Replacing u25A1 character

Hi,
How to replace this □ character in routine while loading data from source system.
Regards,
Pravender

I had face a same problem in ABAP programming, try to use this statement... and check its removing junk character.
Data : A(35) type C,
          B(35) type C,
   CLASS cl_abap_char_utilities DEFINITION LOAD.
   clear : A,B.
   A = your_field.
   concatenate A cl_abap_char_utilities=>cr_lf INTO B.
   REPLACE ALL OCCURRENCES OF cl_abap_char_utilities=>cr_lf In B WITH
   space.
   your_field = B.
Best Regards,

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Replacing a character in a string to another character

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I want to Replace all the Existence of the word - "Test" in a string with "Test1" whereever a space exits before the word Test and someother alphabet after "Test" i.e. Test will be replaced with Test1 if a word starts with Test and contains more alphabets also. For example - TestName should be replaced with Test1Name while MyTest should not be updated to MyTest1.
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Graphical mapping does not support special character like & , <,> to be mapped.
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if you want the special character to be used, Opt XSLT mapping with ISO-8859-1 encoding
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How to replace a character in a string with blank space.

Hi,
How to replace a character in a string with blank space.
Note:
I have to change string CL_DS_1===========CM01 to CL_DS_1 CM01.
i.e) I have to replace '=' with ' '.
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Hi,
Try with this..
call method textedit- >replace_all
exporting
 case_sensitive_mode = case_sensitive_mode
 replace_string = replace_string
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 whole_word_mode = whole_word_mode
changing
 counter = counter
exceptions
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Parameters Description Possible values
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Replace a character in a String array

I have an array of strings and am trying to replace the ' character with a space. I keep getting either a cannot be applied or cannot resolve symbol error. Can anyone help?
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the replace method of the String class takes two parameters and both of them are characters not strings use it like this
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There is a method in String that replaces all
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Find/Replace Extended Character Set characters in filenames in one pipeline

Hello all,
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Answer would depend on the way you want to replace... Easier if you want replace any char in set with selected char:
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But if you want it more complicated, you may do that too. E.g. defining hashtable that can be used to replace individual elements:
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Get-ChildItem * | Rename-Item -NewName {
[regex]::Replace(
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º { "0" }
µ { "u" }
¹ { "1" }
¸ { "," }
Default { "_" }
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Replace a character

Hi all
I have a ascii file should I replace a character with another. How can I do with form?
regards
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Open the file with a text editor would be the simplest solution:
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Hello,
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Regards,
Edited by: slsam01 on Jul 15, 2012 12:56 PM

Hi
awk it's not best for this job.
For replace charecter - generaly use tr or sed
Example on awk:
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Regards.
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Replace single character and leave the ones in expressions

Hi,
I'm looking for nice and elegant solution to my problem. Let's say I have a string "e+exp(e)". I want to replace all "e" with "1", excepts the one in "exp". I was trying to use regular expressions but I've failed after an hour... The solution should be able to solve things like replace "a" in "rand(a)" without changing rand. Basically I need to replace single character without replacing the ones in words/expressions.
Any ideas?
Certified LabVIEW Developer, Certified TestStand Developer
Solved!
Go to Solution.

No time for elegance right now, just brute force. I would pad the string with spaces on each end to remove end cases and then search for the character surrounded by non-word characters.
Message Edited by Darin.K on 04-14-2010 04:06 PM
Attachments:
VariableParsingRegex.png ‏18 KB

How to replace a character at a random position of a column in SQL Server 2000?

Hello everyone,
I'm trying to export the data of a table into a flat file. However, when I try to export it, a column which has a specific character (".") is being loaded as a new column into the file rather than the same column.
Here is the DDL/DML:
CREATE TABLE [dbo].[EXT_Name](
[A_Name] [VARCHAR](4),
[U_Name] [VARCHAR](256),
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[Acc_Desc] [VARCHAR](256),
[S_Type] [VARCHAR](50))
Its just that's it. No more Keys and Indexes on this table.
Here is the bcp command I'm running:
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Data:
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Instead for the data to be loaded as the above, its loading into the file as
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This issue occurs only when [Acc_Desc] column has the "." character in between the string. Could experts in this forum help me please?
Thank you,
Bangaaram
Known is a DROP, Unknown is an OCEAN.

That is most likely not your problem. Your problem is most likely the source data has a CR and/or LF after it in the database.
Run this to remove them from Acc_Desc:
UPDATE [dbo].[EXT_Name]
SET [Acc_Desc] = REPLACE(REPLACE([Acc_Desc],CHAR(13),''),CHAR(10),'')
Perfect! Thank you Tom :)
Known is a DROP, Unknown is an OCEAN.

Replace hex character in a string with another hex character

Hi Guys,
Heres a problem scenario, hex character 92 looks very much like hex character 27 (apostrophe).
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-Anil

I don't think you need to use regex to do this:
String s = something();
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Replacing the \ character in a string

I'm having trouble replacing a backslash in a string. I use .indexOf() to find the character, but I have to use an escape character and write .index("\\"), but it doesn't work - it returns -1.
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thx

The escape is for the compiler, I think, and then you need to escape the backslash.
Try "\\\\".
� {�

Replace a character in a string

Hi,
I've been tearing my hair out trying to do something very simple, replace a backslash character in a string with an underscore. I've searched online and discovered the -replace parameter which you would think would work fine but no, it seems to get in a
tizzy because the character I want to replace is a backslash and I get an error: "Invalid regualr expression pattern".
Here's what I have which produces the error:
$str = 'start\end'
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Can someone tell me how to do this? I simply want to replace a backslash with an underscore.
thanks
Jamie
http://sqlblog.com/blogs/jamie_thomson/ |
@jamiet |
About me

sod's law. I spend half an hour trying to figure this out and then as soon as I post this thread I figure it. The following works:
$str = 'start\end'
$str = $str -replace '\\','_'
$str
http://sqlblog.com/blogs/jamie_thomson/ |
@jamiet |
About me
"-replace" requires a regular expression for each argument, which is why you needed to escape your backslash with another backslash. If you use the replace() string method, you are not required to use regular expressions:
$str = $str.replace('\','_') will work exactly as you expect it to.

Replacing u25A1 character

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