Problem with XSLT: xsl:copy

xsl:copy let us copy a node from the source to the result of a XSLT transformation.
My problem is that each element is copied without its attributes !
For example a template:
<xsl:template match="myelement">
<xsl:copy>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
on a element:
<myelement myattribute="value">text</myelement>
will transform this element in the new element <myelement>text</myelement>. The attribute has desappeared.
How Can I do copy my element exactly as it is, with all its attributes ?
thank's.

Yes, but copy-of copies child elements too. And I don't want to do so. What I want is for example that my template generate an element
<myelement myattribute="value">
<myaddedelement>
</myelement>
with an element
<myelement myattribute="value"/>
in the source.

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Problem with XSLT: xsl:copy

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