Select distinct value

HI all
DESC CLAIMS
CLAIM_NUMBER NUMBER(10)
VERSION          NUMBER(2)
STATUS          NUMBER(1) to every claim_number can be 3 statuses
0/9/1
there must be at least 1 status
Select CLAIM_NUMBER   ,STATUS from claims
order by CLAIM_NUMBER,STATUS
CLAIM_NUMBER   STATUS
6971700            1
6971700            1
6971700            0
8624300            9
10071200          1
10453800          0
10453800          0 I want to fetch only CLAIM_NUMBER that contain only one value status
like CLAIM_NUMBER = 10453800 (which contain only 0 )
10071200 (which contain only 1)
8624300 (which contain only 9)
i started a query like this
select CLAIM_NUMBER
from CLAIMS
group by CLAIM_NUMBER
having count(distinct(status)) < 2 the problem is that i want to add to the condition the status value like 9 or 0
how shall i do that ?
thanks in advanced
Naama

is this what you are looking for?
select p.*from
select CLAIM_NUMBER,STATUS,count(distinct(STATUS)) over(partition by CLAIM_NUMBER) cnt
from CLAIMS
)p
where p.cnt =1
and status=0

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Not sure what you mean either, but perhaps this will start a dialog:
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hi,
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Hi Manohar,
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http://social.msdn.microsoft.com/Forums/sqlserver/en-US/6495db18-a1c1-480b-8c92-89c74ee47cf5/how-to-get-distinct-values-of-sharepoint-column-using-ssrs?forum=sqlreportingservices
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I have three different methods, but there may be something I am missing.
First:
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Second:
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Hi,
There are more possible scenario's, for example:
select t1.*
from   the_table t1
where not exists ( select null
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What is the best way to do this?Only you can tell:
Test all scenario's, check the execution plans, set timing on and pick the best/fastest one ;-)
If it's not clear, please post the execution plans here.

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Please help me out with the below issue.
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Rajesh S

Hi,
I don't think it's not an issue with not selecting "Select Distinct Value" checkbox .. because same column pulled into to other subject areas working fine. But here also sometimes it shows correct distinct value and sometimes all values(Duplicate values).
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Select records based on first n distinct values of column

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eg:
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1 abc 10
1 def 20
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2 jkl 20
2 mno 60
3 pqr 10
4 rst 10
4 tuv 10
5 vwx 10
6 xyz 10
6 hij 10
7 lmn 10
so on... (till some count)
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Query 1 should result --->
ID name age
1 abc 10
1 def 20
2 ghi 10
2 jkl 20
2 mno 60
3 pqr 10
query 2 should result -->
4 rst 10
4 tuv 10
5 vwx 10
6 xyz 10
6 hij 10
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9 .. ..
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Hi,
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FROM     got_grp_id
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;If you'd care to post CREATE TABLE and INSERT statements for your sample data, then I could test it.
See the forum FAQ {message:id=9360002}

Query help in select Distinct on one column.

CREATE GLOBAL TEMPORARY TABLE Table1 (
ID1 varchar2(100) ,
Name1 varchar2(100),
Name11 varchar2(100)
insert into Table1 values ('a','n1','h3');
insert into Table1 values('b','n2','h2');
insert into Table1 values('a','n3','h1');
insert into Table1 values('c','n4','h5');
insert into Table1 values ('c','n5','h4');
insert into Table1 values('d','n6','h6');
select * from Table1;
ID1,NAME1,     NAME11
a,     n1,     h3
b,     n2,     h2
a,     n3,     h1
c,     n4,     h5
c,     n5,     h4
d,     n6,     h6
I am trying to select distinct ID1 and all values associated with it which is max row.I want to result as -
ID1,NAME1,     NAME11
a,     n3,     h1
b,     n2,     h2
c,     n5,     h4
d,     n6,     h6
Can you please help me to write simple query to get above result.
Edited by: 871447 on Jul 25, 2011 9:42 AM
Edited by: 871447 on Jul 25, 2011 9:45 AM

Hi,
Do a self-join, to combine the two rows for each value of id1 onto one output row.
Make it an outer join, in case there is only one row with a vlaue for id1.
SELECT l.id1
,     l.name1
,     NVL ( r.name11
         , l.name11
         )          AS name11
FROM              table1     l
LEFT OUTER JOIN     table1     r ON l.id1     = r.id1
                          AND l.name1     < r.name1
;Edited by: Frank Kulash on Jul 25, 2011 12:57 PM
Sorry, I mis-read the problem.
Lee's solution, above, assumes that name1 is unique, as it is in your sample data.
What output would you want if that's not the case?
If name1 is not unique, but the combination of (id1, name1) is unique, then you can modify Lee's solution like this:
SELECT *
FROM    table1
WHERE   (id1, name1) IN (
                    SELECT    id1
                    ,       MAX (name1)
                           FROM          table1
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;Or, if you can't make any assumptions about uniqueness, you might need something like this:
WITH     got_r_num     AS
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     ,     ROW_NUMBER () OVER ( PARTITION BY id1
                               ORDER BY         name1     DESC
                         ,                name11     DESC
                       )      AS r_num
     FROM     table1
SELECT id1, name1, name11
FROM     got_r_num
WHERE     r_num     = 1
;

"How to get distinct values of sharepoint column using SSRS"

Hi,
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<Query>
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<ElementPath IgnoreNamespaces="True">*</ElementPath>
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Thanks,
Sam.

