Searching file from directory located at http path.

Hi All,
I have made the program to search for a file in a directory and its subdirectories. This is working fine when my directory is located on local machine. But if the same directory is placed in HTTP path, the code fails to search a directory. Does anyone has idea how can i connect to site so as to access the directories. I used URL and URLConnection to read and write file to the site, and this is also working fine but when it comes to directories i find no solution. Please help.

This works fine if i map http://flash/ on my C: and
try to list files in directory C:\Mojo. Can you please
tell how can i know whether the http server i am
trying to access allows directory listing or not.
Because if it does not i have administrator rights on
the server and i can make the changes required.You can see if your Web server allows directory listing by simply
typing in the URL you want to examine, inside your browser, and see if
it shows you a directory listing. For instance, if you type in:
http://flash/Mojo/
in your browser's address bar, and you see a list of files in that
directory, then your Web server supports directory listing.
Note, though, that you can't use the File list() method to get a list of files.
You'll have to make a connection, read the input stream, and then parse
the filenames out of the HTML that the Web server returns. (You can see
what the HTML looks like, by doing View Source inside your brower. That's
what you'll get back from your Java program.)
--Steve

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Delete File from URL located on HTTP Server.

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Hi Experts,
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>>For example, i have the file in directory A, i need to delete that file from that location and place it in B and then from B i have to move it to A again and then move it to C.
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>>A-> B -> A -> C
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Hi,
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public class CopyFiles {
public String copy ( File source, File target)
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FileChannel sourceChannel = null;
FileChannel targetChannel =null;
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sourceChannel =new FileInputStream(source).getChannel();
targetChannel= new FileOutputStream(target).getChannel();
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finally {
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kameshb wrote:
I Don't want to include the file name in destination file. i.e. File destinationFile=new File("C:\\apple"), and at the same time the pdf with same name has to get stored in the destination location, how can I achieve this.It's not totally clear what you're saying here, but what I think you mean is that you don't want to explicitly set the destination file name--you want to just give the copy the same name as the original. Yes?
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Hello,
I have successfully tested the Excel sample on WLS 7, and trying to run it on
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The custom function sets the MS-Excel default directory to System.getProperty("user.dir")+"/excel"
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that it would open that file.
- Mike
"Ashok Gupta" <[email protected]> wrote:
>
Hello,
I have successfully tested the Excel sample on WLS 7, and trying to run
it on
the WLS 8.1.
Anyways, the common question for both is, how to access an excel files
from different
locations (e.g. c:\path\1.xls, \\domain1\finance\fin.xls, \\domain1\marketing\customer.xls,
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I work on a Java process that must be optimized and I
have some questions.
This process includes a part of copying a file from a
location from another (to be more specific, all files
that exist in a directory, to copy in another
directory), wich technique is more efficient and
quickly? To copy using
FileInputStream/FileOutputStream in Java or using a
java Runtime process that calls a copy command of the
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Have you read the"XMLDB FAQ" in this Forum?
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I have a requirement that how can One sender communication channel pick two file from two location.Both the file has same name...How to configure the one receiver communication channel.i dont have any IR,no mapping..Please help me...

>
Soumitra Sinha wrote:
> Hello Vijay
> I already done the adapter specific message attribute.i am getting the file name properly.but that is nothing to do with my req.i am again clearing my problem:
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Ok now I get your requirement.
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See these two examples:
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Please mark the post as answered if it answers your question | My SSIS Blog:
http://microsoft-ssis.blogspot.com |
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Please help me .
note: its read only file.
Thank you.
Karthik.

hI,
try with this statement.
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Read file from directory, update contents of the each file

