Regular Expression to Filter Out Special Case

I wonder if anybody knows how to use regular expressions to match any possible string in existence, exception one?
For example, lets say the string I DON'T want to match is "Foo".
Then I want a regular expression that will match (and capture) everything except EXACTLY "Foo". Therefore, "FooBar" is ok, "FooFoo" is ok, "Fool" is okay, "Java" is okay, "Supercalifragilistic Expialadocious" is okay. Absolutely anything, exception exactly "Foo".
Does anybody know if or how this can be done, using regular expressions (I know I could simply test for .equals, but the problem is, I don't have control of the code that does the validation. All I can do is supply a regular expression, and let the framework do the rest).
Thanks,
Adam

I guess I don't follow you when you say you have to use regexs, since you provide a regex to split().
Do you mean you can only use Pattern and matches(), etc?
I'm just curious now, since it looks like Sabre150 provided a solution to your problem.

Similar Messages

How do I have to define a regular expression to filter out data from file?

Hi all,
I need to extract parts of lines of a ASCII file and didn't get it done with my low knowledge of regular expressions
The file contains hundreds of lines and I am just interested in a few lines, within that lines I just need a part of the data.
One original line looks like that:
TP3| |TP_SMD|Nicht in Stueckliste|~TP TP_SMD TESTPUNKT|-|0|87.770|157.950|0|top|c| |other|TP_SMD|TP_SMD_60RF-TP
Only the bold and underlined information is of interest, I don't need the rest.
I can open that file, read in each line but then I am struggling to pick out only the lines of interest (starting with TP), taking that TP with its number and the coordinates following later on and then writing these shortened lines to a new text file. So the new line should look like that:
TP3; 87.770;157.950;0 (It doesn't matter if the separator will be ; or |)
I thought of using regular expressions - is that the right way or is there a better approach?
Thanks & regards,
gedi, using LabVIEW 8.5
Regards,
gedi

Hi max,
for finding a specific part of a string you can use the "Match Pattern" VI, it is located in the Strings Palette.
Maybe the Extract Numbers.vi example in the examples browser library can help you.
What I did to filter out my data of interest is first to sort out only the columns which I want to have -
then there are still a lot of lines remaining I don't need (this is the thing described above).
The rest I am going to filter out with a (then easy) regular expression with the "Match Pattern" VI.
Regards,
gedi
Regards,
gedi

How to use regular expression replace for this special characters?

hi,
I need to replace the below string, but i couldnt able to do if we use the special charaters '+', '$' . can anyone suggest a way to do this?
select REGEXP_REPLACE('jan + feb 2008','jan + feb 2008', 'feb',1,0,'i') from dual
anwers should be :- feb

you should use escape character \.
the regular expression will look like as follows:
select REGEXP_REPLACE('jan + feb 2008','jan \+ feb 2008', 'feb',1,0,'i') from dual
hope this is what you needed.
cheers,
Davide

ReplaceAll string by regular expression not work for this case.

I will delete all tag and want "pure text" but the output is delete all.
String content = "<aaa>pure text<fff>";
content = content.replaceAll("<.*>","");Content has output is blank because reqular expression match from begin and end of string
But when i change
String content = "<aaa>pure text<fff";
content = content.replaceAll("<.*>","");The output is ==> pure text<fff
How make req match in sequential
Please lead me to solution

peterdog1234 wrote:
Thank you very much.
I know '?' is a Quantifiers.
I do not understand using ?
Please lead me againSee the paragraph "Laziness Instead of Greediness" from [http://www.regular-expressions.info/repeat.html].

Regular Expressions

I am trying to use a regular expression to filter out certain urls from getting aliased in my httpd.conf file.
I currently have
ScriptAliasMatch /someDir/ "C:/myCGIBin/"
which redirects any urls starting with someDir.
Ex. http://www.mySite.com/someDir/someApp.exe maps internally to c:/myCgiBin/someApp.exe
The catch is that there is 1 subdirectory which should not point to the cgi-bin
/someDir/specialDir/*
So any requests to this special directory should fail the ScriptAliasMatch, while all others pass.
ex.
/someDir/somefile.exe PASS
/someDir/someOtherDir/* PASS
/someDir/specialDir/* FAILI am not sure how to build a regular expression to achieve this.

public static void test3() {
    // (?!XXXXX) is negative look ahead,
    // so the regex does not match XXXXX right after /dirA/
    String str = "/dirA/(?!dirB/).*";
    Pattern pat = Pattern.compile(str);
    String [] testCases = { "/dirA/file.exe",
                            "/dirA/goodDir/*",
                            "/dirA/dirB/*",
                            "/dirA/dirB.txt"}; // this last one is valid!
    Matcher m = pat.matcher("");
    for (int i = 0, maxi = testCases.length; i < maxi; i++)
        m.reset(testCases);
System.out.println(testCases[i] + " passes: " + m.find());

Introduction to regular expressions ... last part.

