Question on Array
How can I set the output to be 1 instead of repeating?
Script
import java.util.*;
public class array
static Scanner console = new Scanner(System.in);
public static void main(String args[])
String[] nameList = new String[5];
nameList[0] = "Ali";
nameList[1] = "Ahmad";
nameList[2] = "Ah Chong";
nameList[3] = "Muthu";
nameList[4] = "Ramasamy";
for (int index = 0; index<nameList.length; index++)
System.out.println(nameList[1]);
Output
--------------------Configuration: Array - JDK version 1.5.0_19 <Default> - <Default>--------------------
Ahmad
Ahmad
Ahmad
Ahmad
Ahmad
Process completed.
Do you mean, if the variable named index equals 1 then you want Ahmad to be displayed, otherwise do not display anything? Or maybe you mean, output the value in the array based on the value of the variable named index? It is not clear what you want the output to be.
Edited by: atmguy on Oct 16, 2009 9:53 AM
Similar Messages
-
I have a question regarding arrays. I have a contact class and two classes that extend from it a SchoolContact class and FamilyContact class. Right now as my code is I have three diffrernt arrays to hold all the info. Is there a way to store all this info into one array and print out only the School contacts at one time if the user enters that option or print out all the options at one time if the user selects that? my code is below
//The imports below are for I/O
import java.util.*;
import java.io.*;
// Declare a public class
public class CodeExample {
public static void main(String[] args) {
// Create scanner
Scanner sc = new Scanner(System.in);
//Declare array to hold school contact
SchoolContact[] schoolContactInfo = new SchoolContact[10];
FamilyContact[] familyContactInfo = new FamilyContact[10];
Contact [] contactInfo = new Contact [10];
// Declare variables
int menuOption, creditHours, area, prefix, suffix, studentId, studentContactsSoFar = 0, familyContactsSoFar = 0, contactsSoFar = 0;
double gpa;
char studentData, familyRelationOption;
String menuOption2, menuOption3;
// Get menu to display
do {
System.out.println("-----MENU-----");
System.out.println("1) Enter a Student Contact");
System.out.println("2) Enter a Family Contact");
System.out.println("3) Enter a Contact");
System.out.println("4) Display Student Contacts");
System.out.println("5) Display Family Contacts");
System.out.println("6) Display Contacts");
System.out.println("7) Display All Contacts");
System.out.println("8) Quit");
System.out.println("Selection:");
menuOption = sc.nextInt();
SchoolContact schoolContact = new SchoolContact();
FamilyContact familyContact = new FamilyContact();
Contact contact = new Contact();
// Implement switch statement to
switch (menuOption) {
// If user enters 1 to create contact this will be displayed to user
case 1:
System.out.println("Enter The First Name of The Student");
schoolContact.setFirstName(sc.next());
System.out.println("Enter The Last Name of The Student");
schoolContact.setLastName(sc.next());
System.out.println("Enter the Student ID of this person: 900");
schoolContact.setStudentId(Integer.parseInt("900" + sc.next()));
System.out.println("G)Enter The GPA For This Student");
System.out.println("H)Enter The Number Of Completed Credit Hours");
menuOption2 = sc.next().toUpperCase();
studentData = menuOption2.charAt(0);
// Prompts the user for the next choice
if (studentData == 'G') {
System.out.println("GPA: ");
gpa = sc.nextDouble();
//create the Data object
Data data = new Data();
data.setStudentGPA(gpa);
//add it to the contact
schoolContact.setData(data);
else if (studentData == 'H') {
System.out.println("Hours: ");
creditHours = sc.nextInt();
//create the Data object
Data data = new Data();
data.setStudentCreditHours(creditHours);
//add it to the schoolcontact
schoolContact.setData(data);
else {
System.out.println("Invalid Entry");
System.out.println("Enter The Phone Number of This Student");
System.out.println("(###)-###-####: ");
area = sc.nextInt();
prefix = sc.nextInt();
suffix = sc.nextInt();
//create the phone object
Phone_Number studentPhone = new Phone_Number(area, prefix, suffix);
//add it to the Schoolcontact
schoolContact.setPhone(studentPhone);
//store info in an array
schoolContactInfo[ studentContactsSoFar ] = schoolContact;
//increase the counter to point to the next free location (if any)
studentContactsSoFar++;
break;
case 2:
System.out.println("Enter the First Name of The Contact");
