, and well it's pretty hard (for me that is). I have to be able to type in a date, have it say whether it's a leap year or not, and print out the number of days in the month. It seems pretty straight forward, but I get confused on trying to do the 'if else' statements and even the simplest things like getting the day prompting to work. >< The years I'm doing only goes through 1000 to 1999, so that's why those numbers are there. The program isn't complete, so if anyone could help show me what I'm doing wrong in the areas I'm working on then I'd appreciate it...and I'm still kind of in the basics of Java so if you do hint me with some code then I'd appreciate it if it was stuff that's not too advanced so yea.
// Dates.java
// Determine whether a 2nd-millenium date entered by the user
// is valid
import java.util.Scanner;
public class Dates
public static void main(String[] args)
int month, day, year; //date read in from user
int daysInMonth; //number of days in month read in
boolean monthValid, yearValid, dayValid; //true if input from user is valid
boolean leapYear; //true if user's year is a leap year
Scanner scan = new Scanner(System.in);
//Get integer month, day, and year from user
System.out.print("Type in the month: " );
          month = scan.nextInt();
System.out.print("Type in the day: " );
          day = scan.nextInt();
System.out.print("Type in the year: " );
          year = scan.nextInt();
//Check to see if month is valid
if (month >= 1)
month = month;
else
if (month <= 12)
month = month;
else;
//Check to see if year is valid
if (year >= 1000)
year = year;
else
if (year <= 1999)
year = year;
else;
//Determine whether it's a leap year
//Determine number of days in month
if (year == 1 || 3 || 5 || 7 || 8 || 10 || 12)
     System.out.println (Number of days in month is 31);
     else (year == 4 || 6 || 9 || 11)
     System.out.println (Number of days in month is 30);
//User number of days in month to check to see if day is valid
//Determine whether date is valid and print appropriate message
// Dates.java
// Determine whether a 2nd-millenium date entered by the user
// is valid
import java.util.Scanner;
public class Dates
public static void main(String[] args)
int month, day, year; //date read in from user
int daysInMonth; //number of days in month read in
boolean monthValid, yearValid, dayValid; //true if input from user is valid
boolean leapYear; //true if user's year is a leap year
Scanner scan = new Scanner(System.in);
//Get integer month, day, and year from user
System.out.print("Type in the month: " );
          month = scan.nextInt();
System.out.print("Type in the day: " );
          day = scan.nextInt();
System.out.print("Type in the year: " );
          year = scan.nextInt();
//Check to see if month is valid
if (month >= 1)
month = month;
else
if (month <= 12)
month = month;
else;
//Check to see if year is valid
if (year >= 1000)
year = year;
else
if (year <= 1999)
year = year;
else;
//Determine whether it's a leap year
//Determine number of days in month
if (year == 1 || 3 || 5 || 7 || 8 || 10 || 12)
     System.out.println (Number of days in month is 31);
     else (year == 4 || 6 || 9 || 11)
     System.out.println (Number of days in month is 30);
//User number of days in month to check to see if day is valid
//Determine whether date is valid and print appropriate message
}

