Run TIme Error Message- Array Out of Bounds Exception

Question

Good evening all,
I seem to have a run time error with the below segment of code. I've changed the (args[0]) a variety of ways but still get the same message.
I have a few questions regarding my methodology. First, am I headed down the right path (no spoonfeeding allowed please! I need to grasp and learn this myself). Second, would it be something causing error that is on another line and I'm not seeing it. Third, should I have added the entire class file?
public static void main(String [] args) throws IOException
   Inventory store = new Inventory ( 15);  // Sets store inventory
   Scanner inFile = new Scanner(new File(args [0])); // _Line 27 in the program_
   PrintWriter outfile = new PrintWriter(args [1]); 
   String temp; .
   double price; 
   int quantity; .
   inFile.next();
   int x = 0; Run time error received:
java.lang.ArrayIndexOutOfBoundsException: 0
     at StoreBusiness.main(StoreBusiness.java:27)
Thank you in advance everyone.

Answer 1

WarriorGeek wrote:
Thanks Flounder,
I feel pretty dumb after posting my answer.
I read the arrays tutorial and understand all that's described there but with what I've learned you have to start your array out at zero like I did. Should I use the variable name that I gave it in lieu of zero?No. The point is that since you didn't provide any arguments when you started your program, there is no arr[0] or arr[anything else]. It doesn't matter if you put an int literal between the brackets or a variable or a method that returns int. You can't access elements that don't exist.
So instead of java MyClass you need to do java MyClass something The "something" becomes args[0]. If you're using an IDE instead of the command line, there will be a place to configure what arguments you want to pass when you run your program.