Remove XML node using Xpath

Hello,
I'm using J Developer/SOA Suite 11.1.1.6.0 and BPEL 2.0
I am trying to remove datetime nodes from xml, where the datetime value equals a certain value. So far I have the following BPEL code:
<assign name="RemoveEmptyDates">
      <extensionAssignOperation>
        <bpelx:remove>
          <bpelx:target>$GetNewHires_GetWrittenOffersReadyForUpload_OutputVariable.parameters//*[ . instance of xsd:dateTime and xsd:dateTime(.) = xsd:dateTime('0001-01-01T00:00:00')]</bpelx:target>
        </bpelx:remove>
      </extensionAssignOperation>
    </assign>
I have tried multiple variations of the predicate, but I can't seem to figure it out. Right now I am getting an error in J Developer that specifies it is expecting an "]" right after the "//*[." portion of the predicate. Any ideas on this would be greatly appreciated.
Thanks

You can't use spaces.
you have wrong this part of your text:
[ . instance of xsd:dateTime and xsd:dateTime(.) = xsd:dateTime('0001-01-01T00:00:00')]
check it.

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Retrieve xml attribute value of nth xml node using xpath query

I have an xml with following stucture...
<xml>
<header>
<DocumentReference OrderId="order001">
<DocumentReference OrderId="order002">
<DocumentReference OrderId="order003">
I have to loop through this xml and retrieve the orderId values inside Biztalk orchestration.
In the expression shape, I get the count of 'DocumentReference' nodes using an xpath query and then
Added a loopshape to make sure it loops thru all nodes
Loop condition:   n<=nodeCount     (where n is an integer variable, n=0 to begin with, incremented by 1 thru each loop, nodeCount is # of DocumentReference nodes)
I try retrieve to the orderId in the following expression shape using the below xpath query
xpathQuery = System.String.Format("//*[local-name()='OrderReference'][{0}]/@orderID)",n);
sOrderId = xpath(MsgSingleInvoice,xpathQuery);
And I get the following exception:
Inner exception: '//*[local-name()='OrderReference'][1]/@orderID)' has an invalid token.
Exception type: XPathException
Appreciate any help!   thanks!

Thanks for the quick response. I got rid of it.
And I see a different error:
Inner exception: Specified cast is not valid. Exception type: InvalidCastException
Source: Microsoft.XLANGs.Engine
Target Site: System.Object XPathLoad(Microsoft.XLANGs.Core.Part, System.String, System.Type)
Since variable 'n' is of integer type, I suspected it and changed it to n.ToString() and tested again and still see the same error.

SSMS 2012:FOR XML PATH Using XPath Node Tests-Columnn name 'test()' contains an invalid XML identifier as required by FOR XML?

Hi all,
I am learning XPATH and XQUERY from the Book "Pro T-SQL 2008 Programmer's Guide" written by Michael Coles, (published by apress). I copied the Code Listing 12-8 FOR XML PATH Using XPath Node Tests (listed below) and executed it in my
SQL Server 2012 Management Studio:
--Coles12_8.sql // saved in C:/Documemnts/SQL Server Management Studio
-- Coles Listing 12-8 FOR XML PATH Using XPATH Node Tests
-- Retrieving Name and E-mail Addresses with FOR XML PATH in AdvantureWorks
-- 16 March 2015 0935 AM
USE AdventureWorks;
GO
SELECT
p.NameStyle AS "processing-instruction(nameStyle)",
p.BusinessEntityID AS "Person/@ID",
p.ModifiedDate AS "comment()",
pp.PhoneNumber AS "test()",
FirstName AS "Person/Name/First",
MiddleName AS "Person/Name/Middle",
LastName AS "Person/Name/Last",
EmailAddress AS "Person/Email"
FROM Person.Person p
INNER JOIN Person.EmailAddress e
ON p.BusinessEntityID = e.BusinessEntityID
INNER JOIN Person.PersonPhone pp
ON p.BusinessEntityID = pp.BusinessEntityID
FOR XML PATH;
I got the following error message:
Msg 6850, Level 16, State 1, Line 2
Column name 'test()' contains an invalid XML identifier as required by FOR XML; '('(0x0028) is the first character at fault.
I have no ideas why I got this error message. Please kindly help and advise me how to resolve this error.
Thanks in advance, Scott Chang

