Search for a regular expression in TextEdit's Find panel?

Is it possible to search for a regular expression using TextEdit's Find panel? (This used to be possible in 'Step.)
Help yields nothing, but perhaps there's some hidden technique?
Thanks.

What do you define as a "row"? Is each row a single array element? Since your array elements are strings, each array element itself could be a multiline|multirow string itself that might need to be analyzed one row at a time.
To look for patterns:
If you have LabVIEW 8.0 or higher, you can use "Match regular expression". Else you can use "Match Pattern". It really depends how specific you need to be. Are there lines that start with "Date:" but don't contain a formatted date afterwards?
To search for array elements starting with simple string "Date:", use "match first string".
LabVIEW Champion . Do more with less code and in less time .

Similar Messages

Search for a regular expression in a 1D array?

I've got a 1D array of strings, and I want to find the row with "Date: yy/mm/dd" in it. Since yy/mm/dd would not necessarily be the same between runs, I can't look for the row with "Date: yy/mm/dd".
I tried using the Search 1D Array with "Date: " and "Date: *" as my element input, but it didn't find either of 'em.
I don't know where in vi.lib the function would be in, otherwise I'd attempt to mod the function to take regular expressions, and my off-the-cuff search attempt (looping through the array & using Match Regular Expression) had some odd errors and still didn't find the row.
Thanks!

What do you define as a "row"? Is each row a single array element? Since your array elements are strings, each array element itself could be a multiline|multirow string itself that might need to be analyzed one row at a time.
To look for patterns:
If you have LabVIEW 8.0 or higher, you can use "Match regular expression". Else you can use "Match Pattern". It really depends how specific you need to be. Are there lines that start with "Date:" but don't contain a formatted date afterwards?
To search for array elements starting with simple string "Date:", use "match first string".
LabVIEW Champion . Do more with less code and in less time .

Just installed Firefox 4 but when I try to search for add-ons every result fails to find anything or the loading gui just keeps spinning. What should I try to fix this problem?

Just installed Firefox 4 but when I try to search for add-ons every result fails to find anything or the loading gui just keeps spinning. What should I try to fix this problem?

Glad you seem to have sorted things out.
The warning about the warranty is light hearted, I think at one stage it warned "here be dragons" but also intended to make us think as it warns that making changes may produce problems.

How do I search for an App? I want to find a specific app. – not what's popular, not what's best selling, not what's new – there is no search

How do I search for an App? I want to find a specific app. – not what's popular, not what's best selling, not what's new – there is no search box!!

Is this on a computer's iTunes or an iOS device ? On a computer's iTunes when viewing the store the search box at the top right of iTunes should search the store :
The on the results screen select Apps.
On an iOS device you should have a search tab at the bottom of the App Store app.

Looking for a regular expression that doesnt take in account java comments

Does somebody knows the valid Regular Expression to match 'cat', but none of this:
//cat
// cat
// cat
//   cat
// something catI've tried with some patterns without success:
[^/][^/](\\s)*cat
(?<!//)catI want to use this, for example, to search java code to detect uses of "System.out" not commented.
thanks

The direct approach--finding the text first and then figuring out whether it's a valid match--won't work. Java supports two other kinds of comment plus string literals, any of which could contain the text you're looking for. Also, comments can contain literals, string literals can contain things that look like comments, even char literals can contain quotation marks. The only way to be sure you're getting valid matches is to actively search for comments and literals so you can ignore them. Pattern p = Pattern.compile(
    "//.*+|"                            // inline comment, or
+ "/\\*(?:[^*]++|\\*(?!/))*+\\*/|"    // multiline or javadoc comment, or
+ "\"(?:[^\"\\\\]++|(?:\\\\.))*+\"|" // string literal, or
+ "\'(?:[^\'\\\\]++|(?:\\\\.))*+\'|" // char literal, or
+ "(System\\.out)"                    // bingo
Matcher m = p.matcher(str);
while (m.find())
if (m.start(1) != -1)
    // bingo
}

