Query to return ALL rows even those with zero counts

Question

Hi,
The following query will return only those rows that have a non zero count value:
select c.id, a.name, count(*) as XYZ from CON c, CUST a
where c.help !='1' and (c.id = a.id) group by c.id, a.name order by c.id;
The results are:
1 ME 3
3 YOU 4
What i want is to return all rows in CUST and the count, XYZ, that correspond to each row in CUST that matches the whare condition above, even if the count is zero.
ie
1 ME 3
2 WE 0
3 YOU 4
Can this be done?

Answer 1

You may want to get the counts then do the outer join. If you simply count with an outer join you will get 1 for 'WE' because there is a row in the cust table with 'WE'. This may work for you;
with
  cust as (
   select 1 id, 'ME' name from dual union all
   select 2 id, 'YOU' name from dual union all
   select 3 id, 'WE' name from dual),
  con as (
   select 1 id, '2' help from dual union all
   select 1 id, '2' help from dual union all
   select 1 id, '2' help from dual union all
   select 2 id, '2' help from dual union all
   select 2 id, '2' help from dual union all
   select 2 id, '2' help from dual union all
   select 2 id, '2' help from dual)
-- end of test data 
select a.id, a.name, nvl(c.cnt,0) xyz
from cust a, 
   (select id, help, count(*) cnt
   from con
   where help !='1'
   group by id, help) c
where a.id = c.id(+)