Here are some helpfull hints for you:
1. Your code is really hard to read, there are two main reasons for this. First, your indentation sucks. Second, you seem to be fascinated with saving two (ok four if you count the shift key) keypresses to avoid using { and }.
2. Not using the brackets (you know { and } which you like to avoid) also is causing your code to do some stuff you don't realize or want to happen, or at least it would be if your code compiled.
3. If statements require arguements, "year == 1" is an arguement, "3" is not an arguement. Each operator like the or operator ("||") is essentially a new if and requires a complete arguement. So the following code peice:
if (year == 1 || 3 || 5 || 7 || 8 || 10 || 12)Literally translates to if year equals 1 or if 3 or if 5 or if 7 or if 8 or if 10 or if 12. Doesn't make much sense in english, and it doesn't make much sense in Java either.
4. I am pretty sure "year" is not the variable you want in the code snippet above (the one used in hint 3), especially considering years 1, 3, 5, 7, 8, 10, and 12 are not between 1000 and 1999. You need to be really carefull not make these kind of mistakes when coding, because they are by far the hardest to track down and fix later since they don't really throw up any flags or anything at compile or run time. Take your time and think thuroughly about each line of code while coding it, it will save you tons of time in the long run.
5. What exactly do you expect statements like "month = month;" to do? That translates as make month equal to month. Do you go to the bank and say " I have exactly $3.56 in my pocket, so I would like to deposite all $3.56 and then withdraw $3.56 and put it back in my pocket"? How do you think the teller would look at you? Teller would probably do it, but the teller would feel like he/she wasted time with you and that you are not really right in the head. Java feels the same way when you make it do the same thing, and you love to do it.
6. Code like the following is all wrong, and for more reasons than pointed out in hint 5.
if (month >= 1)
month = month;
else
if (month <= 12)
month = month;
else;Let's say someone put 13 in as the month. It passes the first check because 13 is greater than or equal to 1. so month which is 13, now gets set to 13 (gee that was effective). Now we hit the else and things get confusing because you didn't use brackets or proper indentation (hint 1) so we don't know what your real intent was. Did you mean else do nothing, and the next if statement is then executed, or did you mean to just run the next if statement if the else condition was met? Fortunatly it doesn't matter here because the next if statement is failed anyways since 13 is not less than or equal to 12.
So, we leave this code with month ebing 13, wait when did we add a 13th month to the calendar? Are you using the Jewish calendar? Could be, except even if I put 1234567 as the month your code would except it as valid, and I know no calendar with that many months. Try writing this in english first and translating it to jave, like i would probably say "if the month is greater than or equal to 1 and less than or equal to 12 then the month is valid." Course now what do you do if it is invalid? Hmm, maybe I would actually say "while the month is less than 1 or greater than 12 ask the user for the month" until they get it right.
There are a few other problems, but most of them are probably things you haven't learned yet, and they are not show stoppers so we will let them fly. You already have a lot of work to do to make this better. But I do have one more really really big usefull hint for you:
Never, ever, under any circumstances, should you ever ask in any way or even hint at asking for someone else to provide code solutions to your problems. So "so if you do hint me with some code then I'd appreciate it if it was stuff that's not too advanced " was a very bad thing to do, but fortunatly for you you followed it with proof you were trying to write the code yourself. Had the code you provided not been so full of problems it was obvious a beginner wrote it, you would probably have gotten much less cordial responses. I would seriously consider avoiding any implication of wanting code, at least until you become a regular poster here and people know you are not just looking to get your homework done for you.
Hope some of this helps.
JSG

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I have the bad feeling, that I am missing something. Does anyone else ran across this problem?
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Herbert

Frank,
Thank you for your answer. I'm not using ADF BC, so is there a possible workaround? My model provides a standard java.util.Date. My converter looks like:
public class BirthdateConverter implements Converter {
public Object getAsObject(FacesContext facesContext, UIComponent uIComponent, String sDate) {
    Locale locale = facesContext.getCurrentInstance().getExternalContext().getRequestLocale();
    String pattern = AppUtil.getFourDigitYearPattern(DateFormat.SHORT);
    SimpleDateFormat sdf = new SimpleDateFormat(pattern, locale);
    java.util.Date d = sdf.parse(sDate);
    // converter logic
    return d;
public String getAsString(FacesContext facesContext, UIComponent uIComponent, Object object) {
    if (object == null)
      return null;
    if (!(object instanceof Date))
      return object.toString();
    Locale locale = facesContext.getCurrentInstance().getExternalContext().getRequestLocale();
    String pattern = AppUtil.getFourDigitYearPattern(DateFormat.SHORT);
    SimpleDateFormat sdf = new SimpleDateFormat(pattern, locale);
    return sdf.format((java.util.Date)object);
}AppUtil.getFourDigitYearPattern(DateFormat.SHORT) provides a date pattern, e.g. "M/d/yyyy" for locale en-us. In the above code I did not include try-catch blocks to make it more readable.
Herbert
Message was edited by:
user575859

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This works fine in a leap year, but is kludgy otherwise as it includes an additional month in August – this skews form spreads.
And it gets even uglier when calculating/data viewing year over year forms as the start week for September should vary across leap and non-leap years.
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The Calendar Component does take account of the leap year.
If you look at the code, it has
if ((month == FEBRUARY) && (isLeapYear(year))) numCells++;Not sure what went wrong. I'll take a look at it.
- Winston

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Check in the query if you have one more variable.
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Message was edited by: lllaass got mixed up