Continued from Introduction to regular expressions ... continued., here's the third and final part of my introduction to regular expressions. As always, if you find mistakes or have examples that you think could be solved through regular expressions, please post them.
Having fun with regular expressions - Part 3
In some cases, I may have to search for different values in the same column. If the searched values are fixed, I can use the logical OR operator or the IN clause, like in this example (using my brute force data generator from part 2):
SELECT data
FROM TABLE(regex_utils.gen_data('abcxyz012', 4))
WHERE data IN ('abc', 'xyz', '012');There are of course some workarounds as presented in this asktom thread but for a quick solution, there's of course an alternative approach available. Remember the "|" pipe symbol as OR operator inside regular expressions? Take a look at this:
SELECT data
FROM TABLE(regex_utils.gen_data('abcxyz012', 4))
WHERE REGEXP_LIKE(data, '^(abc|xyz|012)$')
;I can even use strings composed of values like 'abc, xyz , 012' by simply using another regular expression to replace "," and spaces with the "|" pipe symbol. After reading part 1 and 2 that shouldn't be too hard, right? Here's my "thinking in regular expression": Replace every "," and 0 or more leading/trailing spaces.
Ready to try your own solution?
Does it look like this?
SELECT data
FROM TABLE(regex_utils.gen_data('abcxyz012', 4))
WHERE REGEXP_LIKE(data, '^(' || REGEXP_REPLACE('abc, xyz , 012', ' *, *', '|') || ')$')
;If I wouldn't use the "^" and "$" metacharacter, this SELECT would search for any occurence inside the data column, which could be useful if I wanted to combine LIKE and IN clause. Take a look at this example where I'm looking for 'abc%', 'xyz%' or '012%' and adding a case insensitive match parameter to it:
SELECT data
FROM TABLE(regex_utils.gen_data('abcxyz012', 4))
WHERE REGEXP_LIKE(data, '^(abc|xyz|012)', 'i')
; An equivalent non regular expression solution would have to look like this, not mentioning other options with adding an extra "," and using the INSTR function:
SELECT data
FROM (SELECT data, LOWER(DATA) search
          FROM TABLE(regex_utils.gen_data('abcxyz012', 4))
WHERE search LIKE 'abc%'
    OR search LIKE 'xyz%'
    OR search LIKE '012%'
SELECT data
FROM (SELECT data, SUBSTR(LOWER(DATA), 1, 3) search
          FROM TABLE(regex_utils.gen_data('abcxyz012', 4))
WHERE search IN ('abc', 'xyz', '012')
; I'll leave it to your imagination how a complete non regular example with 'abc, xyz , 012' as search condition would look like.
As mentioned in the first part, regular expressions are not very good at formatting, except for some selected examples, such as phone numbers, which in my demonstration, have different formats. Using regular expressions, I can change them to a uniform representation:
WITH t AS (SELECT '123-4567' phone
             FROM dual
            UNION
           SELECT '01 345678'
             FROM dual
            UNION
           SELECT '7 87 8787'
             FROM dual
SELECT t.phone, REGEXP_REPLACE(REGEXP_REPLACE(phone, '[^0-9]'), '(.{3})(.*)', '(\1)-\2')
FROM t
;First, all non digit characters are beeing filtered, afterwards the remaining string is put into a "(xxx)-xxxx" format, but not cutting off any phone numbers that have more than 7 digits. Using such a conversion could also be used to check the validity of entered data, and updating the value with a uniform format afterwards.
Thinking about it, why not use regular expressions to check other values about their formats? How about an IP4 address? I'll do this step by step, using 127.0.0.1 as the final test case.
First I want to make sure, that each of the 4 parts of an IP address remains in the range between 0-255. Regular expressions are good at string matching but they don't allow any numeric comparisons. What valid strings do I have to take into consideration?
Single digit values: 0-9
Double digit values: 00-99
Triple digit values: 000-199, 200-255 (this one will be the trickiest part)
So far, I will have to use the "|" pipe operator to match all of the allowed combinations. I'll use my brute force generator to check if my solution works for a single value:
SELECT data
FROM TABLE(regex_utils.gen_data('0123456789', 3))
WHERE REGEXP_LIKE(data, '^(25[0-5]|2[0-4][0-9]|[01]?[0-9]{1,2})$')
; More than 255 records? Leading zeros are allowed, but checking on all the records, there's no value above 255. First step accomplished. The second part is to make sure, that there are 4 such values, delimited by a "." dot. So I have to check for 0-255 plus a dot 3 times and then check for another 0-255 value. Doesn't sound to complicated, does it?
Using first my brute force generator, I'll check if I've missed any possible combination:
SELECT data
FROM TABLE(regex_utils.gen_data('03.', 15))
WHERE REGEXP_LIKE(data,
                   '^((25[0-5]|2[0-4][0-9]|[01]?[0-9]{1,2})\.){3}(25[0-5]|2[0-4][0-9]|[01]?[0-9]{1,2})$'
; Looks good to me. Let's check on some sample data:
WITH t AS (SELECT '127.0.0.1' ip
             FROM dual
            UNION
           SELECT '256.128.64.32'
             FROM dual
SELECT t.ip
FROM t WHERE REGEXP_LIKE(t.ip,
                   '^((25[0-5]|2[0-4][0-9]|[01]?[0-9]{1,2})\.){3}(25[0-5]|2[0-4][0-9]|[01]?[0-9]{1,2})$'
