Regex and matcher only returns the first match

Question

Hi all.
Im trying to rewrite some code and im using a regular expression to grab data out of a css formatted file, but im getting a bit confused. My matcher is only finding the first occurance of my pattern, how do i get it to find all occurances of my pattern?
here is a sample css file
.header
font-family:arial, verdana;
font-weight:bold;
color:#ff00ff;
background-image:url(background.jpg);
.mainBody
font-weight: bold;
color: Red;
padding 0px;
}and here is my matcher code
tstr = tstr.replaceAll("\\\\","/");
tstr = tstr.replaceAll("\\n","");
tstr = tstr.replaceAll("\\r","");
Pattern styleFind=Pattern.compile("^\\.?[\\w\\s\\W]+?\\{.*?\\}",Pattern.DOTALL | Pattern.MULTILINE);
Matcher styleMatch=styleFind.matcher(tstr);
while(styleMatch.find())
System.out.println("[A]"+styleMatch.group());
}     i thought that if i did while(macther.find) then it would keep looping through finding all of the matches, but it is only finding the first match.
any ideas what im doing wrong?

Answer 1

tstr = tstr.replaceAll("\\\\","/");
tstr = tstr.replaceAll("\\n","");
tstr = tstr.replaceAll("\\r","");
Pattern
styleFind=Pattern.compile("^\\.?[\\w\\s\\W]+?\\{.*?\\}", Pattern.DOTALL | Pattern.MULTILINE);
Matcher styleMatch=styleFind.matcher(tstr); You do MULTILINE despite the fact that you delete all end of line characters first. The '^' matches only at the very beginning of the input.
Apart from that I would prefer "[^\\}]" anytime ofer ".*?\\}", because what you want is a shortest match which often turns out not to be the same as a non-greedy match.
Harald.
Java Text Crunching: http://www.ebi.ac.uk/Rebholz-srv/whatizit/software