Select function that returns multiple columns.

Currently I have a function that will return 1 column and I can use that in a select statement. What I need is to return multiple columns from a table. In the function I have I return the street address from a table that holds information about dealers, I need to be able to also return the columns that contain the city, state, and zip code so it can be used in an sql select statement. How would I do this?
My function:
FUNCTION GET_ADDRESS(dealer_id IN number)
RETURN tbl_dealer_info.c_street%TYPE AS
v_rc tbl_dealer_info.c_street%TYPE;
CURSOR get_dealer_cur IS
SELECT c_street
FROM tbl_dealer_info
WHERE n_dealer_id = dealer_id;
BEGIN
v_rc := NULL;
OPEN get_dealer_cur;
FETCH get_dealer_cur INTO v_rc;
IF get_dealer_cur%NOTFOUND THEN
NULL;
END IF;
CLOSE get_dealer_cur;
RETURN v_rc;
EXCEPTION
WHEN OTHERS THEN
RETURN NULL;
END GET_ADDRESS;
My select statement:
select GET_ADDRESS(1205) Street, DI.n_inactive_flag, DI.n_onhold_flag
from tbl_dealer_info DI
where DI.n_dealer_id = 1205;
I would like to be able to select the street, city, state, and zip all in this select statement from the GET_ADDRESS function.
Thanks,
Lori Neirynck

"The reality is you've probably already put your blinders on and you won't learn the best approach to solving your problem because you insist on asking a courtroom style question (just "yes" or "no" please)."
Actually, I asked this question because I was looking for the best approach to my problem. I have an SQL statement that correctly selects everything it needs to from all 15 tables. The thing of it is it is very long and difficult to read. I wanted to try using functions so that I could change 12 AND/OR statements into 3 IF statements so everything is easier to read. I have received a couple of different ways to do this from other forums that assumed I knew what I was doing. I have gotten one to work, the other I'm still working on. I'll post the one that worked for others that want to know.
SQL> insert into dealer_info values (1,'Me','13 success street', 'Wonder Town','Wonderland','1313');
SQL> commit;
SQL> create type t_address as object (
2 street varchar2(100),
3 city varchar2(30),
4 state varchar2(30),
5 zip varchar2(10));
6 /
Type created.
SQL> create or replace function get_address (p_id number) return t_address
2 is
3 ret t_address := t_address(null,null,null,null);
4 rec dealer_info%rowtype;
5 begin
6 select * into rec from dealer_info where id=p_id;
7 ret.street := rec.street;
8 ret.city := rec.city;
9 ret.state := rec.state;
10 ret.zip := rec.zip;
11 return ret;
12 end;
13 /
Function created.
SQL> col name format a10
SQL> col address format a70
SQL> select name, get_address(id) address from dealer_info;
NAME ADDRESS(STREET, CITY, STATE, ZIP)
Me T_ADDRESS('13 success street', 'Wonder Town', 'Wonderland', '1313')
1 row selected.
-Lori

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        TYPE EMP_EMAIL_UK_aat IS TABLE OF HR.EMPLOYEES.EMPLOYEE_ID%TYPE INDEX BY HR.EMPLOYEES.EMAIL%TYPE;
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                    EMP_EMAIL_UK_aa(rec.EMAIL) := rec.EMPLOYEE_ID;
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    PLS-00382: expression is of wrong type
    ORA-06550: line 1, column 7:
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    HR@XE>Have a feeling this should be really easy. Can anybody help?
    Many thanks in advance.
    Jason
    Edited by: 942375 on 08-Feb-2013 11:45

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