familyContact.setFirstName(sc.next());
System.out.println("Enter The Last Name of The Student");
familyContact.setLastName(sc.next());
System.out.println("Enter The Relationship of This Contact");
System.out.println("A) SISTER");
System.out.println("B) BROTHER");
System.out.println("C) MOTHER");
System.out.println("D) FATHER");
System.out.println("E) OTHER");
menuOption3 = sc.next();
familyRelationOption = menuOption3.charAt(0);
if (familyRelationOption == 'A') {
System.out.println("Relationship: SISTER ");
familyContact.setRelationType(FamilyContact.RelationType.SISTER);
else if (familyRelationOption == 'B') {
System.out.println("Relationship: BROTHER ");
familyContact.setRelationType(FamilyContact.RelationType.BROTHER);
else if (familyRelationOption == 'C') {
System.out.println("Relationship: MOTHER ");
familyContact.setRelationType(FamilyContact.RelationType.MOTHER);
else if (familyRelationOption == 'D') {
System.out.println("Relationship: FATHER ");
familyContact.setRelationType(FamilyContact.RelationType.FATHER);
else if (familyRelationOption == 'E') {
System.out.println("Relationship: OTHER ");
familyContact.setRelationType(FamilyContact.RelationType.OTHER);
System.out.println("Enter The Phone Number of This Contact");
System.out.println("(###)-###-####: ");
area = sc.nextInt();
prefix = sc.nextInt();
suffix = sc.nextInt();
//create the phone object
Phone_Number familyContactNumber = new Phone_Number(area, prefix, suffix);
//add it to the familyContact
familyContact.setPhone(familyContactNumber);
//store info in an array
familyContactInfo[ familyContactsSoFar ] = familyContact;
//increase the counter to point to the next free location (if any)
familyContactsSoFar++;
break;
case 3:
System.out.println("Enter The First Name of The Contact");
contact.setFirstName(sc.next());
System.out.println("Enter The Last Name of The Contact");
contact.setLastName(sc.next());
System.out.println("Enter The Phone Number of This Contact");
System.out.println("(###)-###-####: ");
area = sc.nextInt();
prefix = sc.nextInt();
suffix = sc.nextInt();
//create the phone object
Phone_Number contactNumber = new Phone_Number(area, prefix, suffix);
//add it to the contact
contact.setPhone(contactNumber);
//store info in an array
contactInfo[ contactsSoFar ] = contact;
//increase the counter to point to the next free location (if any)
contactsSoFar++;
break;
case 4:
System.out.println("-----Student Contacts-----");
//print each stored contact
for( int i = 0 ; i < studentContactsSoFar ; i++ )
System.out.println( (i+1) + ". " + schoolContactInfo.toString() + "\n");
break;
case 5:
System.out.println("-----Family Contacts-----");
//prints each stored contact
for( int i = 0 ; i < familyContactsSoFar ; i++ )
System.out.println( (i+1) + ". " + familyContactInfo[i].toString() + "\n");
break;
case 6:
System.out.println("-----Contacts-----");
//prints each stored contact
for( int i = 0 ; i < contactsSoFar ; i++ )
System.out.println( (i+1) + ". " + contactInfo[i].toString() + "\n");
break;
case 7:
System.out.println("Calling Case 7");
for( int i = 0 ; i < contactsSoFar ; i++ )
System.out.println( (i+1) + ". " + contactInfo[i].toString() + "\n");
break;
case 8:
System.out.println("Program Ended");
break;
} while (menuOption != 8);how would I go in printing the contacts from one array, then the next array and so on?
case 7:
System.out.println("Calling Case 7");
for( int i = 0 ; i < studentContactsSoFar ; i++ ) {
System.out.println( (i+1) + ". " + schoolContactInfo.toString() + "\n");
for( int i = 0 ; i < familyContactsSoFar ; i++ ) {
System.out.println( (i+1) + ". " + familyContactInfo[i].toString() + "\n");
for( int i = 0 ; i < contactsSoFar ; i++ ) {
System.out.println( (i+1) + ". " + contactInfo[i].toString() + "\n");
break; -
Trying to teach self Java-question with arrays
I have a question with arrays. I have a simple inventory program that I am writing(very simple). I have declared and created my array. Is this the time I should build a new class outside of my main in order to hold my array? I am still trying to sort through classes and when to create them. My thought is that because it is a hierarchy I should have a new class. For example, Albums is at the top and then there are specific types of albums, like TributeAlbum, PremiereAlbum, etc. Do I need a class for each of these? When I create the class, do I use the same name as the array?