; No surprises here. I can take this example a bit further and try to format valid addresses to a uniform representation, as shown in the phone number example. My goal is to display every ip address in the "xxx.xxx.xxx.xxx" format, using leading zeros for 2 and 1 digit values.
Regular expressions don't have any format models like for example the TO_CHAR function, so how could this be achieved? Thinking in regular expressions, I first have to find a way to make sure, that each single number is at least three digits wide. Using my example, this could look like this:
WITH t AS (SELECT '127.0.0.1' ip
             FROM dual
SELECT t.ip, REGEXP_REPLACE(t.ip, '([0-9]+)(\.?)', '00\1\2')
FROM t
; Look at this: leading zeros. However, that first value "00127" doesn't look to good, does it? If you thought about using a second regular expression function to remove any excess zeros, you're absolutely right. Just take the past examples and think in regular expressions. Did you come up with something like this?
WITH t AS (SELECT '127.0.0.1' ip
             FROM dual
SELECT t.ip, REGEXP_REPLACE(REGEXP_REPLACE(t.ip, '([0-9]+)(\.?)', '00\1\2'),
                            '[0-9]*([0-9]{3})(\.?)', '\1\2'
FROM t
; Think about the possibilities: Now you can sort a table with unformatted IP addresses, if that is a requirement in your application or you find other values where you can use that "trick".
Since I'm on checking INET (internet) type of values, let's do some more, for example an e-mail address. I'll keep it simple and will only check on the
"[email protected]", "[email protected]" and "[email protected]" format, where x represents an alphanumeric character. If you want, you can look up the corresponding RFC definition and try to build your own regular expression for that one.
Now back to this one: At least one alphanumeric character followed by an "@" at sign which is followed by at least one alphanumeric character followed by a "." dot and exactly 3 more alphanumeric characters or 2 more characters followed by a "." dot and another 2 characters. This should be an easy one, right? Use some sample e-mail addresses and my brute force generator, you should be able to verify your solution.
Here's mine:
SELECT data
FROM TABLE(regex_utils.gen_data('a1@.', 9))
WHERE REGEXP_LIKE(data, '^[[:alnum:]]+@[[:alnum:]]+(\.[[:alnum:]]{3,4}|(\.[[:alnum:]]{2}){2})$', 'i'); Checking on valid domains, in my opinion, should be done in a second function, to keep the checks by itself simple, but that's probably a discussion about readability and taste.
How about checking a valid URL? I can reuse some parts of the e-mail example and only have to decide what type of URLs I want, for example "http://", "https://" and "ftp://", any subdomain and a "/" after the domain. Using the case insensitive match parameter, this shouldn't take too long, and I can use this thread's URL as a test value. But take a minute to figure that one out for yourself.
Does it look like this?
WITH t AS (SELECT 'Introduction to regular expressions ... last part. URL
             FROM dual
            UNION
           SELECT 'http://x/'
             FROM dual
SELECT t.URL
FROM t
WHERE REGEXP_LIKE(t.URL, '^(https*|ftp)://(.+\.)*[[:alnum:]]+(\.[[:alnum:]]{3,4}|(\.[[:alnum:]]{2}){2})/', 'i')
Update: Improvements in 10g2
All of you, who are using 10g2 or XE (which includes some of 10g2 features) may want to take a look at several improvements in this version. First of all, there are new, perl influenced meta characters.
Rewriting my example from the first lesson, the WHERE clause would look like this:
WHERE NOT REGEXP_LIKE(t.col1, '^\d+$')Or my example with searching decimal numbers:
'^(\.\d+|\d+(\.\d*)?)$'Saves some space, doesn't it? However, this will only work in 10g2 and future releases.
Some of those meta characters even include non matching lists, for example "\S" is equivalent to "[^ ]", so my example in the second part could be changed to:
SELECT NVL(LENGTH(REGEXP_REPLACE('Having fun with regular expressions', '\S')), 0)
FROM dual
;Other meta characters support search patterns in strings with newline characters. Just take a look at the link I've included.
Another interesting meta character is "?" non-greedy. In 10g2, "?" not only means 0 or 1 occurrence, it means also the first occurrence. Let me illustrate with a simple example:
SELECT REGEXP_SUBSTR('Having fun with regular expressions', '^.* +')
FROM dual
;This is old style, "greedy" search pattern, returning everything until the last space.
SELECT REGEXP_SUBSTR('Having fun with regular expressions', '^.* +?')
FROM dual
;In 10g2, you'd get only "Having " because of the non-greedy search operation. Simulating that behavior in 10g1, I'd have to change the pattern to this:
SELECT REGEXP_SUBSTR('Having fun with regular expressions', '^[^ ]+ +')
FROM dual
;Another new option is the "x" match parameter. It's purpose is to ignore whitespaces in the searched string. This would prove useful in ignoring trailing/leading spaces for example. Checking on unsigned integers with leading/trailing spaces would look like this:
SELECT REGEXP_SUBSTR(' 123 ', '^[0-9]+$', 1, 1, 'x')
FROM dual
;However, I've to be careful. "x" would also allow " 1 2 3 " to qualify as valid string.
I hope you enjoyed reading this introduction and hope you'll have some fun with using regular expressions.
C.
Fixed some typos ...
Message was edited by:
cd
Included 10g2 features
Message was edited by:
cd

