Random numbers to assign elements in a matrix

Hi,
I have a 4 x 4 matrix:
0000
0000
0000
0000
for (int x = 0; x < 4; x++)
for (int y = 0 ; y < 4; y++) {
cell[x][y] = new Cell();
cell[x][y].type = "0";
and I need to have any 4 random cells to be R and any other 4 random cells to be B (with no overlap) so that it looks similar to this:
0RR0
0B00
R0B0
BB0R
I have no clue how to do this, any code to get me started would be very much appriciated. Thank you so much!!!
~Britney

Just call rndShuffle and supply init as parameter.
Each time you do that you get a random sequence
(shuffling) of the int's it contains,
private static Random _rnd = new Random();
public void rndShuffle(int[] path) {
for (int i=path.length; i>0;) {
int p = _rnd.nextInt(i--);
int tmp = path[p];
path[p] = path;
path[i] = tmp;
Thanks for your help. How can I use this random shuffle method if I have an array of Strings instead?

Similar Messages

I need help with this program ( Calculating Pi using random numbers)

hi
please understand that I am not trying to ask anymore to do this hw for me. I am new to java and working on the assignment. below is the specification of this program:
Calculate PI using Random Numbers
In geometry the ratio of the circumference of a circle to its diameter is known as �. The value of � can be estimated from an infinite series of the form:
� / 4 = 1 - (1/3) + (1/5) - (1/7) + (1/9) - (1/11) + ...
There is another novel approach to calculate �. Imagine that you have a dart board that is 2 units square. It inscribes a circle of unit radius. The center of the circle coincides with the center of the square. Now imagine that you throw darts at that dart board randomly. Then the ratio of the number of darts that fall within the circle to the total number of darts thrown is the same as the ratio of the area of the circle to the area of the square dart board. The area of a circle with unit radius is just � square unit. The area of the dart board is 4 square units. The ratio of the area of the circle to the area of the square is � / 4.
To simuluate the throwing of darts we will use a random number generator. The Math class has a random() method that can be used. This method returns random numbers between 0.0 (inclusive) to 1.0 (exclusive). There is an even better random number generator that is provided the Random class. We will first create a Random object called randomGen. This random number generator needs a seed to get started. We will read the time from the System clock and use that as our seed.
Random randomGen = new Random ( System.currentTimeMillis() );
Imagine that the square dart board has a coordinate system attached to it. The upper right corner has coordinates ( 1.0, 1.0) and the lower left corner has coordinates ( -1.0, -1.0 ). It has sides that are 2 units long and its center (as well as the center of the inscribed circle) is at the origin.
A random point inside the dart board can be specified by its x and y coordinates. These values are generated using the random number generator. There is a method nextDouble() that will return a double between 0.0 (inclusive) and 1.0 (exclusive). But we need random numbers between -1.0 and +1.0. The way we achieve that is:
double xPos = (randomGen.nextDouble()) * 2 - 1.0;
double yPos = (randomGen.nextDouble()) * 2 - 1.0;
To determine if a point is inside the circle its distance from the center of the circle must be less than the radius of the circle. The distance of a point with coordinates ( xPos, yPos ) from the center is Math.sqrt ( xPos * xPos + yPos * yPos ). The radius of the circle is 1 unit.
The class that you will be writing will be called CalculatePI. It will have the following structure:
import java.util.*;
public class CalculatePI
public static boolean isInside ( double xPos, double yPos )
public static double computePI ( int numThrows )
public static void main ( String[] args )
In your method main() you want to experiment and see if the accuracy of PI increases with the number of throws on the dartboard. You will compare your result with the value given by Math.PI. The quantity Difference in the output is your calculated value of PI minus Math.PI. Use the following number of throws to run your experiment - 100, 1000, 10,000, and 100,000. You will call the method computePI() with these numbers as input parameters. Your output will be of the following form:
Computation of PI using Random Numbers
Number of throws = 100, Computed PI = ..., Difference = ...
Number of throws = 1000, Computed PI = ..., Difference = ...
Number of throws = 10000, Computed PI = ..., Difference = ...
Number of throws = 100000, Computed PI = ..., Difference = ...
* Difference = Computed PI - Math.PI
In the method computePI() you will simulate the throw of a dart by generating random numbers for the x and y coordinates. You will call the method isInside() to determine if the point is inside the circle or not. This you will do as many times as specified by the number of throws. You will keep a count of the number of times a dart landed inside the circle. That figure divided by the total number of throws is the ratio � / 4. The method computePI() will return the computed value of PI.
and below is what i have so far:
import java.util.*;
public class CalculatePI
public static boolean isInside ( double xPos, double yPos )
     double distance = Math.sqrt( xPos * xPos + yPos * yPos );
public static double computePI ( int numThrows )
    Random randomGen = new Random ( System.currentTimeMillis() );
    double xPos = (randomGen.nextDouble()) * 2 - 1.0;
    double yPos = (randomGen.nextDouble()) * 2 - 1.0;
    int hits = 0;
    int darts = 0;
    int i = 0;
    int areaSquare = 4 ;
    while (i <= numThrows)
        if (distance< 1)
            hits = hits + 1;
        if (distance <= areaSquare)
            darts = darts + 1;
        double PI = 4 * ( hits / darts );
        i = i+1;
public static void main ( String[] args )
    Scanner sc = new Scanner (System.in);
    System.out.print ("Enter number of throws:");
    int numThrows = sc.nextInt();
    double Difference = PI - Math.PI;
    System.out.println ("Number of throws = " + numThrows + ", Computed PI = " + PI + ", Difference = " + difference );
}when I tried to compile it says "cannot find variable 'distance' " in the while loop. but i thought i already declare that variable in the above method. Please give me some ideas to solve this problem and please check my program to see if there is any other mistakes.
Thanks a lot.

