Regarding reverse order name rajesh

Question

could u plz explain at the end of this code how it willl execute.
data : c(6) value 'rajesh'.
data : l type i,i type i value -1.
data : str(6) .
l = strlen( c ). " what will be contain in 'l"
do l times. " what is "l" here
i = i + 1.     " why we keep this "i" and i+1
                    what data it will have
l = l - 1.      " same the above
STRi(1) = Cl(1). " what STR will contain " + " what is the role of + either addition or
                              what C will contain              
could u plz explain clearly
enddo.
write STR.

Answer 1

Hi,
Find my explanation below....
data : c(6) value 'rajesh'.
data : l type i,i type i value -1.
data : str(6) .
l = strlen( c ). "l will contain the length of the string 'rajesh'. i,e -- 6
do l times. " loop at 6 times
i = i + 1. "  i will be used as offset for STR 0 , 1 ,2 ,3 ,4 to add the
              " character one by one
l = l - 1. " to decrement the L since the last char of C is added to STR
            " i,e 'h' is proccesed ... in the next loop we need to get the 's' char of C
STRi(1) = Cl(1). "
Here + stands for the offset ...
for example if i = 2   STR+2(1) .... implies  2nd char of the string STR and 1 stands for the no. of char.
In the Do loop.....
for each pass the char form C in the reverse order is added to the STR..
pass1.
STR = h , l = 6, i = 1
pass2.
STR = hs , l =5, i = 2
pass3.
STR = hse , l = 4, i = 3
pass4.
STR = hsej , l = 3, i = 4
pass5.
STR = hseja , l = 2, i = 5
pass6.
STR = hsejar , l = 1, i = 6
santhosh