Queue Issue, reentrant/multiple calls

I have a slight problem using queues. I've read the posts that are close to my problem but i haven't figured out how to solve my case.
I have a "main window" where i want the queue to show constantly. Then i have 5 places that can add values to a single queue to be tested with a specific equipment. Even if i use 1 name for the queue the reference when obtaining the queue changes (read in a post). So i'm not able to modify 1 queue from 4 different places. I don't think it's appropriate to link from the "main window" the queue reference into the 5 places it should modify them.
So how should i solve my case? With reading the queue status from a Global Variable (not good solution)?
Attachments:
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When you open a queue by name you get a different queue ref to the same queue.
So you should be able to load the queue inside your subvi and post messages to the main VI without passing the reference around.
Be aware queues are bound to the application instance and you can't use them in a different app instance.
Just make sure that you keep the queue alive. So don't close it immediatly after writing to the queue.
Ton
Message Edited by TonP on 07-26-2007 01:20 PM
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http://software.cisco.com/download/release.html?mdfid=283095470&flowid=46243&softwareid=282074289&release=9.4%281%29&relind=AVAILABLE&rellifecycle=&reltype=latest
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http://www.cisco.com/en/US/partner/docs/voice_ip_comm/cuipph/8941_8945/firmware/9_2_2/english/release/notes/8941_8945_922.html
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"Mush15" <[email protected]> wrote in
message
news:g7hela$flo$[email protected]..
> Ok the issue is a stack overflow caused by calling the
function
> recursivly.
>
> I have tried creating 2 functions and have each call the
other but still
> recieve a stack overflow.
>
> Any ideas help??
Try incrementing a counter every time you call the function
and decrementing
it on the way out. When you hit 2640 times, stop calling it.

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In consider
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"Eric6756" wrote in message
news:[email protected]...
> Greg,
>
> As I think I lost you in the point of this line of questions, let me
> back up.
>
> A couple of week ago I asked the following question, "Is there a
> labVIEW library call that can be made from a dll to tell labVIEW to
> abort the calling vi thread?" To that question you made the following
> statement:
>
> "... and I doubt that there is a function to do that from a DLL as the
> DLL could be arbitrarily deep down the stack and the function called
> would have to magically find the VI that it wants to abort. And don't
> forget that DLLs can be called by multiple VIs at the same time."
>
> You seem to be saying here that what I'm asking for is not possible.
> And having thought about this for a while, I didn't understand why
> not.
>
> For the moment I'm going to ignore the caveat you just put into the
> dll calling presumptions I've made and assume the dll is going to
> execute synchronously within a thread. As the original question
> suggests, the objective here is to message labVIEW from a dll to
> provide the same functionallity as a CIN, namely return an error code
> to labVIEW from a dll.
>
> A library function could do this as follows:
>
> First, the library function would have two modes; set error, and
> return error
>
> (1) set error:
>
> 1.1 get the set error caller thread ID from API
> 1.2 get the passed in error
> 1.3 store the error and associated thread ID locally
>
> (2) return error
> 2.1 get return error caller thread ID from API
> 2.2 locate the error, if any, associated with thread ID
> 2.3 return the error and clear it locally
>
> Now, if a dll encountered an error that it wanted labview to deal
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> function to return the error. This of course works only if the dll
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> from the thread and the presumption that an error could be uniquely
> associated with a thread is itself an error.
>
> Having looked at your reply again, I think though your answering a
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> labVIEW to abort the vi chain, I don't want to abort a vi chain from
> within the dll. It is a feature of CIN calls which I wanted in dll
> calls.
>
> That a dll call may not be synchronous within a thread throws a wrench
> in the works. Apparently I've just chased down a dead end.
>
> Hey, but thanks for the wrench...
> Kind Regards,
> Eric

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