Hi Sam,
By code, the CAML language doesn’t have any reserved word (or tag) to set this particular filter to remove duplicate results.
In this case, we could use the custom code to get distinct records.
Here are the detailed steps:
1.         Create a hidden parameter that gets all the records in one field.
Note: Please create another dataset that is same of the main dataset. This dataset is used for the parameter.
2.         Create a function that used to remove the duplicate records.
Here is the code:
Public Shared Function RemoveDups(ByVal items As String) As String
Dim noDups As New System.Collections.ArrayList()
Dim SpStr
SpStr = Split(items ,",")
For i As Integer=0 To Ubound(Spstr)
If Not noDups.Contains(SpStr(i).Trim()) Then
noDups.Add(SpStr(i).Trim())
End If
Next
Dim uniqueItems As String() = New String(noDups.Count-1){}
noDups.CopyTo(uniqueItems)
Return String.Join(",", uniqueItems)
End Function
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And the default value to be the value you what such as the first value:
=Split(Code.RemoveDups(JOIN(Parameters!ISSUE_STATUS_TEMP.Value, ",")), ",").(0)
4.         Go to the main dataset. Open the property window of this dataset.
5.         In the “Filters” tab, set the filter to be:
Expression: <The field to be filter>
Operator: =
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The parameter “Region” should be the parameter we created in the step3.
Now, we should get distinct values of SharePoint columns.
If there is anything unclear, please feel free to ask.
Thanks,
Jin
Jin Chen - MSFT

Get distinct values from plsql array

Hi,
I have declared a variable as below in plsql proc.
type t_itemid is table of varchar2(10);
inserted set of items in to this using a program
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I am using 9i so i cannot use set operator and more over my problem is that i am declaring the variable inside the plsql block . when i tried i am getting the below errors:
SQL> r
1 declare
2 type t_type is table of varchar2(10);
3 v_type t_type;
4 begin
5 v_type := t_type('toys','story','good','good','toys','story','dupe','dupe');
6 for i in (select column_value from table(v_type)) loop
7 dbms_output.put_line(i.column_value);
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ERROR at line 6:
ORA-06550: line 6, column 41:
PLS-00642: local collection types not allowed in SQL statements
ORA-06550: line 6, column 35:
PL/SQL: ORA-22905: cannot access rows from a non-nested table item
ORA-06550: line 6, column 10:
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Hi All,
Could you please let me know the appropriate CE function to get the distinct values from column table.
IT_WORK = SELECT DISTINCT AUFNR FROM :IT_WO_DETAILS;
Thank you.

Hi,
If you have 10g, you can use Model( with model performance is better than connect by )
Solution
========================================================================
WITH t AS
(SELECT '0989.726332, 1234.567432, 3453.736379, 3453.736379, 0989.726332, 3453.736379, 1234.567432, 1234.567432, 0989.726332'
txt
FROM DUAL)
SELECT DISTINCT TRIM(CHAINE)
FROM T
MODEL
RETURN UPDATED ROWS
DIMENSION BY (0 POSITION)
MEASURES (CAST( ' ' AS VARCHAR2(50)) AS CHAINE ,txt ,LENGTH(REGEXP_REPLACE(txt,'[^,]+',''))+1 NB_MOT)
RULES
(CHAINE[FOR POSITION FROM 1 TO NVL(NB_MOT[0],1) INCREMENT 1] =
CASE WHEN NB_MOT[0] IS NULL THEN TXT[0] ELSE REGEXP_SUBSTR(txt[0],'[^,]+',1,CV(POSITION)) END );
=========================================================================
Demo
=======================================================================
SQL> WITH t AS
2 (SELECT '0989.726332, 1234.567432, 3453.736379, 3453.736379, 0989.726332, 3453.736379, 123
4.567432, 1234.567432, 0989.726332'
3 txt
4 FROM DUAL)
5 SELECT DISTINCT TRIM(CHAINE)
6 FROM T
7 MODEL
8 RETURN UPDATED ROWS
9 DIMENSION BY (0 POSITION)
10 MEASURES (CAST( ' ' AS VARCHAR2(50)) AS CHAINE ,txt ,LENGTH(REGEXP_REPLACE(txt,'[^,]+',''))+1 NB_MOT)
11 RULES
12 (CHAINE[FOR POSITION FROM 1 TO NVL(NB_MOT[0],1) INCREMENT 1] =
13 CASE WHEN NB_MOT[0] IS NULL THEN TXT[0] ELSE REGEXP_SUBSTR(txt[0],'[^,]+',1,CV(POSITION)) END );
TRIM(CHAINE)
3453.736379
1234.567432
0989.726332
SQL>
========================================================================

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Thanks,
Malli

Malli,
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To be more clear in the first step of solution 1

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