Question related to regex and whitespaces \s

Hello, i have a problem related to regex.
I have a text area where sm types text. I noticed that when i click on the Enter button (i have a new line) the string is not being recognised.
String regex = "[A-Za-z0123456789_./-]*";I tried to place \s but \s includes other whitespaces characters.
I would like to include in my regex the \n character (the Enter button) or general the \s characters.
How am i supposed to do that?
Thanks, in advance!

g_p_java wrote:
prometheuzz wrote:
>
Note that on Windows, a line break is "\r\n".
Also, A-Za-z0123456789_ can be written as \w:
String regex = "[\r\n\\w./-]*";
If we are using Linux , Unix is that different?The OS line break is just \n. I'm not sure what Swing puts into a GUI element, whether it's OS dependent or not. It won't hurt you to leave the \r in there though. If there's no \r in the string, it won't stop your regex from working, just like it won't stop it from working when you have A-Z and they don't happen to enter a Z.
The only way it would cause a problem to leave the \r in the regex is if \r were somehow part of the input and you didn't want it treated as end-of-line. I don't see that happening though.

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