You've declared a local variable, distance, in the method isInside(). The scope of this variable is limited to the method in which it is declared. There is no declaration for distance in computePI() and that is why the compiler gives you an error.
I won't check your entire program but I did notice that isInside() is declared to be a boolean method but doesn't return anything, let alone a boolean value. In fact, it doesn't even compute a boolean value.

Random numbers in sumproduct function

have no success with this:     e33 has 1, f33 has 2, g33 has 3.    k22 has 4, k25 has 5, k32 has 6.       expecting (1x4) + (2x5) + (3x6) = 4+10+18= 32
    it's the outer product in matrix algebra.     in apl it's 1 2 3 +.x 4 5 6 = 32
     how is a random list or range of values entered?     thanks.     don mattern

I could be wrong, but I do not believe numbers has the power to make matrix calculations. I might suggest excel if that is an option.
This is how I would say that you need to do matrix multiplication. I am going to assume you know all the rules for multiplying matrices. First you need to have 4 separate tables with no header rows, no footer rows, nor header columns.
I will demonstrate with a (3x3)(3x3). The first two tables are the Matrices that you are multiplying.
1
2
3
4
5
6
7
8
9
9
8
7
6
5
4
3
2
1
The third is the Transpose of Table 2. In row 1 column A, place this formula =INDEX(TRANSPOSE(Table 2::$A$1:$C$3),ROW(),COLUMN()), and then fill it all the way out. And this is your result:
9
6
3
8
5
2
7
4
1
Now in the fourth table, in row 1 column A place this formula: =SUMPRODUCT(OFFSET(Table 1::$A$1,ROW()−1,0,1,3),OFFSET(Transpose of Table 2::$A$1,COLUMN()−1,0,1,3)) and fill out to the rest of the table.
30
24
18
84
69
54
138
114
90
This is a slight doozy, but I will explain when I have it written up in a few.

