Range Partitioning a table based on day of the week

I have a logging table which i want to partition into 7 partition, each one for the day of the week, eg MON,TUE, WED. I am aware and I can do a list partition by creating a parition key which stores 'DY' of the week and this means that I need to add another column to the existing table.
I wanted to explore the option of creating a range parition based on the timestamp column that already exists. Can anyone let me know if this option is possible?
Example
create table test_partition
( log_id number,
log_date TIMESTAMP(6),
log_value varchar2(100)
PARTITION BY RANGE (log_date)
PARTITION p1_mon VALUES LESS THAN (), ---- Not sure what can be used here to create this parition.
PARTITION p2_tue VALUES LESS THAN (),
PARTITION p3_wed VALUES LESS THAN (),
PARTITION p4_thu VALUES LESS THAN (),
PARTITION p5_fri VALUES LESS THAN (),
PARTITION p6_sat VALUES LESS THAN (),
PARTITION p7_sun VALUES LESS THAN ()
Any oracle guru with some suggestion for this would be highly appreciated..
Cheers,
VJ

Something like:
PARTITION P1_MON VALUES LESS THAN (TIMESTAMP'2009-03-10 00:00:00')
....Bear in mind that you will have to write a procedure to drop and create your daily partitions, and run that on a daily basis. Also you would be well advised to create a catchall partition that holds anything that won't go into your latest specified partition, eg:
PARTITION P_MAX VALUES LESS THAN (MAXVALUE)

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I have 7 days of week boolean parameters for which when the user selects the date range, they can also filter which days of the week to use within that date range.
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Range Partitioning for the day of the week

I have a logging table which i want to partition into 7 partition, each one for the day of the week, eg MON,TUE, WED. I am aware and I can do a list partition by creating a parition key which stores 'DY' of the week and this means that I need to add another column to the existing table.
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Example
create table test_partition
( log_id number,
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log_value varchar2(100)
PARTITION BY RANGE (log_date)
PARTITION p1_mon VALUES LESS THAN (), ---- Not sure what can be used here to create this parition.
PARTITION p2_tue VALUES LESS THAN (),
PARTITION p3_wed VALUES LESS THAN (),
PARTITION p4_thu VALUES LESS THAN (),
PARTITION p5_fri VALUES LESS THAN (),
PARTITION p6_sat VALUES LESS THAN (),
PARTITION p7_sun VALUES LESS THAN ()
Any oracle guru with some suggestion for this would be highly appreciated..
Cheers,
VJ

VJ,
Here is an example of daily partitioning , let me know if this is what you want or you can modify this even to weekly, monthly, quarterly and yearly partitions.
CREATE TABLE YY_EVENT
PART_KEY       DATE                           NOT NULL,
SUBPART_VALUE NUMBER                             NULL,
EVENT_NAME     VARCHAR2(30 BYTE)                  NULL,
EVENT_VALUE    NUMBER                             NULL
TABLESPACE TEST_DATA
PARTITION BY RANGE (PART_KEY)
PARTITION Y_EVENT_20090310 VALUES LESS THAN (TO_DATE(' 2009-03-11 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN'))
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    NOCOMPRESS
    TABLESPACE TEST_DATA,
PARTITION Y_EVENT_20090311 VALUES LESS THAN (TO_DATE(' 2009-03-12 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN'))
    LOGGING
    NOCOMPRESS
    TABLESPACE TEST_DATA
)Regards

Oracle returning incorrect day of the week

Hi there,
I have a table named Performance, which includes a date field named PDATE, some other attributes such as title, etc, and a field named WEEKDAY, which includes the numerical value for the day of the week. Here is an example:
PER#
P#
THEATRE#
WEEKDAY
PDATE
PHOUR
PMINUTE
COMMENTS
1
1
1
1
02-MAR-10
19
30
Normal evening time
2
1
1
2
03-MAR-10
19
30
Normal evening time
58
6
6
3
04-MAR-10
19
30
Normal evening time
5
1
1
4
05-MAR-10
19
30
Normal evening time
I went to verify the day of the week in a calendar (in fact I checked more than one) and I noticed that the Weekday value seems incorrect. For instance, the 2nd of March was a Tuesday so I would expect WEEKDAY to say 3 (considering Sunday to be the 1st day of the week, which is the universal norm), or perhaps 2 (considering Monday to be the 1st day of the week).
First thing that came to mind is, since the WEEKDAY is a number field which has been pre-populated, the person who populated it made a mistake.
So I went to verify this by running a query that would give me the correct day of the week by extracting it from the PDATE field:
SELECT DISTINCT pdate, EXTRACT(year from pdate) year,
to_char(to_date(pdate,'DD/MM/YYYY'),'DY') weekdaycalc, weekday
FROM ops$yyang00.Performance
ORDER BY pdate
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YEAR
WEEKDAYCALC
WEEKDAY
02-MAR-10
2010
SUN
1
03-MAR-10
2010
MON
2
04-MAR-10
2010
TUE
3
05-MAR-10
2010
WED
4
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2010
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5
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2010
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2010
SAT
7
09-MAR-10
2010
SUN
1
10-MAR-10
2010
MON
2
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Regards,
P.

Hi,
1bded5c7-e555-4306-ac86-45da83dff439 wrote:
Thanks both Frank and Solomon for the help. I am quite new to Oracle and I feel you folks went the extra mile on the explanation
Based on your explanations, I changed the formula so the date format would be processed as YY rather than YYY.
SELECT DISTINCT pdate, EXTRACT(year from pdate) year,
to_char(to_date(pdate,'DD/MM/YY'),'DY') weekdaycalc, weekday
FROM Performance
ORDER BY pdate
And I got the correct values now:
PDATE
YEAR
WEEKDAYCALC
WEEKDAY
02-MAR-10
2010
TUE
1
03-MAR-10
2010
WED
2
04-MAR-10
2010
THU
3
05-MAR-10
2010
FRI
4
06-MAR-10
2010
SAT
5
07-MAR-10
2010
SUN
6
08-MAR-10
2010
MON
7
The interesting bit here, is the original WEEKDAY field, which clearly has been created with the same mistake I did (this whole table wasn't created by me). I reckon I spotted a design bug.
Regards,
P.
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If you want to see what day of the week pdate is, then use:
TO_CHAR (pdate, 'DY')
or, to make it NLS-independent:
TO_CHAR (pdate, 'DY', 'NLS_DATE_LANGUAGE=ENGLISH')
This is simpler than what you posted, it's more efficient and easier to debug and to maintain, and it also gets the results you want in all cases.
One more time: TO_DATE, as the name hints, converts something (a VARCHAR2, to be precise) TO a DATE. If pdate is already a DATE, then what do you need to convert? You're implicitly converting a DATE to a VARCHAR2, then explicitly converting that VARCHAR2 back to a DATE, and then calling TO_CHAR. That's 3 function calls (1 of them error prone) where only 1 is needed.
Also if you ever have to reconcile 2-digit years with 4-digit years (and, again, in this problem you don't) the correct way is to convert the 2-digit year to a 4-digit year, not vice-versa.
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Rick,
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The WEEKDAY function allows specifying either Sunday or Monday as the first day of the week:
WEEKDAY
The WEEKDAY function returns a number that is the day of the week for a given date. WEEKDAY(date, first-day)
Â date: The date the function should use. date is a date/time value. The time portion is ignored by this function.
Â first-day: An optional value that specifies how days are numbered.
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Range Partitioning a table based on day of the week

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