Referencing a custom component file as a parameter in PopUpManager.createPopUp()

Question

Hello !
I'm trying to open a custom mxml file in a popUp window. The
custom TitleWindow component (myPopUpComponent.mxml) is located in
a folder "view" which is located aside my main file.
When I try to compile the following line (in the main file),
var myPopup:TitleWindow = TitleWindow (
PopUpManager.createPopUp ( this, view.myPopUpComponent, true ));
... I got the error: "1120: Access of undefined property
view."
This use to work with Flex 1.5. What's the new way of
pointing to a file in your directory structure ?
Of course, everything works fine if I put the component
directly beside the main file and use this instead:
var myPopup:TitleWindow = TitleWindow (
PopUpManager.createPopUp ( this, myPopUpComponent, true ));
But I should be allowed to have some sort of folder hierarchy
in my project ....
Is someone have come across something similar ?

Answer 1

Thanks Tracy !
That did the trick ... It was more of a FlexBuilder issue
then ...
I wonder though if there's a way to have the path as part of
the code. It should. When a custom mxml file is included in a main
file and referenced through a namespace declared in the main
container tag (eg. xmlns:MyComp="view.*"), the path to the file is
in the code, not as an IDE project's setting ... What if I was not
using FlexBuilder ?
Thanks again, JF