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We have an oracle database with about 6 million records. There is a date field called Entered Date that ranges from 1985 to the present.
The majority of these records were entered prior to Jan 1 2000.
If I run a query like
select count(*) from (tablename) where entered_date < '01-JAN-00' I get 0
if I do
select count(*) from (tablename) where entered_date < '31-DEC-99' I get 0
BUT IF I DO
select count(*) from (tablename) where entered_date < '01-JAN-00' I get 6 million records
or
select count(*) from TREASURY.ctrc where entrydate > '31-DEC-99' I get 6 million records
I've tried the same queries using 4 digit years but get the same results; it thinks that 2000 is the less than 1999
How do I get around this?
thanks

Hi,
975204 wrote:
there are 6 million records on the table
about two thirds have a date prior to Jan 1 , 2000How do you know that? From knowledge of the application, you may know that two thirds of them are supposed to have dates prior to 2000, but if
SELECT COUNT (*)
FROM      TABLE_NAME
WHERE      ENTRYDATE < TO_DATE ( '01-JAN-2000'
                       , 'DD-MON-YYYY'
;returns 0, that's pretty strong proof that none of them actually do.
When I look at the dates , they display as 31-DEC-86Another example of why using 2-digit years is such a bad idea.
I cant actually provide dump of this clients confidential dataSeriously; you can't provide one DUMP output? You've already said that it displays as 31-DEC-86, so even if the fact that 1 entry in the 6-million row table was done on December 31, 1986 was such a big secret, it's already out, and you won't be causing any more harm by showing the DUMP results.
I ran the query with the same format as the date ie
SELECT COUNT(*) FROM TREASURY.CTRC WHERE ENTRYDATE < TO_DATE ( '31-DEC-99'
, 'DD-MON-YY'
but same results
if the column is defined as a DATE type, does Oracle make a distinction based on how the data displays, meaning does it think that 31-DEC-86 is different than 31-DEC-1986?No, all DATE columns have the same format. A DATE may be displayed one way of the other, but it is stored as neither.
Do I need to convert all the data to a 4 digit year? You should always display dates with a 4-digit year.
Run an update query that says if year >= 80 and <= 99 add 19 in front of the year, else add 20 in front of the yearLet's find out exactly what the problem is, first.
Did you see Ascheffer's message? ^1^ It was dated just a couple of minutes before your last message, so you might not have noticed it. Run it to see what the actual 4-digit years are.
If it shows, for example, that there are a lot of entrydates in the years 2080 to 2099, and you decide that all of those really should be 100 years earlier, then use ADD_MONTHS to correct them:
UPDATE     table_name
SET     entrydate = ADD_MONTHS ( entrydate
                           , -100 * 12
WHERE   entrydate >= TO_DATE ( '01-JAN-2080'
                         , 'DD-MON-YYYY'
AND     entrydate < TO_DATE ( '01-JAN-2100'
                         , 'DD-MON-YYYY'
;Edited by: Frank Kulash on Mar 15, 2013 6:09 PM
^1^ Obviously, you did see Ascheffer's message; I was still typing the message above when you posted another one.

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Hi,
I found a bug on the iphone (2.0.2)
When I create a rendez-vous in calendar and I add a note on several lines
example :
Mr Doe
Phone : 00000000
This contact won't synchronize with the exchange server (mail2web), if I create the same appointment on my mac (entourage) it will sync normally.
If I create the same appointment with calendar (on the iphone) and do'nt write the note on several lines, example :
Mr Doe, Phone : 000000
It will sync normally.
Someone else also has this problem ?
Message was edited by: bobby001

I also experianced this problem after an upgrade to Mountain Lion.
I think it has to do with the fact that in Lion the account settings were managed from iCal, and now they are managed by the OS?
Anyway I finally solved it by:
Open Calendar (formerly iCal).
Go to the Calendar menu and select Preferences.
Select the Accounts tab.
Remove the Exchange server account which is giving you the error messages. This calendar will be removed from the Calendar app.
Go to System Preferences and click on the "Mail, Contacts & Calendars" pane, find your Exchange server account, and check the "Calendars & Reminders" option to re-enable your calendar.
Your Calendar should now sync properly.
I had to do this for all of the accounts I had set up in Calander, and haven't had any problems since.

Problem with leap years in Calendar demo

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