hai,
I could not understand how to debug the error i have now.
target
1- read the files from directory // i able ot do this part
2- for each file
for each file read the content & compare with the existing List & update the list // i able to do this part
when i try to combine both parts , i got some following error
run:
E:\java\check\100130.ixf
Error: children[i] (The system cannot find the file specified)
BUILD SUCCESSFUL (total time: 2 seconds)
i can see from the code that children[i] only gives the error when i use that in the second part of the code.
can any one help me on this??
Thanks
Priyan
the original code
import java.io.BufferedReader;
import java.io.DataInputStream;
import java.io.File;
import java.io.FileInputStream;
import java.io.InputStreamReader;
import java.io.RandomAccessFile;
import java.util.ArrayList;
public class CompareList
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         ArrayList a2 = new ArrayList();
         a1.add("1");
         a1.add("2");
         a1.add("3");
         a1.add("4");
         a1.add("5");
         a1.add("6");
         a1.add("7");
         a1.add("8");
         a1.add("9");
         a1.add("10");
         a1.add("11");
         a1.add("12");
         a1.add("13");
         a1.add("14");
         a1.add("15");
         a1.add("16");
         a1.add("17");
         a1.add("18");
         a1.add("19");
         a1.add("20");
         a1.add("21");
         a1.add("22");
         a1.add("23");
         a1.add("24");
         a1.add("25");
         a1.add("26");
         a1.add("27");
         a1.add("28");
         a1.add("29");
         a1.add("30");
         a1.add("31");
         a1.add("32");
         a1.add("33");
         a1.add("34");
         a1.add("35");
         a1.add("36");
         a1.add("37");
         a1.add("38");
         a1.add("39");
         a1.add("40");
         a1.add("41");
         a1.add("42");
         a1.add("43");
         a1.add("44");
         a1.add("45");
         a1.add("46");
         a1.add("47");
         a1.add("48");
         a1.add("49");
         a1.add("50");
         a1.add("51");
         a1.add("52");
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                   System.out.println( children);
FileInputStream fstream = new FileInputStream("children[i]");
DataInputStream in = new DataInputStream(fstream);
BufferedReader br = new BufferedReader(new InputStreamReader(in));
String strLine;
while ((strLine = br.readLine()) != null)      {
String line =strLine.substring(0,2);
// Print the content on the console
//System.out.println(line);
a2.add(line);
} // end of add list2
if (a1.size() > a2.size())
int k = 0;
for (int l = 0; l < a2.size(); l++)
if (!((String)a1.get(l)).equals((String)a2.get(l)))
//System.out.println((String)a2.get(i));
// System.out.println("dd");
k = l;
k++;
for (int l = k; l < a1.size(); l++)
System.out.println((String)a1.get(l));
String str = "children[l]";
File file = new File(str);
RandomAccessFile rand = new RandomAccessFile(file,"rw");
rand.seek(file.length()); //Seek to end of file
rand.writeBytes((String)a1.get(i)); //Write end of file
rand.writeBytes("., 0.");
rand.writeBytes("\n");
}// end of comparing and updating the list2
          in.close();
catch (Exception e){//Catch exception if any
System.err.println("Error: " + e.getMessage());

thanks for the information.
i tried, the error
like this
run:
E:\java\check\100130.ixf
java.lang.StringIndexOutOfBoundsException: String index out of range: 2
        at java.lang.String.substring(String.java:1935)
        at CompareList.main(CompareList.java:84)
BUILD SUCCESSFUL (total time: 0 seconds)this comes because in my code i used children[i] as string in the later part
    else {
           for (int i = 0; i < children.length; i++) {
                    System.out.println( children);
FileInputStream fstream = new FileInputStream(children[i]);
DataInputStream in = new DataInputStream(fstream);
BufferedReader br = new BufferedReader(new InputStreamReader(in));
String strLine;
while ((strLine = br.readLine()) != null)      {
String line =strLine.substring(0,2);
a2.add(line);
System.out.println(line);
} // end of add list2
if (a1.size() > a2.size())
int k = 0;
for (int l = 0; l < a2.size(); l++)
if (!((String)a1.get(l)).equals((String)a2.get(l)))
//System.out.println((String)a2.get(i));
// System.out.println("dd");
k = l;
k++;
for (int l = k; l < a1.size(); l++)
System.out.println((String)a1.get(l));
String str = "children[l]";
File file = new File(str);
RandomAccessFile rand = new RandomAccessFile(file,"rw");
rand.seek(file.length()); //Seek to end of file
rand.writeBytes((String)a1.get(i)); //Write end of file
rand.writeBytes("., 0.");
rand.writeBytes("\n");
rand.close();
}// end of comparing and updating the list2
          in.close();
i stil could not figure out it yet. do u have any clue with this.

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¯\_(ツ)_/¯

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