Regarding join statement

Question

SELECT  vbrkvbeln vbfavbelv
          vbrkfkdat vbrkkunag
          vbrpwerks kna1name1
              FROM vbrk
              INNER JOIN vbrp ON vbrkvbeln = vbrpvbeln
              INNER JOIN vbfa ON vbfavbeln = vbrkvbeln
              INNER JOIN kna1 ON kna1kunnr = vbrkkunag
              INTO CORRESPONDING FIELDS OF TABLE INVTAB
              WHERE vbrp~werks IN s_werks
              AND vbrk~fkdat IN s_fkdat
              AND vbrk~kunag IN s_kunag
              AND vbrk~fkart IN ('ZF2','FVAT')
              AND vbrk~fksto <> 'X'
              AND vbrk~rfbsk = 'C'
              AND vbrk~sfakn = ''
              AND vbrk~inco1 = 'TWO'
              AND VBRK~VKORG NE '5000'
              AND vbfa~vbtyp_n = 'M'
              AND vbfa~vbtyp_v = 'J'.
i am writng this join statement
but when displaying i am getting multiple records for a particular entry
say for a particular documnet number if it is having N no. of line itmes and when searching in vbfa thenumber of preeecig documents are M then the resords that it is disp;laying is N*M.
but in some cases it is showing records more than this
can you please help me why it is showing more records.
and in if you can explain me with an example with a dummy no of records how it will fetch record that will be a great help.

Answer 1

Hi Ashish,
please chk the following links for inner and outer join ,
http://help.sap.com/saphelp_erp2004/helpdata/en/cf/21ec77446011d189700000e8322d00/frameset.htm
http://www.sap-img.com/abap/several-nested-inner-join-statements-can-be-inefficient.htm
http://www.thespot4sap.com/Articles/SAPABAPPerformanceTuning_InnerJoinStatement.asp
now how to write join statements
SELECT
a~ebeln
a~ebelp
a~matnr
a~txz01
a~menge
a~meins
a~netpr
a~brtwr
a~netwr
a~mwskz
a~navnw
a~effwr
a~werks
b~eindt
FROM
ekpo AS a
INNER JOIN
eket AS b
ON
aebeln = bebeln
INTO
TABLE t_ekpo
WHERE
a~ebeln = t_ekko_temp-ebeln
AND b~ebeln = t_ekko_temp-ebeln.
Think there are 2 tables . a right hand table and a left hand table.
in inner join : only those fields having coresponding values in the left hand side table are selected.
in outer join all the fields on the left hand side table are selected and the fields which have no corresponding values in the right hand side table are displayed as null values..
Reward points if helpful
Regards ,
Amber S