More info, just in case: My original class is AlbumInventory. I have created an array to hold 25 TributeAlbums which has 4 instance variables.
Question 2: Why can I not refer to an album variable like TributeAlbums[0].itemNumber?
Thanks in advance for your input.
DeniseI have a question with arrays. Okay.
I have a simple
inventory program that I am writing(very simple). I
have declared and created my array. Is this the time
I should build a new class outside of my main in
order to hold my array? In an OO language classes are usually a good idea.
I am still trying to sort
through classes and when to create them. My thought
is that because it is a hierarchy I should have a new
class.This sounds a bit confused. You should have a new class when it is appropriate to do so.
For example, Albums is at the top and then
there are specific types of albums, like
TributeAlbum, PremiereAlbum, etc. Do I need a class
for each of these? Not sure. Why is the type not an attribute of the Album class? This (attribute) seems at first glance to be the way to do it.
When I create the class, do I use
the same name as the array?
? I am going to say no but I'm not following what you are really asking here.
More info, just in case: My original class is
AlbumInventory. I have created an array to hold 25
TributeAlbums which has 4 instance variables.
Can you please post some of your actual formatted code? It would also be helpful to know what the attributes for an Album are as you have them. -
A question about arrays (brace yourself this is a long post)
I am working on an assignment that is about generating a random rabbit race by using arrays:
Rabbit Race
Write a program to simulate a race between 4 rabbits (numbered 0 to 3). Initially, all contestants are at the start of the race track (position 0) and must race on a 20 meter track (positions numbered 0 to 19). Each participant has its own technique; some run fast, but are sometimes lazy; while others run slowly but steadily. All rabbits make 1 movement one after the other and the one who arrives at the end of the track before the others, wins the race. Here are the rabbit?s strategies :
At each turn, rabbit 0:
- sleeps (so does not run), 50% of the time;
- runs 4 meters, 30% of the time;
- runs 3 meters, 20% of the time.
At every turn, rabbit 1 runs 2 meters.
At each turn, rabbit 2:
- sleeps, 30% of the time;
- runs 3 meters, 70% of the time.
At each turn, rabbit 3:
- runs 1 meter, 80% of the time;
- runs 10 meters, 20% of the time.
The difficulty in the race is that the track has little slippery hills. So after each movement, rabbits can slide down a hill bringing them either closer to the finishing line, or closer to the starting line. How much they slide and in what direction depends on the slope of the hill at their current position, and how many meters they ran during this turn. Each position (or meter) of the hill has a slope represented by an integer between -3 and +2. If the slope is :
- zero : then, there is no hill at this position and rabbits that reach this position stay there.
- a negative integer : then, there is a declining side of a hill at this position, and all rabbits reaching this position will slide down
to a new position that is closer to the finishing line. The new position will be the current position minus the slope times the number of meters the rabbit ran.
For example, assume a rabbit was in position 10, then ran 5 meters to position 15. If the slope at position 15 is -2, then the new position of the rabbit will be 15 - (-2 x 5) = 25.
- a positive integer : then, there is a rising side of hill at that position, and all rabbits reaching this position will slide down to a new position that is closer to the starting line. The new position will be the current position minus the slope times the number of meters the rabbit ran.
For example, assume a rabbit was in position 10, then ran 5 meters to position 15. If the slope at position 15 is +1, then the new position of the rabbit will be 15 - (+1 x 5) = 10.
Notes on the race:
- Rabbits have 40 turns to reach the finish line. If after 40 turns no one has managed to reach position 19 (or beyond), then the race is cancelled and no winner is declared.
- A rabbit?s position can never go below 0. If, after calculating a rabbit?s position, you arrive at a negative position (ex. position -3), then consider that it is at position 0.
- Consider that any position outside the track (ex. position 0 or position 20) has a slope of 0.
- If a rabbit reaches position 19 (or goes beyond it), it does not immediately win the race. If any other rabbit reaches position 19 (or beyond) during the same turn, then there is a tie.
- If at the same turn, one rabbit reaches position 19, and another reaches a position higher than 19, the second rabbit does not win the race because it went further than the first. They both win.