Random numbers in a table

I'm new to java, so please bear with me. What I want to do is create a program which chooses random numbers (between 0-9) in a table, and then presents a diagram of how many of each number comes up.
e.g. if the table size was 10, the output could be something like:
0 *
1 **
2
3 *
9 **
with the stars representing the number of times the number showed up. Any assistance you could provide would be great and appreciated. Thank you

1) Create a Map. The key will be one of the random numbers, the value will be a counter of the number of times the number has been stored.
2) Generate a random number.
3) Place the random number in the map key, and increment the value.
4)Print the random numbers and as many asterisks as the counter values.
I believe this is classwork? Asking about problems in the code that are not working is ok - asking people to write sample code for you is not ok. Part of the assignment requires you to read the documentation and figure out how to write the code.

How to generate unique random numbers

Hi All,
I am wondering whether there is already a random library or built-in function available in Java to produce some random numbers between certain ranges that are not repetitive. Let's look at a common examples as follows:
Random diceRoller = new Random();
for (int i = 0; i < 10; i++) {
int roll = diceRoller.nextInt(6) + 1;
System.out.println(roll);
}My understanding from this approach is that it allows the same number to be repeated over and over again. However, I would like to find out how to continue generating random numbers from remaining ones that haven't been generated earlier.
Using the above example to illustrate my intention:
1st random number generated - possibility of 1 - 6 showed up. Say 5 is picked.
2nd random number generated - possibility of 1, 2, 3, 4, 6 only. Say 2 is picked.
3rd random number generated - possibility of 1, 3, 4, 6 available. Say 1 is picked.
4th random number generated - possibility of 3, 4, 6 left. Say 6 is picked.
5th random number generated - possibility of 3, 4 remains. Say 4 is picked.
Any assistance would be much appreciated.
Many thanks,
Jack

htran_888 wrote:
Hi All,
I am wondering whether there is already a random library or built-in function available in Java to produce some random numbers between certain ranges that are not repetitive. Let's look at a common examples as follows:
Random diceRoller = new Random();
for (int i = 0; i < 10; i++) {
int roll = diceRoller.nextInt(6) + 1;
System.out.println(roll);
}My understanding from this approach is that it allows the same number to be repeated over and over again. However, I would like to find out how to continue generating random numbers from remaining ones that haven't been generated earlier.
Using the above example to illustrate my intention:
1st random number generated - possibility of 1 - 6 showed up. Say 5 is picked.
2nd random number generated - possibility of 1, 2, 3, 4, 6 only. Say 2 is picked.
3rd random number generated - possibility of 1, 3, 4, 6 available. Say 1 is picked.
4th random number generated - possibility of 3, 4, 6 left. Say 6 is picked.
5th random number generated - possibility of 3, 4 remains. Say 4 is picked.
Any assistance would be much appreciated.If it is your school assignment then you have the answer above (List & the lists length).
(You might want to look at Collections)

Random numbers

I'm doing a java program using random numbers.
I would like to avoid that each generated number, besides unique, is different from its index in array - for instance, the first number in array is not number 1, the second is not number 2, the third not number 3, and so one.
Can someone help ?
That�s my relevant code :
     boolean isRepeated = false;
        int [] rNums = new int [t1];
        for (int x = 0 ; x < t1 ; x++)
        do
        isRepeated = false;
       rNums [x] = (int) ((Math.random () * t1) + 1);
       for (int y = 0 ; y < x ; y++)
           if (rNums [x] == rNums [y])
       isRepeated = true;
       break;
       while (isRepeated);

Any suggestion ?Not really.
The not reapeating part by itself is easy. Either populate the array with numbers that match the indices and then shuffle, or just keep track of which numbers you've used to far and get the next number in a loop until you get one you haven't used up yet.
The no-number-at-its index (and by the way, array indices start with 0, not 1) is fairly easy. Say your array is 10 elements, 0..9. So you generate a random number in the range 0..8 (9 possible values). Say we're trying to populate index 3. If the number generated is < 3, then use it as-is. If it's >= 3, then add 1.
Putting them together is harder. And you could end up with a situation where 0-8 are populated, and the only number that's not used and the only index that's not used are both 9.
Why are you imposing these restrictions?

