Search and replace YYYYMMDD to DD-MM-YYYY (in file)

I have a problem with date formatting. There is a mismatch between my banks .csv file and the standard of iBank...
I would like to make an AppleScript (or Automator/AppleScript) app which search .csv file for strings "YYYYMMDD" and replaced it with "DD-MM-YYYY", but frankly I am not an AppleScript star There is a line of the .csv file below.
"NL000BANK0000000000";"EUR";"20130101";"C";"100.00";"NL000BANK0000000000";"";"20 130102";"";"";"Accountholder";"Transactionnote";"";"";"";"";"";"";""
Does anybody can help me with it?

You could run the following in an Automator "Run Shell Scrpt" (or Applescript)
awk '
        while( match($0,/\"[1-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]\"/) ) {
            date = substr($0,RSTART+1,8)
            year = substr(date,1,4)
            month = substr(date,5,2)
            day = substr(date,7,2)
            new = day "-" month "-" year
            if ( month+0 >= 1 && month+0 <= 12 &&
                 day+0   >= 1 && day+0   <= 31 &&
                 year+0  != 0                  ) {
                sub(date,new,$0)
        print
' $1 >$HOME/new_$1
You would change the "Pass input:" to "as arguments" which will populate $1 with the file you drag and drop onto the Automator app you create.
The script will create a new file in your home folder with "new_" in front of the name from the file you dragged and dropped onto the automator app you create.

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    I can't get the format to have a number from 1-99. The number of replacements should add up to 6 in this case. I have tried with \d for any number, and I also tried [1-99].
    Solved!
    Go to Solution.

    Right click on the Search And Replace String function.  There is an option to use Regular Expressions.  Then give this a try.
    EDIT: You will need to set the Replace All input to TRUE.
    There are only two ways to tell somebody thanks: Kudos and Marked Solutions
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    Attachments:
    Match Pattern.png ‏12 KB

  • Search and replace string problems

    Hi to all,
    I have problem with Search and replace string function. It shows me a wrong Value (Number) from 15 to 100 is everything OK (15=0, 30=1, 45=2, 100=3), but after 100 ........
    Take look in VI and if you have any ideas post them please
    THX
    Igor 
    Attachments:
    indexing.vi ‏10 KB

    there will be no 15115 string, but 15 or 115 and 15 is 0, 115 is 4. Anyway, i have changed string input format and now its working THX for your help
    Attachments:
    indexing.vi ‏10 KB

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