Ok I know this is long and boring to read but I already completed the majority of the assignment here is my code:
public class Assignment_3 {
public static void main (String args[])
int[] position = new int[20];
int[] slope = new int[20];
int[] moveRabbit = new int[4];
moveRabbit[1] = 2;
int[] currentPosition = new int[4];
int currentPositionandSlope = 0;
for (int i=0;i<position.length;i++)
{ position=i;
System.out.print(position[i] + " ");
System.out.println();
for (int i=0;i<(position.length-5);i++)
{ slope[i]=(int) (-3 + Math.random()*5);
for (int i=0;i<position.length;i++)
System.out.print(slope[i] + " ");
System.out.println();
for (int turn=1;turn<=40;turn++)
int randomNb0 = (int) (Math.random () * 100);
int randomNb2 = (int) (Math.random () * 100);
int randomNb3 = (int) (Math.random () * 100);
if (randomNb0<=50)
moveRabbit[0] = 0;
else if (randomNb<=30)
moveRabbit[0] = 4;
else
moveRabbit[0] = 3;
if (randomNb2<=30)
moveRabbit[2] = 0;
else
moveRabbit[2] = 3;
if (randomNb3<=80)
moveRabbit[3] = 1;
else
moveRabbit[3] = 10;
for (int j=0;j<=3;j++)
System.out.println ("Rabbit" + j + " is at position " + position[currentPosition[j]]);
if (slope[currentPosition[j]+moveRabbit[i]] < 0)
currentPositionandSlope = position[currentPosition[j]+moveRabbit[j]] - (slope[currentPosition[j]+moveRabbit[j]] * moveRabbit[j]);
else if (slope[currentPosition[j]+moveRabbit[i]] > 0)
currentPositionandSlope = position[currentPosition[j]+moveRabbit[j]] - (slope[currentPosition[j]+moveRabbit[j]] * moveRabbit[j]);
else
currentPositionandSlope = (currentPosition[j]+moveRabbit[j]);
System.out.println ("it will move by " + moveRabbit[j] + ", but at position " + (position[currentPosition[j]] + moveRabbit[j]) + " there is a slope of " + slope[currentPosition[j] + moveRabbit[j]]);
System.out.println ("so it will slip by " + (position[currentPositionandSlope] - moveRabbit[j]) + " positions, and end up at position " + position[currentPositionandSlope]);
currentPosition[j] += currentPositionandSlope;
*Ok basically my question is that in the assignment there is an example output where the rabbit is at position 21 but the array is only 20 in length and my program crashes if i go beyond the array length.*
The example output is here:
Welcome to the 4 rabbit race:
position: 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19
slopes: 0 0 1 -2 1 0 -1 -1 1 -2 1 0 -1 -1 1 0 0 0 0 0
TURN #1
rabbit 0 is at position 0
it will move by 3, but at position 3 there is a slope of -2
so it will slip by 6 positions, and end up at position 9
rabbit 1 is at position 0
it will move by 2, but at position 2 there is a slope of 1
so it will slip by -2 positions, and end up at position 0
rabbit 2 is at position 0
it will move by 3, but at position 3 there is a slope of -2
so it will slip by 6 positions, and end up at position 9
rabbit 3 is at position 0
it will move by 1, but at position 1 there is a slope of 0
so it will slip by 0 positions, and end up at position 1
TURN #2
rabbit 0 is at position 9
it will move by 0, but at position 9 there is a slope of -2
so it will slip by 0 positions, and end up at position 9
rabbit 1 is at position 0
it will move by 2, but at position 2 there is a slope of 1
so it will slip by -2 positions, and end up at position 0
rabbit 2 is at position 9
it will move by 3, but at position 12 there is a slope of -1
so it will slip by 3 positions, and end up at position 15
rabbit 3 is at position 1
it will move by 1, but at position 2 there is a slope of 1
so it will slip by -1 positions, and end up at position 1
TURN #3
rabbit 0 is at position 9
it will move by 3, but at position 12 there is a slope of -1
so it will slip by 3 positions, and end up at position 15
rabbit 1 is at position 0
it will move by 2, but at position 2 there is a slope of 1
so it will slip by -2 positions, and end up at position 0
rabbit 2 is at position 15
it will move by 3, but at position 18 there is a slope of 0
so it will slip by 0 positions, and end up at position 18
rabbit 3 is at position 1
3
it will move by 10, but at position 11 there is a slope of 0
so it will slip by 0 positions, and end up at position 11
TURN #4
rabbit 0 is at position 15
it will move by 0, but at position 15 there is a slope of 0
so it will slip by 0 positions, and end up at position 15
rabbit 1 is at position 0
it will move by 2, but at position 2 there is a slope of 1
so it will slip by -2 positions, and end up at position 0
*rabbit 2 is at position 18*
*it will move by 3, but at position 21 there is a slope of 0*
*so it will slip by 0 positions, and end up at position 21*
*We have a potential winner...*
rabbit 3 is at position 11
it will move by 1, but at position 12 there is a slope of -1
so it will slip by 1 positions, and end up at position 13
So yeah :) that's basically my question (all this text for a simple question like that lol)
If you've managed to get to the end of my post then any guidance on my code would be appreciated too :)I'm not going to read that long post. As suggested, produce an SSCCE
and paste in the exact, complete error message, and indicate clearly which line causes it.