6 random numbers without repeat

I'm trying to make a 6 digit random number generator between 1 and 48. When the user click a button 6 random numbers show up in 6 different textFeilds. The problem is that I don't want the same number twice. How can I generate 6 different random numbers without using return and breaking out of the function?
import flash.events.Event;
stop();
btn.addEventListener (MouseEvent.CLICK, random1);
function random1 (evt:Event) {
          display1.text = "";
          display2.text = "";
          display3.text = "";
          display4.text = "";
          display5.text = "";
          display6.text = "";
          var r1 = Math.floor(Math.random()*(1+48-1))+1;
          var r2 = Math.floor(Math.random()*(1+48-1))+1;
          var r3 = Math.floor(Math.random()*(1+48-1))+1;
          var r4 = Math.floor(Math.random()*(1+48-1))+1;
          var r5 = Math.floor(Math.random()*(1+48-1))+1;
          var r6 = Math.floor(Math.random()*(1+48-1))+1;
          if (r2 == r1 || r3 == r2 || r4 == r3 || r5 == r4 || r6 == r5) {
                    return;
          var liste:Array = new Array();
          liste.push(r1,r2,r3,r4,r5,r6);
          liste.sort(Array.NUMERIC);
          display1.text = String(liste[0]);
          display2.text = String(liste[1]);
          display3.text = String(liste[2]);
          display4.text = String(liste[3]);
          display5.text = String(liste[4]);
          display6.text = String(liste[5]);

Here's the code for the approach mentioned with your textfields included
btn.addEventListener (MouseEvent.CLICK, random1);
function random1 (evt:Event) {
    var nums:Array = new Array();
    // fill the array of numbers
    for(var i:uint=1; i<=48; i++){
        nums.push(i);
    shuffle(nums);
    // grab the first six in the shuffled array
    var liste:Array = nums.splice(0,6);
    // assign the values to the textfields
    for(var j:uint=1; j<=6; j++){
        this["display"+String(j)].text = String(liste[j]);
function shuffle(a:Array) {
    var p:int;
    var t:*;
    var ivar:int;
    for (ivar = a.length-1; ivar>=0; ivar--) {
        p=Math.floor((ivar+1)*Math.random());
        t = a[ivar];
        a[ivar] = a[p];
        a[p] = t;

Array of unique random numbers - help?

basically, i'm trying to create a BINGO card.
i stared learning Java a week ago and am finding it easy to learn and use....at least so far.
my instructor gave me the assignment to created a BINGO card. so i used the system.out.format command to make 5 tab fields, 8 spaces each ("%8s %8s %8s %8s %8s", "B", "I", "N", "G", "O"). although the assignment only wanted me to think numbers out of thin air, just to use as examples, i went above and beyond with the idea to make a BINGO card generator that could actually function.
then i started the random number sequences, using the Math.random() command. all told, there are 24 of these in the program, one for each number on a bingo card. the field in the middle is the FREE space, so it has no Math.random command.
in BINGO, each letter (one of my five tab fields) can have a number in ranges of 15. B is 1 to 15, I is 16 to 30, etc. it looks similar to this:
B I N G O
9 19 39 57 66
3 28 32 51 74
3 29 FREE 46 70
14 28 43 55 67
9 24 35 59 62
as you can tell, i'm having trouble with actually making unique random numbers so that none repeat.
is there a command or string or something to help me accomplish this?