Inline display of error message for a regular expression validation

Hi All,
I am using ApexLib in my application.
I am using regular expression validation for some of the items.
Those validation will happen when the button is pressed and the message will be displayed as per the error.
But, I want the errors to be displayed immediately when the focus is away from that item.
as we do for required items.
could anybody help me to achieve it?
Thanks in advance
bye
Srikavi

Hi Srikavi,
to achieve a Validation of an item when leaving the field you'll have to use some javascript code (as ApexLib does internally).
What do you need:
- onChange - Event on your Item
- some Javascript code which is called in the onChange Event (you can put this code either in your page html header or, if it is used more often in your application, in a seperate js File)
- call the ApexLib method apexlib.error.showError to display your error
I actually never tried it myself, but i'm pretty sure that this will work (according to what i've seen in the ApexLib code).
Have fun and tell us how it went,
Peter
Edited by: peter_raganitsch on Sep 5, 2008 11:56 AM

ALC-FUT-001-007: Syntax error in the regular expression *. from File Utilities - Find in ES2

Has anyone encountered the above error when trying to use the Foundation - File Utilities service Find?
This is occuring in ES2, and I have tried using an asterisk, as well as the exact file name I know exists.
I have tried literals in the Process Properties, as well as passing it in via string variables.
Any help is appreciated.
Thanks
Mark

Thanks for your response.
Here is what we have learned:
We should not put the regular expression value in single quotes - eliminates the error.
The problem is, the Find operation always returns an empty list no matter what criteria we enter - even C:\ with criteria = *.*
ES 2 is running on a Windows 2003 machine.
Thanks Again
Mark

When I try to enter my Printer model to search for drivers on HP support site the input panel disappears . It was OK in previous Firefox versions but not in 18.

I tried to search for driver for one printer at HP web site. When you go on support page you are presented with 3 options. If you click on the first to search for drivers a panel is displayed that has input box to enter your printer model. When I click on that input box the panel disappears.

'''Try the Firefox SafeMode''' to see how it works there. <br />
''A troubleshooting mode, which disables most Add-ons.'' <br />
[https://support.mozilla.org/en-US/kb/troubleshoot-firefox-issues-using-safe-mode#w_safe-mode-window_2 Troubleshoot Firefox issues using Firefox SafeMode]
When in Safe Mode... <br />
* The status of plug-ins is not affected.
* Custom preferences are not affected.
* All extensions are disabled.
* The default theme is used, without a persona.
* userChrome.css and userContent.css are ignored.
* The default toolbar layout is used.
* The JIT Javascript compiler is disabled.
* Hardware acceleration is disabled.
* You can open the Firefox 15.0+ SafeMode by holding the '''Shft''' key when you use the Firefox desktop or Start menu shortcut.
* Or use the Help menu item, click on '''Restart with Add-ons Disabled...''' while Firefox is running.
''To exit the Firefox Safe Mode, just close Firefox and wait a few seconds before using the Firefox shortcut (without the Shft key) to open it again.''
'''''If it is good in the Firefox SafeMode''''', your problem is probably caused by an extension, and you need to figure out which one. <br />
http://support.mozilla.com/en-US/kb/troubleshooting+extensions+and+themes
''When you figure out what is causing that, please let us know. It might help other user's who have that problem.''

How to search for 'period single space any letter' in find/change

Hi, i'd like to check my document to make sure that between all periods and first words of a sentence there are not single spaces but double spaces. Is there a way to search for any instances of single spaces that appear after a period?