I did notice this though:
Ok basically my question is that in the assignment there is an example output where the rabbit
is at position 21 but the array is only 20 in length and my program crashes if i go beyond the array length.Either you're misunderstanding something, or the assignment has a typo. If you have an array of length 20, then the indices are 0..19.
Maybe the instructor is calling index 0 position 1--separating Java's array impelementation details from
colloquial 1-based counting, so that the rabbit starts at "position 1" (index 0) goes through "position 20"
(index 19), and when he's done, he's "at postion 21"--i.e., past the finish line, off the end of the course, etc.
This won't correspond to any index in the array, but can still be considered a logical position in the race. "Oh, he's
at position 21. He's done. There's nothing more to do with the array, as it has no slot corresponding to
this 'done' position."
That's pure speculation on my part. You'll have to ask your instructor or figure out for yourself what's going on. -
Hello,
I hope this is the right forum: I have a simple Java Problem but i do not get it.
Is like that: I have to swap values within an array e.g i have one array with 3 indices. Indice 0 (the first indice) has value 12. The middle indice has no value, and the second indice has value 9. How to swap 9 to 12 and 12 to 9 without direct swap, in other words, by using the middle indice that has no value or is zero? And how do i write it in an array?
My other questions: How do i Declare an array and values of its indices?
I hope this is the right forum or site at all, in cas enot, i hope you still can help or give me links that could help. I really need this.Please study this tutorial http://java.sun.com/docs/books/tutorial/java/data/arrays.html
-
Hi, i got some question about arrays.
My question is how do i auto increase the array size for theList[0] to store the over time if the user enter more than 1 employee.
static void showPayInfo(int num1 , int num2)
for(int coloum = 1 ; coloum <= num2 ; coloum++)
System.out.print("Enter employee's over time $: ");
ot = CspInput.readDouble();
Double = ot;
getDouble(Double);
static double ot , Double;
static void getDouble(double Double)
double[] theList = new double[2];
theList[0] = ot;
public static void main(String[] args)
int a;
System.out.print("How many employees : " );
a = CspInput.readInt();
showPayInfo(1,a);
}how to create the list?
import java.util.ArrayList;
class testArrayList {
public static void main(String[] args) {
ArrayList<String> list1 = new ArrayList<String>();
// Populate list
for (int i = 0; i < 5; i++) {
list1.add("List item " + i);
// Show list
for (int i = 0; i < list1.size(); i++) {
System.out.println(list1.get(i));
} -
Hopefully an easy question about arrays
hi there
is there any way of creating an array of objects that is of unspecified size at the time of creating and then add objects as and when they are read from a file?
longer explanation:
i am creating molecule visualization software. the molecule's structure is stored in a text file, ie each line has info on one atom ie 3d coords etc. i'm storing the molecule structure in an object (Molecule.java) which has an array (Structure[]) of atoms (Atom.java). obviously molecules can have any number of atoms in it and you don't know how many until you've gone through the whole file and counted. The only way i can think of doing it is to go through the whole file, coun the atoms, close the file, create the Molecule object with the structure array size of NoOfAtoms and then open the file again and add the atoms as i go through them again. however, i refuse to believe this is the most efficient way of doing it as i have to go throguh the same file twice which brings me back to my original question.