The best way I've come up with is to use an object to store the numbers that implements Collection--like ArrayList...
Then you load it with the range of numbers that you want and call, shuffle() on the object, that will randomize your range of numbers and then you can choose the quantity you want from the storage object. So let's say you need 25 number in the range of 1 to 100:
Add the numbers (you have to use classes so I would do Integers) 1 to 100;
call shuffle()
pull back the first 25 numbers
This will guarantee that each number is distinct and in a random order.
If you need multiple sheets populated, you can just call shuffle() between population of each sheet.
package Junk;
import java.util.ArrayList;
import java.util.Collections;
class Junk{
private ArrayList<Integer> l;
Junk(){
    l = new ArrayList<Integer>();
public void loadList(int s, int e){
    for(int i=s; i<=e; i++){
      l.add(new Integer(i));
public void randomizeList(){
    Collections.shuffle(l);
public void printList5(){
    for(int i=0; i<5; i++){
      System.out.println(l.get(i));
public static void main(String[] args){
    Junk j = new Junk();
    j.loadList(10,99);
    j.randomizeList();
    j.printList5();
    System.out.println();
    j.randomizeList();
    j.printList5();
}

Figuring out the occurence of random numbers?

So, I'm taking this Computer Science class, and I've been struggling so much with today's lesson.
For this particular question, I have to get 20 random numbers between 1-5, represent them in text format, and the show how often each of the numbers occured. I've done the first two of the three parts, but this last part really has me stumped..
(Note: I'm using Ready to Program by Holt.... so I'm using their console)
Here's the code I got so far:
import java.util.*;
import hsa.Console;
import java.io.*;
public class RandomNumbers
    static Console c;
    static public void main (String[] args) throws IOException
        c = new Console ();
        int a;
        Random generator = new Random();
        c.println("Generating Numbers: ");
        for(a=1;a<=20;a++)
            int r = generator.nextInt(5)+1;
                switch(r)
                     case 1: c.print("One",10); break;
                     case 2: c.print("Two",10); break;
                     case 3: c.print("Three",10); break;
                     case 4: c.print("Four",10); break;
                     case 5: c.print("Five",10); break;
}}

I had a similar assignment my last semester for C++. I would think the general idea is the same.
Here I declare an Array. Then I store the values of the dice rolled in the array and display it on the screen. The syntax will be different since you are not using C++.
#include <iostream>          // preprocessor directive
#include <ctime>          // preprocessor directive
#include <cmath>          // preprocessor directive
#include <cstdlib>          // preprocessor directive
using namespace std;     // enables preprocessor directives
int random_int(int a, int b);          // function prototpye
int main ()     // main function
     srand(time(NULL));          // enables random numbers to be generated
     int d1, d2, sum;                         // declaring variables
     int a[10] = {0,0,0,0,0,0,0,0,0,0};     // initializes valus in array to 0
     int roll;                                   // declaring variable
     cout << "Roll how many times?";          // ask number of times to roll dice
     cin >> roll;                              // get number of times to roll dice
     for(int i=0; i<=roll; i++)               // to roll the dice the numbers or times asked
          d1 = random_int(1,6);               // generates number for die 1
          d2 = random_int(1,6);               // generates number for die 2
          sum = d1 + d2;                         // adds the two dice together
          if(sum == 2)                         // increase value in array by 1 that corresponds to 2
               a[0]++;
          else if(sum==3)                         // increase value in array by 1 that corresponds to 3
               a[1]++;
          else if(sum==4)                         // increase value in array by 1 that corresponds to 4
               a[2]++;
          else if(sum==5)                         // increase value in array by 1 that corresponds to 5
               a[3]++;
          else if(sum==6)                         // increase value in array by 1 that corresponds to 6
               a[4]++;
          else if(sum==7)                         // increase value in array by 1 that corresponds to 7
               a[5]++;
          else if(sum==8)                         // increase value in array by 1 that corresponds to 8
               a[6]++;
          else if(sum==9)                         // increase value in array by 1 that corresponds to 9
               a[7]++;
          else if(sum==10)                    // increase value in array by 1 that corresponds to 10
               a[8]++;
          else if(sum==11)                    // increase value in array by 1 that corresponds to 11
               a[9]++;
          else if(sum==12)                    // increase value in array by 1 that corresponds to 12
               a[10]++;
     for(int j = 2; j<=12; j++)
          cout << j << " " << a[j-2] <<endl;          // output the array
     return 0; //exit program
int random_int(int a, int b)          // used to generate te random numbers
     int random = rand()%(b-a+1) + a;
     return (random);
}

