Reverse or oposit help

Question

i have field  ( 3 - 8 )
i need to look like ( 8 - 3 )  how i can do it.

Answer 1

Hi little richi
               Please try to use this code.
DATA v_text(20) TYPE c.
DATA v_new_text(20) TYPE c.
DATA v_num TYPE i.
DATA v_i TYPE i.
DATA v_2i TYPE i.
v_text = '( 8- 3 )'.
v_num = STRLEN( v_text ).
v_2i = 0.
v_i = v_num - 1.
DO v_num TIMES.
  IF v_textv_i(1) <> '(' AND v_textv_i(1) <> ')'.
    WRITE v_textv_i(1) TO  v_new_textv_2i(1).
    v_i = v_i  - 1.
  ELSE.
    WRITE v_textv_i(1) TO  v_new_textv_i(1).
    v_i = v_i  - 1.
  ENDIF.
  v_2i = v_2i + 1.
ENDDO.
WRITE :/ v_text.
WRITE: / v_new_text.
Regards
Wiboon