as i said i'm hopeing there is a simple answer
cheersUse a Collection . Use a Vector, ArrayList or even a Hashtable. You do not need to define the size of these objects and can add and remove Objects from them whenever you want
-
I have this bit of code
public class BubbleSort {
public static void main(String[] args) {
for (int st=0; st<args.length; st++){
int st_to_int = Integer.parseInt(args[st]);
System.out.println(st_to_int);
how can I convert st_to_int to arrays[7] of interger of 7 ARRAYSDear warnerja,
I tried it but it came up with this error
BubbleSort.java:12: ']' expected
int st_to_int[st] = Integer.parseInt(args[st]);
^
reply to
If I interpret your question correctly, I think you want something like:
int[] st_to_int = new int[args.length];
for (int st = 0; st < args.length; st++)
st_to_int[st] = Integer.parseInt(args[st]);
} -
A question about arrays. Please Help
Ok here is my question lets say i have a multie varible array such as
int[][] thisList = new int[3][64];And I have a number of other arrays that are single variable arrays, and which have data stored in them.
List1[64]
List2[64]
List3[64]is there a way i can store all these three list in the multie varible array?
for example i know i can do this, > Correct me if i am wrong
List1 = List2; where List1 one now contains all the elements that List2 has.
but is there a way i can
us the same format with a multie varible array, to store all three list in it.
such as thisList[1][] = List1; thisList[2][] = List2[]; Thanksfor example i know i can do this, > Correct me if i
am wrong
List1 = List2; where List1 one now
contains all the elements that List2 has.There will be one array. Both the List1 and List2 reference variables will point to that same array.
(By the way, convention in Java is for variables to start with lowercase.)
>
but is there a way i can
us the same format with a multie varible array, to
store all three list in it.
such as thisList[1][] = List1; thisList[2][] =
List2[];
You can do thisList[1] = List1 if thisList is an int[][] and List1 is an int[]. However, that will not copy any ints. It will just do the same as the above--cause the reference thisList[1] to point to the same array object as List1 does.
If you want to copy values from one array to another, use System.arraycopy. -
Very simple and quick question about Arrays
Hi,
I have the following code to produce a student grades provessing system. I have got it to store data in the array, i just cant figure out how to add the integers from the row to produce a total. Thats all I want to do create a total from the 6 marks and add a percentage.
Any help would be greatly appreciated.
-------------CODE BELOW----------------------
import java.util.*;
public class newstudent1_2
public static void main (String[]args)
System.out.println ("-----------------------------------------------"); //Decorative border to make the welcome message stand out
System.out.println (" Welcome to Student Exam Mark Software 1.2"); //Simple welcome message
System.out.println ("-----------------------------------------------");
int [][] mark;
int total_mark;
int num_students;
int num_questions = 9;
Scanner kybd = new Scanner(System.in);
System.out.println("How many students?");
num_students =kybd.nextInt();
mark = new int[num_students][num_questions] ;
for (int i=0; i<num_students; i++)
System.out.println("Enter the Students ID");
String student_id;
student_id =kybd.next();
System.out.println("Student "+i);
for( int j=1; j<num_questions; j++)
System.out.println("Please enter a mark for question "+j);
mark[i][j]=kybd.nextInt();
System.out.print("id mark1 mark2 mark3 mark4 mark5 mark6 mark7 mark8");
//This section prints the array data into a table
System.out.println();
for (int i=0; i<num_students; i++)
for( int j=0; j<num_questions; j++)
System.out.print(mark[i][j]+"\t"); //the \t is used to add spaces inbetween the output table
System.out.println();
--------------END OF CODE---------------
Thanks.I had to do this same sort of thing for a school assignment but i didnt use an array.
import java.text.DecimalFormat;
import TurtleGraphics.KeyboardReader;
public class grade_avg
public static void main(String[] args)
int grade, total = 0, count = 0;
double avg = 0.0;
KeyboardReader reader = new KeyboardReader();
DecimalFormat df = new DecimalFormat("0.00");
for (;;)
grade = reader.readInt("Please enter a grade: ");
if (grade > 0)
total = total + grade;
count ++;
if (grade == 0)
avg = total / count;
System.out.println("The average is: " + df.format(avg));
System.exit(0);
}output looks like:
Please enter a grade: 100
Please enter a grade: 50
Please enter a grade: 0
The average is: 75.00 -
Hello and a question about Arrays
Hello! I am a student working towards a CIS degree, I'm only in my second term, so I have a long way to go still. Next term (starts in November) I'll be starting my first language (Java) so I figured this is a good spot to register and get acquainted with all of you.