Non repeating random numbers

Hi,
Im writing code to generate 10 random numbers and i have code written so that if a number between 1 and 10 is already chosen, it has to look for another number. heres snippets of the code:
for (int b = 0; b < 2; b++)
for (int i = 0; i < a.length; i++)
int test = (int)(Math.random() * 10);
boolean r = valueExists(test);
if (r == (true))
test = (int)(Math.random() * 10);
else
a[i] = test;
boolean valueExists(int value)
int z = a.length;
boolean exists = false;
for (int j = 0; j < z; j++)
if (a[j] == value)
exists = true;
return exists;
when i run this code, the numbers do repeat. can anyone help?

import java.util.List;
import java.util.ArrayList;
import java.util.Random;
public class RandomNumbersDemo {
    private List numbers = new ArrayList();
    private Random random = new Random();
    public static void main(String[] args) {
             RandomNumbersDemo demo = new RandomNumbersDemo();
        demo.init();
        demo.doThatVoodoo();
    public void doThatVoodoo() {
        while (numbers.size() > 0) {
            System.out.println(getRandomInteger());
    public int getRandomInteger() {
        int element = random.nextInt(numbers.size());
        Integer randomInteger = (Integer) numbers.get(element);
        numbers.remove(element);
        return randomInteger.intValue();
    public void init() {
        for (int i = 0; i < 10; i++) {
            numbers.add(new Integer(i));

Random Numbers Question

I'm working from a chapter in Gary Rosenzweig's
ActionScript 3.0 Game Programming University. In this
example 36 random cards are created and placed on the stage. I
understand most of the code except for this line:
thisCard.cardFace = cardList[r]; The line above the one I
just mentioned assigns a random value to r and I don't understand
how the computer knows it's not assigning a value to cardFace that
already exists? Since this function is iterating several times
wouldn't it be possible for one of the random numbers to be
repeated?
Joe

yes, one card is deleted. that card is thisCard.cardFace.
it's just like dealing cards. when you deal an ace of clubs
to someone, that card is removed from the deck. any card dealt
after that is randomly selected from the remaining cards.
the code above is more akin to organizing a deck of cards
with the ace of clubs on top, king of clubs beneath, queen of
clubs,...,2clubs,ace of diamonds,...,2diamonds,...,2spades. then
pick a random number between 1 and 52, select that card number and
remove it from the deck. now pic a random number between 1 and 51
and remove that from the dect. etc.

I am trying to generate an array of 30 random numbers. after every 5 readings a new vi should open and tell the user that 5 readings has been completed. and again carry on with the generation of array.

since i do not have a transducer now, i am currently generating an array of 30 random numbers. after every 5 readings a warning should be given to the user that 5 readngs are complete. this cycle should repeat. the array size is 30.
please help me out, waiting for reply asap.
once i have the transducer, i will be taking 30 analog samples and then after every 5 smaples that wraning will be displaye din a new VI
Solved!
Go to Solution.

Use a while loop with a time delay representing your sampling period.
Use the count terminal to check if equals 4, so 4th iteration=5th sample.
Use a case structure. The true case will only be executed on the 4th iteration.
In the true case place a subVI with your desired message in the front panel. Go to the VI properties window and set "open front panel when called".
The closing condition of the warnign is not giving in your description.
Consider that rather than usign a subvi for this, you could use the "One/Two/Three button dialog" or "display message" vis at the "dialog and user interface" pallete.
Please give it a try and send your own VI. Do not expect us to provide a working solution.
Regards,

How can you generate Multiple random numbers from 1 to 49?