Firstly, when I said InDesign inflates the space I didn't mean it whacked in a great chunk of space. It just gives a little bit more air relative to the fit of the text around it. You may not always see any noticeable difference. But when I read a book I don't want to see obvious white spaces at the start of every sentence. As long as the full point and following capital letter register on my brain fast enough that I am reading a new sentence, that's good enough for me. I think it makes reading more fluid. If you want to see extra space at the start of a sentence, then it's probably best to carry on with your double spacebar - unless you want to try something more exotic like a fixed width space.
I didn't mean you to literally type <full point><space><any character> into the find. I was just trying to tell you what to input. Type the full point, hit the spacebar, and then use the options list to the right of the find field (shown as a @), select "Wildcards", then select "any character". What you should see in your find field is . ^?
You could then enter . ^? - that's two spaces. See why I spelled it out as <space>? - into the change to field.
k

Which Regular Expression to use to find white spaces?

Hi all,
I have this code that reads lines of text from a text file containing words and all types of white spaces. It's then suppose to split it into words and assign to a word array. I use "\\s+" as the delimiter but it won't read in words after a tab space in the text file.
Does anyone know a better regular expression/delimiter I could use?
My code so far:
try
               br = new BufferedReader(new FileReader(args[0]));
          catch (FileNotFoundException fnfe)
               System.out.println("Error opening file '" + args[0] + "'. " +"Please omit .txt extension.");
               System.exit(3);
          boolean finish = false;
          String input = null;
String[] array=null;
          //read lines until end of file is reached
          while (!finish)
               try
                    input = br.readLine();
               catch(IOException ioe)
                    System.out.println("I/O error");
                    System.exit(2);
               //end of file?
               if (input==null)
                    finish=true;
               else
                    array = input.split("\\s+");
          }

here's my 2nd version using stringtokenizer:
String[] array = null;
BufferedReader br = null;
br = new BufferedReader(new FileReader(args[0]);
          catch (FileNotFoundException fnfe)
               System.out.println("Error opening file '" + args[0] ");
               System.exit(4);
          boolean finish = false;
          String input = null;
               try
                    input = br.readLine();
               catch(IOException ioe)
                    System.out.println("I/O error");
                    System.exit(3);
               //end of file?
               if (input==null)
                    finish=true;
               else
                    StringTokenizer tokens = new StringTokenizer(input);
                    count = tokens.countTokens();
                    array = new String[count];
                    int i=0;
                    while (tokens.hasMoreTokens())
                         array[i] = tokens.nextToken();
                         i++;
               }it only returns the last line of the text file. How do i get it to read all the words into the array?

Syntax error for using Regular Expression

HI all,
I tried to use Regular expresion to convert my string
my sample code is like this:
REPLACE ALL OCCURRENCES OF REGEX '\w*' IN INTAB-SCITY WITH '$1_$2'.
REPLACE ALL OCCURRENCES OF REGEX '\w*' IN INTAB-DCITY WITH '$1_$2'.
REPLACE ALL OCCURRENCES OF REGEX '\w*' IN INTAB-BCITY WITH '$1_$2'.
While activating, I got this syntax error:
The word REGEX is reserved
What happen? Did I got a old ECC version? Or something else got wrong??
Any help would be appreciated.
Edited by: Chih-Chieh Chan on Dec 10, 2008 8:58 AM

My ECC version is 5.0
does it make some difference?

I downloaded an app. then upgraded my new 4s to IOS7, and the app icon disappeared, the onlly way to access the app is to go to the app icon and search for it, and then open, I cannot find the app icon, but the provider says it is stored somewhere ?

How or where do I find the app in the iphone, the provider says it is stored somewhere?

More than likely it is on an altenate home screen (swipe to the left to navigate), or in a folder. When you did the spotlight search, did it indicate as folder?

Regular expression: multiple possible matches, find all?

Hi, I'm looking over something I'm afraid, the solution to my problem will probably be simple :(
Consider the input string "something aname bname something"
I have a list of other strings that might occur in the string:
"aname"
"aname bname"
I want to know if any of the strings in the list occurs in the input string, possibly both.
For this, I created the pattern "(?i)(aname)|(aname bname)(?i)"
With a Matcher, it will only match the "aname", while I want to find both the "aname" and the "aname bname".
Reversing the pattern, "(?i)(aname bname)|(aname)(?i)", it will only find "aname bname", and not the single "aname".
I cannot really create a very sofisticated pattern such as "(aname( bname)?)", since the list of strings comes from a database. Creating a very nice pattern by looking at the possible matcher strings before compiling the pattern is not really a clean solution.
Again: what is my at-this-point-non-functional-brain missing? Thanx!