Anyway, right now I'm in a programming logic and design class. In this class we use Pseudocode to get the basic constructs of programming down without doing anything language specific. I just read the chapter that introduces Arrays and had a difficult time following it. Could any of you take a minute and give me your definition of what exactly an array is and how it works? Or maybe point me to a link that might help me? I've got the 'jist' of it, but the book jumps right into algorithms using arrays without much explaination as to what they are.
Thanks for any response and for helping a programming "n00b".
-Rawhide>
Hello! I am a student working towards a CIS
CIS degree, I'm only in my second term, so I have a
long way to go still. Next term (starts in November)
I'll be starting my first language (Java) so I
figured this is a good spot to register and get
acquainted with all of you.
Anyway, right now I'm in a programming logic andThink of an array as a series of boxes. These boxes store data for three
elements. So you would have three boxes that store one element of data.
So 'this' array has a capacity of three. If you want something bigger,
you'd create a array with more boxes, say 10. Then your array has a capacity of 10.
To get to anything from a array, you either need to :
a) go through all the elements of the array
b) or actually know the element you want to retrieve.
The second case is simple enough, you usually just specify the element you want. For example the first element would be zero.(counting starts from zero). The last element would be 9 (10 -1).
The first case requires some knowledge of looping, you'd generally itterate from the first until the last element of the array, in each and every element that you are at, do the stuff you need to do. This will go on until the end of the array is reached.
for(int i=0; i<=arraylength;i++ ) {
do some stuff. like print out to the console.
I'm not giving you any specific java code because you didn't ask for any and you were doing a course that wasn't language specific. So I figured that may be a simpler explanation(was it?) was in order.
Let me know if you need clarification.
and design class. In this class we use Pseudocode to
get the basic constructs of programming down without
doing anything language specific. I just read the
chapter that introduces Arrays and had a difficult
time following it. Could any of you take a minute
and give me your definition of what exactly an array
is and how it works? Or maybe point me to a link that
might help me? I've got the 'jist' of it, but the
book jumps right into algorithms using arrays without
much explaination as to what they are.
Thanks for any response and for helping a programming
"n00b".
-Rawhide -
A few questions about Arrays and Array Methods.
I have 2 dimentional arrays in a number of classes, and I wish to pass them about as variables, however, I can only seem to send int[], rather than int[][]. Gives me some compile errors.
Another thing. How do i get the length of an array?
I've tried: getLength(object), but it's a 2d array (int[][]), and It's having none of it. How do i get the length of a particular side?An object like int[][] only has a single "length", and that is the length of the first dimension. This object is an array that contains arrays of int, and each of those arrays could have a different length. Your 2D array may happen to be rectangular but that isn't a requirement of Java. So you would have to write your own code to find the lengths of the sides. The first side would be theArray.length, the second side would be theArray[0].length, and like that.
-
A normal question regarding array threhold function
Hi, i try to use the array threshold vi function but faced some problems. Pls see my VI. I can only a threshold result but can't get the other. Hope anyone could help me. Thanks
Attachments:
Test1.vi 37 KBThe Threshold 1D Array function is looking for a rising edge across your threshold. Since your first array only contains falling data points the threshold function never finds a valid transition.
See the LabVIEW help file for more detailed information about the threshold function.
Christian L
NI Consulting Services
Christian Loew, CLA
Principal Systems Engineer, National Instruments
Please tip your answer providers with kudos.
Any attached Code is provided As Is. It has not been tested or validated as a product, for use in a deployed application or system,
or for use in hazardous environments. You assume all risks for use of the Code and use of the Code is subject
to the Sample Code License Terms which can be found at: http://ni.com/samplecodelicense -
Question-Creatin array from a large # of scalars
Hello
I am developing LV code, where a large number of calculations are being done
in various ways as scalars. I would like to assemble these (say about 200
such) into a 1D array. I want to avoid using Build Array with 200 element
inputs. Also, these are not being generated within a For-Next loop to be
able to use the auto-indexing function or shift-registers.
Is there a relatively simpler way to create a 1D array from a large number
of scalars?
Reason I want to do this, is to make it easy to pass this array to other
vi's via a connector output or store to like a spreadsheet or send to a
printer.
TIA
Khan Kabir
Xerox Corp.Hi Khan,
you can use Vi-Server to automatically build an array of values contained in controls or indicators of your front panel.