Can I write this condition with only one reg expr in Oracle (regexp_substr in my example)?I meant to use only regexp_substr in select clause and without regexp_like in where clause.
but for better understanding what I'd like to get
next example:
a have strings of two blocks separated by space.
in the first block 5 symbols of [01] in the second block 3 symbols of [01].
In the first block it is optional to meet one (!), in the second block it is optional to meet one (>).
The idea is to find such strings with only one reg expr using regexp_substr in the select clause, so if the string does not satisfy requirments should be passed out null in the result set.
with t as (select '10(!)010 10(>)1' num from dual union all
select '1112(!)0 111' from dual union all --incorrect because of '2'
select '(!)10010 011' from dual union all
select '10010(!) 101' from dual union all
select '10010 100(>)' from dual union all
select '13001 110' from dual union all -- incorrect because of '3'
select '100!01 100' from dual union all --incorrect because of ! without (!)
select '100(!)1(!)1 101' from dual union all -- incorrect because of two occurencies of (!)
select '1001(!)10 101' from dual union all --incorrect because of length of block1=6
select '1001(!)10 1011' from dual union all) --incorrect because of length of block2=4
select '10110 1(>)11(>)0' from dual union all)--incorrect because of two occurencies of (>)
select '1001(>)1 11(!)0' from dual)--incorrect because (!) and (>) are met not in their blocks
--end of test data