Thanks for the link. Of course I have read the manual, I guess there is something wrong with my eyes because I don't immediatly see the answer. Last weekend I already ordered new glasses, but they take three to four weeks to deliver my new glasses. Could you in the mean time point me to the exact place I should look?
In all seriousness, I already tried the Matcher. It's the pattern itself that causes it to match only the first alternative in the list of groups in that pattern. I did read the Pattern manual here.
My test code:          String input = "something aname bname";
          String match1 = "aname";
          String match2 = "aname bname";
          String quotedPattern = "(?i)(" + Pattern.quote(match1) + ")|(" + Pattern.quote(match2) + ")";
          System.out.println(quotedPattern);
          Pattern p = Pattern.compile(quotedPattern);
          Matcher m = p.matcher(input);
          while (m.find()) {
               for (int i = 0; i < m.groupCount() + 1; i++) {
                    System.out.println("Group " + i + ":\t" + m.group(i));
          }Outputs:
(?i)(\Qaname\E)|(\Qaname bname\E)
Group 0:     aname
Group 1:     aname
Group 2:     null
The last matching group should also match in my opinion. If I turn the pattern around, i.e. first "aname bname" and then "aname", it will still only find "aname bname" and not "aname", which would also match.
Thanks again

Regular Expressions - Logical AND

I know this isn't Java, and it's not really an algorithm, but I can't figure this out. I hope amongst this bright group of developers someone can help me.
I am searching for a regular expressions that will match a series of words.
Example:
Given the words: "ship book"
What regular expression could be used to find both the word "ship" and the "book"?
I have found one expression that will do it ... ship.*book|book.*ship
But that expression doesn't scale. Does anyone know of a better way?
Thanks,
BacMan

Hi,
How about something like:
public class Regexp1
   private static final Pattern all = Pattern.compile(
         "^(\\s*\\b(monkey|turnip|ship|book)\\b\\s*)*$" );
   private static final Pattern p = Pattern.compile(
         "\\s*\\b(monkey|turnip|ship|book)\\b\\s*" );
   public static void main( String[] argv )
      find( "ship book turnip monkey" );
      find( "monkey giraffe mango" );
      find( "ship shipship ship" );
   public static void find( String text )
      System.out.println( "Text: " + text );
      Matcher m = p.matcher( text );
      System.out.println( "Matches all: " + all.matcher( text ).matches() );
      while ( m.find() )
         System.out.println( "Matching word: '" + m.group(1) + "'" );
   }which will produce this when run:
Text: ship book turnip monkey
Matches all: true
Matching word: 'ship'
Matching word: 'book'
Matching word: 'turnip'
Matching word: 'monkey'
Text: monkey giraffe mango
Matches all: false
Matching word: 'monkey'
Text: ship shipship ship
Matches all: false
Matching word: 'ship'
Matching word: 'ship'Pattern all tests to see if all the words are present.
Pattern p finds each matching word and ignores others.
Ol.

How to Search for "(" error in a string?

I am trying to search for "(" in a string, however the compiler thinks that I searching for a regular expression, and fails.
Exception in thread "main" java.util.regex.PatternSyntaxException: Unclosed group near index 1
Please help me find a way to search for "(" in a string.
Example:
String test="This is a test.";
if (test.matches("(")){
System.out.println("There is a match")
I also tried:
test.matches("\050")
and test.matches("\(")
Thank you!

I also tried:
test.matches("\050")
and test.matches("\(")For this particular problem, I think indexOf is a more appropriate solution. However, for future reference, I think what you want to do for parentheses is escape the backslash, not the bracket.
i.e.
test.matches("\\(");

Search for a regular expression in TextEdit's Find panel?

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