Hi Michelle, Thanks for your nice response.
I corrected the mistake and executed the revised code. It worked nicely.
I just have one question to ask you about the appearance of the xml output of my Co;les12_8.sql:
<row>
<?nameStyle 0?>
<Person ID="1" />
697-555-0142<Person><Name><First>Ken</First><Middle>J</Middle><Last>Sánchez</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="2" />
819-555-0175<Person><Name><First>Terri</First><Middle>Lee</Middle><Last>Duffy</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="3" />
212-555-0187<Person><Name><First>Roberto</First><Last>Tamburello</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="4" />
612-555-0100<Person><Name><First>Rob</First><Last>Walters</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="5" />
849-555-0139<Person><Name><First>Gail</First><Middle>A</Middle><Last>Erickson</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="6" />
122-555-0189<Person><Name><First>Jossef</First><Middle>H</Middle><Last>Goldberg</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="7" />
181-555-0156<Person><Name><First>Dylan</First><Middle>A</Middle><Last>Miller</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="8" />
815-555-0138<Person><Name><First>Diane</First><Middle>L</Middle><Last>Margheim</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="9" />
185-555-0186<Person><Name><First>Gigi</First><Middle>N</Middle><Last>Matthew</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="10" />
330-555-2568<Person><Name><First>Michael</First><Last>Raheem</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="11" />
719-555-0181<Person><Name><First>Ovidiu</First><Middle>V</Middle><Last>Cracium</Last></Name><Email>[email protected]</Email></Person></row>
<row>
I feel this xml output is not like the regular xml output. Do you know why it is diffrent from the regular xml xml output? Please comment on this matter.
Thanks,
Scott Chang
What do you mean by regular xml document? Are you referring to fact that its missing a root element? if yes it can be added as below
USE AdventureWorks;
GO
SELECT
p.NameStyle AS "processing-instruction(nameStyle)",
p.BusinessEntityID AS "Person/@ID",
p.ModifiedDate AS "comment()",
pp.PhoneNumber AS "text()",
FirstName AS "Person/Name/First",
MiddleName AS "Person/Name/Middle",
LastName AS "Person/Name/Last",
EmailAddress AS "Person/Email"
FROM Person.Person p
INNER JOIN Person.EmailAddress e
ON p.BusinessEntityID = e.BusinessEntityID
INNER JOIN Person.PersonPhone pp
ON p.BusinessEntityID = pp.BusinessEntityID
FOR XML PATH('ElementName'),ROOT('RootName');
replace ElementName and RootName with whatever name you need to set for element as well as the root element
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How to select a specific XML node with XPath

Hi,
I'm trying to a select a specific node from my XML data using the XPath Builder. For example, say I have a process variable 'xmlData' with the
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    101
    User 2
    102
I can successfully use the following expression to retrieve the name of
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But this always returns null. I've tried surrounding /process_data/@userId
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Hi,
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A better example is:
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    user1
    User 2
    user2
I can get the following to work perfectly:
(/process_data/xmlData/users/user[userid='user2'])/name
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/process_data/@userId = "user2"
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" in the below block
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7 dbms_output.put_line( 'SBI_count '||SBI_count );
8 for I in 1..SBI_count
9 LOOP
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12 SELECT 'SID',extractvalue(VALUE(li), '//flag')
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15 END LOOP;
16 commit;
17* end;
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SBI_count 2
Row 0
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Try this code, just keep a reference to your root node so you can keep appending children to it:
DECLARE
xmlDoc xmldom.DOMDocument;
xmlNode xmldom.DOMNode;
xmlNode1 xmldom.DOMNode;
xmlElem1 xmldom.DOMElement;
xmlElem2 xmldom.DOMElement;
xmlText xmldom.DOMText;
CURSOR cur_emp IS
SELECT *
FROM emp;
--WHERE empno = 7369;
row_emp emp%ROWTYPE;
BEGIN
xmlDoc := xmldom.newDOMDocument;
xmlNode := xmldom.makeNode(xmlDoc);
xmlElem1 := xmldom.createElement(xmlDoc,'root');
xmlNode := xmldom.appendChild(xmlNode,xmldom.makeNode(xmlElem1));
OPEN cur_emp;
LOOP
FETCH cur_emp INTO row_emp;
EXIT WHEN cur_emp%NOTFOUND;
xmlElem2 := xmldom.createElement(xmlDoc,'name');
xmldom.setAttribute(xmlElem2, 'empno',TO_CHAR(row_emp.empno));
xmlNode1 := xmldom.appendChild(xmlNode,xmldom.makeNode(xmlElem2));
xmlText := xmldom.createTextNode(xmlDoc,row_emp.ename);
xmlNode1 := xmldom.appendChild(xmlNode1,xmldom.makeNode(xmlText));
END LOOP;
CLOSE cur_emp;
xmldom.writeToFile(xmlDoc,'c:\xmltest1.txt');
END;
null

How to retrieve a node using xpath in java

Hi,
I need to make an application in which on click of a button an xml is
displayed on the browser.
Now when a user selects a node in the xml then i need the xpath of the selected node for some processing.
How to retrieve the xpath.
I am using Struts framework.

There is not a specific method for achieving this.
You can store the whole xml document into a defined
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But my XML is fixed and the same XML is used everytime.
Now the structure of the XML is like it has same named nodes inside the parent node.
example :
<Human>
<Person>
<Person></Person>
<Person>
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<Human>
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Can u help regarding the same........

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import flash.display.LoaderInfo;
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Hi,
Actually i have to process multiple purchase orders which is coming from IDOC and when i didn't use the parent node i am getting all the purchase orders and then purchase order header followed with details,
But i need the detials records and purchase order header corresponding to the purchase order, so for that i have define parent node, but at the output i dont require this parent node..
i mean the output shuld look like below by removing parent node.
mt_receiver
HeaderNode
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PurchaseOrder
--Field1
--Field2
PurchaseHeader
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--Field2
Details
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--Field2
--Field3
PurchaseOrder
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PurchaseHeader
--Field1
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i think you understand now..
regards,
sai

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i assume that loc always corresponds to name. So to find the rows to remain is just a simple group by
with data as(
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