Firm Redirect with Set Cache Batch Updates or regular Expressions mapping?

Hello everybody,
I use the Sun Java Web Proxy as a Reverse Proxy. I want that the Proxy takes a special css-File only from a special server.
for Instance: example.css should be taken from http://server.domain.com/static/example.css
Should I use the "Set Cache Batch Updates" in the Caching-Tab or should I create a regular Expression mapping? In second case, how could the Expression looks like (SUN regular expressions are a different from normal - as I know)?
Thank you for help.
Greetings
Johannes

The regexpr. could be "http://.*/tud\\.css
But is such a redirect possible at all?
Please help me. I am a little bit helpless.
Thanks
InfoSeeker09

Regular Expressions in the new editor

Hi,
we just ubgraded to SAP GUI 6.40 and ERP 2005, when i hit ctrl-h the search and replace dialog is popping up in the new editor. But the checkbox "regular expression" is greyed out and cant be activated. Why?
cu
Rainer

Hi, I can only confirm that. The help indicates that it should work, but on the screencaps, it's grayed out too.
Besides that,
Open completion automatically after is not implemented yet (is mentioned in the help).
There are also problems with the incremental search backwards. It works only once.
Eddy
PS.
Put yourself on the SDN world map (http://sdn.idizaai.be/sdn_world/sdn_world.html) and earn 25 points.
Spread the wor(l)d!

Carriage Return - Regular Expression

Hi guys,
I'm looking for an effective method to speed up the extreme optimization process in my work (finally to not do it manually).
The particulary issue is to find a good regular expression to replace the carriage returns in the source code with nothing.
I searched on the net, and many sources converge on the RegExr tool: http://gskinner.com/RegExr/
I tried to set up an expression to solve my problem but it doesn't work. The expression that was generated by the tool is:
Find: /\r/g Replace: (none)
When i enter the expression in Dreamweaver Find & Replace panel (with regular expression option checked and match case, etc. unchecked), it seems to not produce any valid change on the code.
I'm sure that i'm wrong something.
Anyone have suggestion?
Thanks all for help.

I don't understand the point of this. There's very little to be gained from removing white space from code. And if you do this to JavaScript, you'll very likely break the code.
Safer method, go to Edit > Preferences > Code Format > click on Tag Libraries and define how you want your code formatted. Then apply with Command > Apply Source Formatting.
Nancy O.

Need Regular Expression?

Hi all,
I need the regular expression to find out any other characters present in the given string apart from the expression given (0-9,A-Z,a-z,._(underscore),-(hyphen),space). Thanks in advance.

DarrylBurke wrote:
Good regexes don't need to be obfuscated, and any attempt to do so is liable to render them more lucid :-\
dbHeh, well, x = -x; doesn't need to be obfuscated either!

Regular Expression Abbreviation of Words

Suppose I have got data in my column like
Balla Ram Chog Mal College
Maharishi Dayanand University
Cambridge Public School
Now I want to write a query using regular expressions to find out the abbreviations. e.g the resulting data set should be:
BRCMC
MDU
CPS
How should I write regexp for it ?

One way, using SUBSTR and INSTR, tested on 10g.
with data as
select 'Balla Ram Chog Mal College' col from dual union all
select 'Maharishi Dayanand University' col from dual union all
select 'Cambridge Public School' col from dual
select col, replace(ltrim(max(sys_connect_by_path(str, ',')) keep (dense_rank last order by r), ','), ',') abbr
from (
select col, substr(col, decode(level, 1, 1, instr(col, ' ', 1, level - 1) + 1), 1) str, level, row_number() over (partition by col order by level) r
from data
connect by level <= length(col) - length(replace(col, ' ')) + 1
       and col = prior col
       and prior sys_guid() is not null
order by col, level
group by col
start with r = 1
connect by r - 1 = prior r
       and col = prior col
       and prior sys_guid() is not null;
COL                           ABBR
Balla Ram Chog Mal College    BRCMC
Cambridge Public School       CPS
Maharishi Dayanand University MDU
With 11g, you will not require the Outer query to concatenate the results, you can directly use LISTAGG as demonstrated by Hashim.

[svn:bz-4.0.0_fixes] 20615: fixing the regression failure caused by the nest collection level fix, an actionscript type without remote alias will resolved as " className", we should filter out the special case

Revision: 20615
Revision: 20615
Author:   [email protected]
Date:     2011-03-04 12:11:09 -0800 (Fri, 04 Mar 2011)
Log Message:
fixing the regression failure caused by the nest collection level fix, an actionscript type without remote alias will resolved as ">className", we should filter out the special case
Modified Paths:
    blazeds/branches/4.0.0_fixes/modules/core/src/flex/messaging/io/amf/AmfIO.java

Remember that Arch Arm is a different distribution, but we try to bend the rules and provide limited support for them. This may or may not be unique to Arch Arm, so you might try asking on their forums as well.