I attach a vi in LV6 that:
- Creates an array of references of all the front panel controls and indicators
- Extracts the values of a determined number of controls/indicators
- Converts each value in a DBL format (of course it can be changed)
- Builds an array of values extracted
N.B. the order of the references array refers to the order of the controls/indicators on your panel. It's important that you set correctly the panel order to make this vi build an array of the wanted controls/indicators; to access panel order: Edit - Set Tabbing Order. If for instance you want to make an array of 5 controls but in your panel you have a boolean at
order #3 you will get an error ( you can't convert a boolean to DBL...)
Let me know if you need more help.
good luck,
Alberto
Attachments:
building_controls_array.vi 35 KB -
Im a couple days new in java, Ive been searching for an answer for hours and havent found a solution.
This is the mistake it shows (when trying to use any element of the array):
array required, but java.util.ArrayList <java.lang.String> found
The array is:
public static ArrayList<String> numList = new ArrayList<String>();
Im filling it this way: (so that it contains each word of a file in separate)
BufferedReader br = new BufferedReader(new FileReader("Archivo.txt"));
try
while(true)
String aLine = br.readLine();
if(aLine == null) throw new EOFException("Le?do todo el archivo.");
if(!aLine.equals(""))
StringTokenizer st = new StringTokenizer(aLine);
while(st.hasMoreTokens())
numList.add(st.nextToken());
}catch(EOFException e)
The problem comes when I try to use the elements of the array (in specific when trying to convert each element of the array to int, so that i can do math operations with them).
for example:
for (a=0; w>a; a++)
int x = Integer.parseInt(numList[a])
Can anyone help me with this? (where is the mistake and how to convert from string array elements to int)
Thank you // Muchas GraciasThe trouble is that you're confusing ArrayLists with arrays. They're not the same thing.
Currently you're making an ArrayList. If you want an array of String, do this:
String[] myArray = new String[50];
int i = 0;
while(st.hasMoreTokens()) {
myArray[i] = st.nextToken();
i++;
}Or perhaps better yet:
String[] numListArray = numList.toArray(new String[0]);But you really don't need an array for what you're doing. Use an Iterator.
Iterator<String> strings = numList.iterator();
while(strings.hasNext()) {
int x = Integer.parseInt(strings.next());
}You get the idea. Read the Collections tutorial about iterators. Read the language spec about arrays. Also look at the java.util.Arrays class. -
Hi,
I have a for loop and an array outside the for loop. In each iteration some values are sent to the array.
For example, after first loop, I send following data to array:
2 3 4 5
4 5 6 7
after the second loop, other data send to array again and will overwrite the former data in array. How can I append the data to the array?
I try to use "Insert into array.vi", but how to keep the former array's data?
Thanks.You have quite a few options.
The attached VI (LabVIEW 7.1) shows two possibilities, either building the table (2D string) or building the array (2D DBL).
(NOTES: If this is in a fast FOR loop it is not useful to update the display inside the loop, simply place the output terminals outside the FOR loop, connected to the shift registers on the right. If you know the final array size and it is relatively big, it is more efficient to initialize the shift register with the full sized array (e.g. filled with zeroes or NaNs), then replace array sections as you go in the loop. This avoids array resizing operations.)
LabVIEW Champion . Do more with less code and in less time .
Attachments:
temp_ni_MOD.vi 43 KB
Maybe you are looking for
-
OAS 4.0.8 & Developer Server 6.0
Hi, I 've installed on WindowsNT Workstation 4.0/SP5 1.) Developer Server Rel.6.0 2.) OAS 4.0.8.0.0 When I open a HTML file which has a reference to Forms executable (.fmx) I get the Oracle Developer Server logo and nothing happens. Java console show
-
Pdf email attachment for human task detail notification
We have a human task detail notification with pdf attachment. The email notification (generated automatically) flat out all content but no pdf attachment. Is this supported and if yes how to make it work?
-
Swipe left and right with magic mouse doesn't work in safari
Hey there, I accidently deleted something in the navigation bar in safari. Now when i swipe left and right with my magic mouse, it doesn't go to the previous pages anymore. But the wierd thing is it still works with my magic trackpad. And even wierde
-
Dear colleagues, I've got the following issue: 1) 2 company codes in one client. They were previosly legally independent units, but now one the companies acquired the other. They were previously consolidated in SAP. 2) Each of the companies represent
-
Gr po upload for movement type 101
Dear cons We want to upload GR PO UPLOAD FOR MOVEMENT TYPE 101(IMPORTED MATERIAL).We have store data in a excel file. We want to upload. What is the procedure to make a report? Because the procurement cycle of imported case is different to domestic c