Running Multiple JDKs on the Same Machine

I've been developing with the 1.4.2_07 JDK, but my
company is moving to the 1.5.0 JDK as the new
standard for our product. Of course, we're going to
continue supporting the 1.4.x JRE as a deployment
platform for the near term.
As a developer, I'm going to need to have both JDKs
installed, side-by-side so that I can use both of
them in my development/testing cycles. So I just
downloaded and installed the 1.5.x JDK, and I defined
the following environment variables:
JAVA_HOME_1_4 = C:\j2sdk1.4.2_07
JAVA_HOME_1_5 = C:\Program Files\Java\jdk1.5.0_02
JAVA_HOME = %JAVA_HOME_1_4%
In theory, I should now be able to switch JDKs just
by changing my JAVA_HOME variable to
%JAVA_HOME_1_5%.
Easy as pie.
Unfortunately, that doesn't work, because the 1.5 JDK
installs a number of registry keys which hard-code
the current java version. So, even when I have
JAVA_HOME set up to point to the 1.4.x JDK, running
"java -version" at the commandline indicates that the
1.5 java is being called.
I'd like to suggest to Sun that, in the future, there
should be a generic, version-independent launcher
that reads in the JAVA_HOME variable at runtime and
calls the appropriate binaries and the appropriate
runtime libraries.
Having to futz around with the registry every time I
want to switch my development environment is a big
hassle.
--BenjiSmithI've tried the same approach, but abit different
first - deleted java.exe and javaw.exe from %SystemRoot%\system32
Then set the following (All vars are system ones)
JAVA_HOME=D:\sun\jdk1.5.0_04
JAVA_HOME_1.4=D:\sun\j2sdk1.4.2_08
JAVA_HOME_1.5=D:\sun\jdk1.5.0_04
JAVA_HOME_BIN=%JAVA_HOME%\bin
PATH=%JAVA_HOME_BIN%;...
Now by switching JAVA_HOME we should get it right
but,
it appears that xp recognizes the new values for vars only upon rebooting.
Also, you can see all current vars by typing set in cmd
More over, I thought that maybe it'd work if I just simply logout/login back, and it did but strangely the var while JAVA_HOME showed a new value, JAVA_HOME_BIN had the previous one.
HMM...

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function(){return A.apply(null,[this].concat($A(arguments)))}
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