Regular Expression Filter Mapping In Web.xml

I have a situation where I need to filter URL's that don't have a file extension. There are hundreds of URL's, so i can't specify each one separately.
From what I understand, you can have a filter mapping in web.xml to map certain file extensions to a filter, such as :
<filter>
<filter-name>MyFilter</filter-name>
<filter-class>com.filters.MyFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>MyFilter</filter-name>
<url-pattern>*.esi</url-pattern>
</filter-mapping>
...where all files of extension .esi go through the filter. Additionally, I want to map all url's WITHOUT a file extension to pass through this filter. So if I have a request for "http://myserver.com/home" it will pass through the filter.
Does weblogic support regular expressions for pattern matching in filter-mapping? If so, can you provide examples or links to documentation?
Thanks,
Jim

No, regular expressions are not supported. You can specify the mapping with extensions, or with paths, not at the same time in the same mapping specification. However, you can specify two servlet mappings, one with extension, and one with path.
The exact wording from the spec (2.4) is as follows:
In the Web application deployment descriptor, the following syntax is used to define
mappings:
• A string beginning with a ‘/’ character and ending with a ‘/*’ suffix is used
for path mapping.
• A string beginning with a ‘*.’ prefix is used as an extension mapping.
• A string containing only the ’/’ character indicates the "default" servlet of
the application. In this case the servlet path is the request URI minus the context
path and the path info is null.
• All other strings are used for exact matches only.

Trying to use regular expressions to convert names to Title Case

I'm trying to change names to their proper case for most common names in North America (esp. the U.S.).
Some examples are in the comments of the included code below.
My problem is that *retName = retName.replaceAll("( [^ ])([^ ]+)", "$1".toUpperCase() + "$2");* does not work as I expect. It seems that the toUpperCase method call does not actually do anything to the identified group.
Everything else works as I expect.
I'm hoping that I do not have to iterate through each character of the string, upshifting the characters that follow spaces.
Any help from you RegEx experts will be appreciated.
{code}
* Converts names in some random case into proper Name Case. This method does not have the
* extra processing that would be necessary to convert street addresses.
* This method does not add or remove punctuation.
* Examples:
* DAN MARINO --> Dan Marino
* old macdonald --> Old Macdonald <-- Can't capitalize the 'D" because of Ernst Mach
* ROY BLOUNT, JR. --> Roy Blount, Jr.
* CAROL mosely-BrAuN --> Carol Mosely-Braun
* Tom Jones --> Tom Jones
* ST.LOUIS --> St. Louis
* ST.LOUIS, MO --> St. Louis, Mo <-- Avoid City Names plus State Codes
* This is a work in progress that will need to be updated as new exceptions are found.
public static String toNameCase(String name) {
* Basic plan:
* 1. Strategically create double spaces in front of characters to be capitalized
* 2. Capitalize characters with preceding spaces
* 3. Remove double spaces.
// Make the string all lower case
String retName = name.trim().toLowerCase();
// Collapse strings of spaces to single spaces
retName = retName.replaceAll("[ ]+", " ");
// "mc" names
retName = retName.replaceAll("( mc)", " $1");
// Ensure there is one space after periods and commas
retName = retName.replaceAll("(\\.|,)([^ ])", "$1 $2");
// Add 2 spaces after periods, commas, hyphens and apostrophes
retName = retName.replaceAll("(\\.|,|-|')", "$1 ");
// Add a double space to the front of the string
retName = " " + retName;
// Upshift each character that is preceded by a space
// For some reason this doesn't work
retName = retName.replaceAll("( [^ ])([^ ]+)", "$1".toUpperCase() + "$2");
// Remove double spaces
retName = retName.replaceAll(" ", "");
return retName;
Edited by: FuzzyBunnyFeet on Jan 17, 2011 10:56 AM
Edited by: FuzzyBunnyFeet on Jan 17, 2011 10:57 AM