I am very new at programming with the iPhone SDK and I need some help with a project I am working on. What I want to do is set up a window with 6 labels and 1 button. When the user clicks the button, the program will populate 6 randomized numbers each ranging from 1 to 49, and then place each of 6 numbers in a label. But each time the program ends and starts again the numbers cannot be the same, and also when the user clicks the button, no label can have the same number twice, so for example. If label 1 had the number 10, the other 5 labels cannot have that number until the button is clicked again. I know how to set up the interface, I just need the code. I would so greatly appreciate someone's help in this matter. I have been trying to do this for days and I cannot figure it out. Possibly someone who knows tons about Objective C programming can help me!
Thank-you so very much!!

I see that you're writing a lottery number generator. Perhaps the easiest way to do it is to emulate a real lottery: fill an array (NSMutableArray, probably) with the numbers between 1 and 49, pick one at random, remove that number from the array, and repeat. (You can think of the numbers as being the balls and the array as being the machine that pops them out.)
One simple way to get the random indices needed is to extract six random bytes from Randomization Services using SecRandomCopyBytes, then loop over them, using the modulo operator (%) to select an index within the size of the array.
And no, I'm not going to write your code for you. If I was going to do that, I could package and sell the app myself.

Problem with Purchase Order creation with Random numbers .

Hi Experts
Currently i am facing an issue with Bapi BAPI_PO_CREATE1 to create Purchase order with random numbers for example items 1, 3,5.
Please let me know the settings .
Thanks in Advance

Hi Neha,
A reset of the release strategy only takes place if
- the changeability of the release indicator is set to '4' in
   case of a purchase requisition and '4' or '6' in case of
   another purchasing document (purchase order, request for
   quotation, contract, scheduling agreement),
- the document is still subject to the previous release
   strategy,
- the new TOTAL NET ORDER VALUE is higher than the old one.
The total net order value is linked to CEKKO-GNETW for a purchase order,
CEBAN-GSWRT for a purchase requisition item-wise release and CEBAN-GFWRT
for a purchase requisition overall release.
If you have maintained a Tolerance for value changes during release
(V_161S-TLFAE), the release strategy is reset when the value of the
document is higher than the percentage you have specified and if the
document is still subject to the previous release strategy.
Review the SAP note 365604 and 493900 for more
information about Release strategy.
Regards,
Ashwini.

What is the importance of word account in 'Account' assignment elements

Automatic 'account assignment derivation' minimizes the manual effort of entering postings in which the 'account assignment elements' can be entered. The values derived appear as default values that you can overwrite if you wish.
FM account assignment elements, Derivation of FM Account Assignment Elements from CO Acct Assgnmnts.
These are many place where word account assignment elements is used in sap.
what is the importance of word 'Account'. What should we understand if word 'account' assignment element wording is used in FM,CO or FI.

i have tried but no one answers specific question -- What is 'account assignment element'.
its used everywhere as if everyone understands it in every module.
for e.g
FM account assignment elements are not migrated to BCS. Nevertheless, they are crucial to proper migration, since budget data is assigned to these account assignment elements. You have the following options:
· If you do not want use new FM account assignment elements in BCS, you should proceed as follows:
Migration at fiscal year-end: no specific action is required. See link below.
Migration during the course of a fiscal year: you should carry out the activation of account assignments for BCS and optionally also define your budget structure.
· If you want to use new FM account assignment elements in BCS, such as the grant or funded program, proceed as follows:
Now if someone is new to SAP what would he understand with word - FM account assignment elements
Like in FI we have GL account and in FM we have Commitment item. Two different nomenclature. Why account assignment element is used freely as If everyone else understands it, I would love to understand that how to interpret word account assignment element differently if used in different module.

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