Regular Expressions problem with OPA

hi,
I have version OPA 10.2, when I try using regualr expressions it won't let you submit data and move onto the next screen.
I've tried for example using the OPA hel's National Insurance number, I tried for a 6 digit number using:
For a minimum of 6 digits:
^\D*(?:\d\D*){6,}$
and I also tried:
^[0-9]{1,6}$
None of them worked; is there something obvious I'm missing?
Thanks

Hello,
Just tried this out and the two expressions worked as I would expect. I receive the error message as configured in the properties file and cannot progress to the next screen until I enter 6 digits or more. Is that different to the behaviour you are seeing? Also, have you tried using the debugger without screens? The error message would appear at the top of the debug window "Cannot set value of attribute 'test'. Reason: Invalid Value."
Also, are you trying to validate a text attribute or a number attribute? Number attributes can be a little trickier since the regex appears to run against them after they're converted. So if the user enters "99", the regex validates against "99.0".

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I need help with regular expressions. I have a situation when I need to get data from one table to another and I think my problem can be solved using REG EXP, but I don't know how to use them properly.
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But Still it has a problem in pattern and rectified it below.
Like :-
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DD
40
But if I (The way you test) use a non zero value like 43 ; below query will not return 43.
SQL> select regexp_substr('15/43','[^/][0 9]',1,2) DD from dual;
DD
My pattern has a slight mistake("-" missing between 0 and 9) and I changed and retested . Correct pattern - '[^/][0-9]' and now it will return 43..
SQL> select regexp_substr('15/43','[^/][0-9]',1,2) dd from dual ;
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Message Edited by Tammo on 03-06-2008 12:26 PM
Message Edited by Tammo on 03-06-2008 12:26 PM
Attachments:
RegEx1.vi ‏56 KB
BlockDiagram1.jpg ‏18 KB
FrontPanel1.jpg ‏18 KB

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:-) And I still don't understand it!It's quite easy though ;-) Suppose a word w is generated by some grammar.
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WyattEA wrote:
> Hello, i'm using find and replace with a regular express
for the first time. I
> have it checkmarked and it's finding my text but it's
missing (not
> highlighting) the ')' at the end of the line. Here's my
code:
>
> [($[0-9]+US)]
That's not how square brackets work
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least one
digit, followed by US,
followed by a right parens.
Mick
>
> it's supposed to find everything inside the square
brackets - but it misses
> the closing parenthesis after . I need to
find this string and replace
> with nothing to remove the string from any/all pages. Is
there a reason why
> it's missing the closing parenthesis? I was actually
able to add a few more
> parenthesis (e.g. "))))") before OR after the closing
square bracket and it
> still found the original text minus the closing bracket
and the extra
> parenthesis didn't prevent the text from being found.
>
> Any help is appreciated!
>
> James...
>

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Thanks for ur help

>
adding parenthesis to make order of ops more obvious. adding "?" to show un-executed calls.
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(? && ?) = ?
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