Hopefully someone will still be able to provide a RegEx solution, but until that time here is a working method.
Also, if people have suggestions of other rules for letter capitalization in names, I am interested in those too.
* Converts names in some random case into proper Name Case. This method does not have the
* extra processing that would be necessary to convert street addresses.
* This method does not add or remove punctuation.
* Examples:
* CAROL mosely-BrAuN --> Carol Mosely-Braun
* carol o'connor --> Carol O'Connor
* DAN MARINO --> Dan Marino
* eD mCmAHON --> Ed McMahon
* joe amcode --> Joe Amcode         <-- Embedded "mc"
* mr.t --> Mr. T                    <-- Inserted space
* OLD MACDONALD --> Old Macdonald   <-- Can't capitalize the 'D" because of Ernst Mach
* old mac donald --> Old Mac Donald
* ROY BLOUNT,JR. --> Roy Blount, Jr.
* ST.LOUIS --> St. Louis
* ST.LOUIS,MO --> St. Louis, Mo     <-- Avoid City Names plus State Codes
* Tom Jones --> Tom Jones
* This is a work in progress that will need to be updated as new exceptions are found.
public static String toNameCase(String name) {
     * Basic plan:
     * 1. Strategically create double spaces in front of characters to be capitalized
     * 2. Capitalize characters with preceding spaces
     * 3. Remove double spaces.
    // Make the string all lower case
    String workStr = name.trim().toLowerCase();
    // Collapse strings of spaces to single spaces
    workStr = workStr.replaceAll("[ ]+", " ");
    // "mc" names
    workStr = workStr.replaceAll("( mc)", " $1 ");
    // Ensure there is one space after periods and commas
    workStr = workStr.replaceAll("(\\.|,)([^ ])", "$1 $2");
    // Add 2 spaces after periods, commas, hyphens and apostrophes
    workStr = workStr.replaceAll("(\\.|,|-|')", "$1 ");
    // Add a double space to the front of the string
    workStr = " " + workStr;
    // Upshift each character that is preceded by a space and remove double spaces
    // Can't upshift using regular expressions and String methods
    // workStr = workStr.replaceAll("( [^ ])([^ ]+)", "$1"toUpperCase() + "$2");
    StringBuilder titleCase = new StringBuilder();
    for (int i = 0; i < workStr.length(); i++) {
        if (workStr.charAt(i) == ' ') {
            if (workStr.charAt(i+1) == ' ') {
                i += 2;
            while (i < workStr.length() && workStr.charAt(i) == ' ') {
                titleCase.append(workStr.charAt(i++));
            if (i < workStr.length()) {
                titleCase.append(workStr.substring(i, i+1).toUpperCase());
        } else {
            titleCase.append(workStr.charAt(i));
    return titleCase.toString();
{code}

Regular Expression Search for Case Statement in VBA

Hi,
I'm having trouble trying to use regular expressions in a case statement. I have a CSV spreadsheet of a server's netstat output and am trying to plot everything into Visio. I have been able to do that, however I'm not trying to expand this capability and
resuse the same code for many different servers.
I have the mainServer variable set as a Variant and in my current example it is set as "INTPXY001" (internal proxy server 001). I have tried different regex statements for the potential to have INTPXY001 - INTPXY999, EXTPXY001 - EXTPXY999, and
SVCPXY001 - SVCPXY999 in place of the Case "INTPXY001", but nothing I have tried seems to work.
'========================================
Set mainServer As Variant
Set AppVisio = CreateObject("visio.application")
AppVisio.Visible = True
AppVisio.Documents.AddEx "", visMSDefault, 0
AppVisio.Documents.OpenEx "server_u.vss", visOpenRO + visOpenDocked
mainServer = ActiveSheet.Cells(1, 2) 'sets mainServer to INTPXY001
With AppVisio.ActiveWindow.Page
Select Case mainServer
Case "INTPXY001"
.Drop AppVisio.Documents.Item("SERVER_U.VSS").Masters.ItemU("Proxy server"), 2.25, 9.25
Case Else
.Drop AppVisio.Documents.Item("SERVER_U.VSS").Masters.Item(("Server"), 2.25, 9.25
End Select
End With
'========================================

You cannot declare variables As Variant in VBScript. All variables in VBScript are implicitly variants.
If you are asking about VBA (Visual Basic for Applications), then you're not asking in the correct forum.
-- Bill Stewart [Bill_Stewart]

Regular Expression to Filter Out Special Case

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